On Sat, Jan 25, 2014 at 06:41:00PM +0100, Luca Ferrari wrote:
> On Sat, Jan 25, 2014 at 4:12 PM, Paul Johnson wrote:
>
> > $ perl -E '$h = { a => qr/y/ }; say $_ =~ $h->{a} for qw(x y z)'
>
> Thanks, but then another doubt: having a look at
> http://perldoc.perl.org/perlop.html#Regexp-Quote-Like
On Sat, Jan 25, 2014 at 4:12 PM, Paul Johnson wrote:
> $ perl -E '$h = { a => qr/y/ }; say $_ =~ $h->{a} for qw(x y z)'
Thanks, but then another doubt: having a look at
http://perldoc.perl.org/perlop.html#Regexp-Quote-Like-Operators I dont
understand how I can use the regexp for substitution, th
On Sat, Jan 25, 2014 at 03:51:53PM +0100, Luca Ferrari wrote:
> Hi,
> I'm just wondering if it is possible to place a regexp as a value into
> an hash so to use it later as something like:
>
> my $string =~ $hash_ref->{ $key };
>
> Is it possible? Should I take into account something special?
Ye
Hi,
I'm just wondering if it is possible to place a regexp as a value into
an hash so to use it later as something like:
my $string =~ $hash_ref->{ $key };
Is it possible? Should I take into account something special?
Thanks,
Luca
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