I have to remove punctuation so that I can look in a dictionary to list all possible
completions of the english word: "te*t".
ie. teat teet tent test text
If I leave the punctuation in, there will be no dictionary matches on "te*t,".
Is that clearer now?
Lonya
---
The
the punctuation easily enough, but I don't know how to join it back in
later.
Is there another function besides split and join that I should be using?
Any ideas?
Thanks for any help!
Lonya
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een pushed onto it. Get rid of the
"@possWords = " part of this line.
-- tdk
Original Message
Subject: Re: scalar vs. vector context
Date: Mon, 7 May 2001 15:05:46 -0400 (EDT)
From: "Brett W. McCoy" <[EMAIL PROTECTED]>
To: Lonya Julin <[EMAIL PROTEC
" ;
if ($dwords{lc($temp)}){
@possWords = push(@possWords,$temp) ;
print "\nThis is \@possWords after pushing \$temp: @possWords\n";
$c++ ;
#print "This is \$c after increment: $c \n" ;
}
$temp = $word;
#print "This is \$temp being \$word again: $tem
