On Jul 10, 2008, at 12:54 AM, Gopal Ghosh wrote:
*
>>> 7/3
2
>>> 7/-3
-3
>>> 3/7
0
>>> # again reapting the questions with one more decimal place
>>> 7.0/3
2.3335
>>> 7.0/-3
-2.3335
>>> 3.0/7
0.42857142857142855
>>> # why it is not showing the exact
Dear sir / madam
I am a new user of python and this is my first mail to local user group of
python. I came across a strange behavior pf python n unable to explain it
*
>>> 7/3
2
>>> 7/-3
-3
>>> 3/7
0
>>> # again reapting the questions with one more decimal place
>>> 7.0/3
2.33
Anand Chitipothu wrote:
On Wed, Jul 9, 2008 at 8:47 PM, Kushal Das <[EMAIL PROTECTED]> wrote:
Hi all,
a = [12, 12, 1321, 34, 23, 12, 34, 45, 77]
for x in a:
... if x == 12:
... a.remove(x)
a
[1321, 34, 23, 12, 34, 45, 77]
Can any one explain me how the remove works and how it is effe
I noticed it. But surely only in quantity, not in quality :)
On Wed, Jul 9, 2008 at 8:30 PM, O.R.Senthil Kumaran <[EMAIL PROTECTED]> wrote:
> * scriptor Anand Balachandran Pillai, explico
>> ASPN cookbook site was up for a new look and feel for quite some time.
>> The old site is still in Web 1.0
On Wednesday 09 July 2008 09:26:09 pm Anand Chitipothu wrote:
> It never iterated over the second the 12. When x=12 for the last time,
> there was still a 12 at the begining of the list. (try printing the
> list also for every iteration).
>
> It internally maintains an index for iteration. If you h
Hi kushal,
On Wed, Jul 9, 2008 at 8:47 PM, Kushal Das <[EMAIL PROTECTED]> wrote:
>
a = [12, 12, 1321, 34, 23, 12, 34, 45, 77]
for x in a:
> ... if x == 12:
> ... a.remove(x)
a
> [1321, 34, 23, 12, 34, 45, 77]
This is not possible in python because when you remove the a[1] th
On Wed, Jul 9, 2008 at 8:47 PM, Kushal Das <[EMAIL PROTECTED]> wrote:
> Hi all,
>
a = [12, 12, 1321, 34, 23, 12, 34, 45, 77]
for x in a:
> ... if x == 12:
> ... a.remove(x)
a
> [1321, 34, 23, 12, 34, 45, 77]
>
> Can any one explain me how the remove works and how it is effectin
On Wed, Jul 9, 2008 at 8:47 PM, Kushal Das <[EMAIL PROTECTED]> wrote:
> Hi all,
>
> >>> a = [12, 12, 1321, 34, 23, 12, 34, 45, 77]
> >>> for x in a:
> ... if x == 12:
> ... a.remove(x)
> >>> a
> [1321, 34, 23, 12, 34, 45, 77]
>
> Can any one explain me how the remove works and how it is effe
On Wed, Jul 9, 2008 at 8:47 PM, Kushal Das <[EMAIL PROTECTED]> wrote:
> Hi all,
>
a = [12, 12, 1321, 34, 23, 12, 34, 45, 77]
for x in a:
> ... if x == 12:
> ... a.remove(x)
a
> [1321, 34, 23, 12, 34, 45, 77]
>
> Can any one explain me how the remove works and how it is effectin
Hi all,
>>> a = [12, 12, 1321, 34, 23, 12, 34, 45, 77]
>>> for x in a:
... if x == 12:
... a.remove(x)
>>> a
[1321, 34, 23, 12, 34, 45, 77]
Can any one explain me how the remove works and how it is effecting the for
loop.
Kushal
--
Fedora Ambassador, India
http://kushaldas.in
http://dgpl
* scriptor Anand Balachandran Pillai, explico
> ASPN cookbook site was up for a new look and feel for quite some time.
> The old site is still in Web 1.0 without support for tags and the search
> is not very good.
I had mostly followed new recipes using the Google Reader, so hadn't got a
chance
Hi All ,
We want to access the functions from a c++ dll. This dll is not a COM dll.
With this dll function (ISO14229_DiagnosticSessionControl_10) we are able to
communicate to the dll but the return for the 4th argument array is always
getting as 0.
Any solution for this...?
iRecLen =
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