Re: pattern substitution

2006-11-18 Thread Rob Dixon
Adriano Allora wrote: hi to all, Hi Adriano. Read my comments in-line and my solution at the end. I've got a list of tagged words, like this one (only a little bit longest): e CON e le DET:def il ha VER:presavere|riavere detto VER:pperdire < NOM

Re: pattern substitution

2006-11-18 Thread John W. Krahn
Adriano Allora wrote: > hi to all, Hello, > I've got a list of tagged words, like this one (only a little bit longest): > > > e CON e > le DET:def il > ha VER:presavere|riavere > detto VER:pperdire > < NOM > CORRVER:inficorre >>

Re: pattern substitution

2006-11-18 Thread D. Bolliger
Adriano Allora am Samstag, 18. November 2006 11:52: > hi to all, Ciao Adriano > I've got a list of tagged words, like this one (only a little bit > longest): > > > e CON e > le DET:def il > ha VER:presavere|riavere > detto VER:pperdire > < NOM > C

Re: Perl - Joining of Binary values

2006-11-18 Thread Dr.Ruud
Rob Dixon schreef: > my $binary = unpack 'b*', join '', map chr hex, @hex; > > But this is a beginners' group :) No problem if you explain some of the details: (*1*) my @temp1 = map chr hex, @hex; This achieves about the same: my @temp1; foreach my $elm (@hex) { push @temp1, chr(

pattern substitution

2006-11-18 Thread Adriano Allora
hi to all, I've got a list of tagged words, like this one (only a little bit longest): e CON e le DET:def il ha VER:presavere|riavere detto VER:pperdire < NOM CORRVER:inficorre > NOM e CON e a PRE a I