hi again, thanks to you, i got it with my date. so 1st point is out. i
still have a short problem, as i should get my date back in the format
ddmmyy and i get it in d m y (with %2d, but how to handle in vars)
#!/usr/bin/perl
$t1=time();
$t2=$t1 - 604800;
$diff=$t1 - $t2;
print "Zeit 1; $t1\tZe
hi list,
i'd like to try a first perl-script that should:
-define todays date
-define todays date minus one week
-find in a special directory files, that contain ddmmyy
-remove them
..since i am an absolute beginner in programming...i think, if i can read
out this directory, i can find the files
