On 14/08/2011 23:19, Rajeev Prasad wrote:
in this simple example. i am not able to figure what is the bitwise
funtion doing:
my @subArray = grep { $_& 1 } @array;
The & operator requires the types of its operands to be identical -
either string or numeric. In either case the values are ANDed
in this simple example. i am not able to figure what is the bitwise funtion
doing:
my @subArray = grep { $_ & 1 } @array;
what is the significance of 1 here?
is this equivalent? { 1 & $_ }
does the EXPR inside grep's curly braces have to produce the grepped text or
just a true false value? i
On Thu, 11 Aug 2011 23:30:32 -0700, John W. Krahn wrote:
> Peter Scott wrote:
>> On Thu, 11 Aug 2011 16:17:51 -0700, siegfried wrote:
>>> Is there a way to do it with less typing? How can I do it without
>>> creating a temporary variable "@p"? Thanks, siegfried
>>>
>>> find /xyz -exec perl -e 'fore
Hi th0ma5_anders0n,
if you must use unpack try these:
>>on Win32:
perl -e "printf('%04g',unpack("B8",pack('c',6)))" # Ans: 0110
>>on Ubuntu
perl -e 'printf("%04g\n",unpack("B8",pack("c",6)))' # Ans: 0110
regards.
Timothy
th0ma5_ander...@yahoo.com wrote:
Hi all,
Hello,
When converting a single number (eg 6) to its binary format using
unpack as in:
unpack 'B8', '6'; # output = 00110110
You are not converting the number 6, you are converting the string '6'.
I get the 8 character output 00110110.
Does unpac
Hi all,
When converting a single number (eg 6) to its binary format using
unpack as in:
unpack 'B8', '6'; # output = 00110110
I get the 8 character output 00110110.
Does unpack have options for it to only return the last 4 characters
of this output (ie 0110)?
Or is the only option to use substr?
