--";
print "\nHave a nice day !!!\n";
[root@ ~]# perl t.pl
str = [/a/b/./c/../d]
str1 = [/a/b/./c/../d]
---
str = [/a/b/./c/../d]
str1 = [/a/b/./d]
---
str = [/a/b/./c/../d]
str1 = [/a/b
Hi Peter
Actually, I don't want to translate the path into realpath because some of
the paths even do not exist on the host. What I need is just a simplified
format.
Anyway, thank you for the advice.
On Wed, 02 Jul 2008 21:33:59 +0800, Chen Yue wrote:
> I have a file containing UNI
Hi Rob
Thank you for the suggestion. Actually, abs_path requires the original path
exists on the host. But my case does not fulfill this. This is what puzzled
me.
Sent: Wednesday, July 02, 2008 9:58 PM
To: beginners@perl.org
Cc: Chen Yue
Subject: Re: simplify a path
Chen Yue wrote:
>
Hi
I have a file containing UNIX-styled Path in each line. But the path is
simplified enough. Some of them has ".." and "." in the middle, such as
"/a/b/./c/../d".
Now I want to simplify each Path according to Unix tradition.
/a/b/./c/../d->/a/b/d
The only way I could think out is to sp
Hi
I fully understand this. So I wonder is there a way to get the path that the
blabla.lnk points to?
--
Windows does not support the "links" that Unix has.
Windows links have a .lnk extension that you can check for.
--
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional comman
Hi
On Linux, I can use "-l" to judge whether a file is a soft link and use
readlink/Cwd::realpath to get its real path. But on windows (activeperl),
seems both function do not work. Is there a way to do this for me?
--
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands
If you are in a *nix system, you can try to run
$result=` mk_view $view_name ETC`
instead and see the output from $result. It may be helpful to find the root
cause.
-邮件原件-
发件人: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
发送时间: 2008年1月17日 22:16
收件人: beginners@perl.org
主题: Help in sys
