$#array is the index of the last element of @array, so it will be one less
than scalar @array which is the number of elements in @array (since Perl
arrays start with index 0). Therefore, to get the number of elements, you
would need to add one to $#array, which makes scalar @array faster. To get
th
Hi,
For the following two expressions, are they of the same speed or one
of them is faster?
`$#array` vs `scalar @array`
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Regards,
Peng
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