Re: printing anonymous array

2012-07-08 Thread John W. Krahn
timothy adigun wrote: [snip] my %new_hash = (); foreach my $data1 ( keys %$hash1 ) { while ( my ( $key, $value ) = each %$hash2 ) { my ($new_value) = keys %$value; $new_hash{$key} = $new_value if $data1 == $key; } } No need for the nested llops: my %new_hash; for

Re: printing anonymous array

2012-07-08 Thread Chris Stinemetz
Thank you very much. That was the solution I was looking for. Take care, Chris

Re: printing anonymous array

2012-07-08 Thread timothy adigun
Hi Chris, Please, check comments and codes below. On Sun, Jul 8, 2012 at 6:19 AM, Chris Stinemetz wrote: > Thank you very much for your responses. > > I have another question. > > I would like to replace the second element from hash1 with the second key > from %hash2 > > I believe what you