On 11/13/2018 8:07 AM, Tetsuo Handa wrote:
> Hello.
>
> I want to represent up to a few hundreds gigabytes for file size.
>
> On 32bits platform, I noticed that
>
>my $value = ...;
>printf("%u\n", $value);
>
> prints 4294967295 if $value >= 4294967295 whereas
>
>my $value = ...;
>pr
Hi Andy ,
thanks for the reply . Yes the purpose is to compare the
timestamps ans yes these are the only two formats .
Thanks,
On Wed, Nov 14, 2018 at 2:48 AM Andy Bach wrote:
> Calling upgrade.sql on 05-JUL-18 10.19.42.559000 PM -12
> Calling apply.sql on 17.10.18 12:28:12,447849
Calling upgrade.sql on 05-JUL-18 10.19.42.559000 PM -12
Calling apply.sql on 17.10.18 12:28:12,447849 +02:
> I created on regex : \d\d\.\d\d\.\d\d\s[012][0-9]:[0-5][0-9]>:[0-5][0-9]
> this only matches : Calling apply.sql on 17.10.18 12:28:12,447849 +02:
Right as your first string has word chars
I don't have an answer for you, but I find this
interesting. I note the same issue in 64bit
up near
18446744073709551615
I'm guessing the guy who wrote
Math::BigInt
may have the answer.
Mike
On 11/13/2018 8:07 AM, Tetsuo Handa wrote:
Hello.
I want to represent up to a few hundreds gigaby
Hello.
I want to represent up to a few hundreds gigabytes for file size.
On 32bits platform, I noticed that
my $value = ...;
printf("%u\n", $value);
prints 4294967295 if $value >= 4294967295 whereas
my $value = ...;
printf("%s\n", $value);
and
use Math::BigInt;
my $value = ...;
On Mon, 12 Nov 2018 18:18:12 +0530
Asad wrote:
> Hi all ,
>
>I have two stings from logfile how can we have a common regex so
> that its parse datetime details for further parsing ;
>
> Calling upgrade.sql on 05-JUL-18 10.19.42.559000 PM -12
> Calling apply.sql on 17.10.18 12:28:12,
