h the value is
returned? How does perl know whether (0) = a scalar expression with
parentheses for precedence grouping (vacuously in this case); or a single
element list; or, if a function precedes it, () indicating function arguments?
Ross
P.S. Sorry, my mail client basically forces top-posti
I think I figured out one thing from my earlier message:
print '$template{uname}{ross} =' , $template{uname}{ross}, "\n";
#$template{uname}{ross} =ARRAY(0x20f41d8)
# I'm still surprised this worked. Somehow we've gone 2 levels down with one $.
print '${$template{uname
perl -c adduser gives its first error as
"my" variable $new_uid masks earlier declaration in same scope at adduser line
283.
First, it doesn't seem to me I'm declaring the variable at all at 283. I
suppose it could be an implicit declaration if there wasn't a previous
declaration, but there is
