You might take a look at AnyEvent Intro:
http://search.cpan.org/~mlehmann/AnyEvent-7.02/lib/AnyEvent/Intro.pod
在 2012-8-30，下午9:46， Chris Stinemetz 写道：
> Hello List,
>
> I am creating a program, where for the first time, I will be reading
> in data from a socket port.
>
> I am a bit confused a
On Thu, 30 Aug 2012 15:03:43 -0400
Paul Anderson wrote:
> Works great until you start using a coordinate system that places
> points on a sphere:)
Just pretend it's a really, really big hill. ;)
--
Just my 0.0002 million dollars worth,
Shawn
Programming is as much about organization an
Works great until you start using a coordinate system that places points on a
sphere:)
Paul Anderson -- VE3HOP
On 2012-08-30, at 2:31 PM, Uri Guttman wrote:
> On 08/30/2012 12:20 PM, Paul Anderson wrote:
>> It looks like 2*10^-13 miles is about twice the inter atomic distance in
>> d
On 08/30/2012 12:20 PM, Paul Anderson wrote:
It looks like 2*10^-13 miles is about twice the inter atomic distance in
diamond:)
i don't know why you need to calculate great circle distances. it is
obvious to any observer that the earth is flat so simple geometric
distances should be fine.
It looks like 2*10^-13 miles is about twice the inter atomic distance in
diamond:)
Paul Anderson -- VE3HOP
On 2012-08-30, at 4:22 AM, Chris Stinemetz wrote:
>>
>>
>> Because floating-point arithmetic as done by limited precision computers is
>> always an approximation. An IEEE 754
Hello List,
I am creating a program, where for the first time, I will be reading
in data from a socket port.
I am a bit confused about how to print the processed data while still
reading in data from the port. Thus far, I have only processed data
from a file where the while loop ends when EOF cr
>
>
> Because floating-point arithmetic as done by limited precision computers is
> always an approximation. An IEEE 754 double-precision 64-bit floating point
> number uses a 53-bit fraction and therefore has about 16 decimal digits of
> precision. So calculating zero within 13 digits (e-013) i
