Shawn H Corey writes:
> On Fri, 25 Apr 2014 12:39:21 -0700
> John SJ Anderson wrote:
>
>> Perl doesn't charge you by the lines of code you use, so doing this:
>>
>>my $re = shift;
>>$re = qr/$re/;
>>
>> is just fine.
>
> This also works:
>
> my $re = qr/$ARGV[0]/;
> shift @ARGV
Uri Guttman writes:
> On 04/25/2014 12:55 PM, Harry Putnam wrote:
>> Uri Guttman writes:
>>
>>> why would you expect anything but 1 as the value? shift will return 1
>>> value or undef. that anon array will be dereferenced to an array with
>>> 1 entry. the array is in scalar context which return