portant. I replaced it with '@a' and then I was not getting
results like original code which
added confusion). Actually I never gave a thought to slice of a hash.
Thanks again,
Tushar
Sudarsan Raghavan wrote:
> Tushar Kulkarni wrote:
>
> > Hi,
> > I have this cod
Thanks Kevin,
But I am really confused about 'foreach (@a{keys %h})'. What '%h' is doing
here?
Also I was under impression that '$_' is a copy of $a[0] ..$a[n] (or
actually whatever we are using, - depends on context) , but here if I modify $_
it modifies actual variable. So is it alias?
Hi,
I have this code, but I am not getting how this works. Can someone
help?
%h = ( one => 15,
two => 26,
three => 37 );
my @a;
foreach (@a {keys %h})
{
$_ = $_ + 10;
}
print "New\n";
foreach (@a{keys %h})
{
print "$_\n";
}
This prints
New
10
10
10
Can s
