On Mon, Jun 13, 2011 at 2:07 PM, Shashidhar wrote:
>
>
> On Mon, Jun 13, 2011 at 6:32 PM, Kumar Bibek wrote:
>>
>> AFAIK, you cant do it.
>>
>
> I have tried the below code.
> WebView webview = new WebView(this);
> setContentView(webview);
> byte[] post = EncodingUtils.get
HTTP POST requests are not normally encoded in Base64. They are
normally encoded as application/x-www-form-urlencoded.
On Mon, Jun 13, 2011 at 9:07 AM, Shashidhar wrote:
>
>
> On Mon, Jun 13, 2011 at 6:32 PM, Kumar Bibek wrote:
>>
>> AFAIK, you cant do it.
>>
>
> I have tried the below code.
>
On Mon, Jun 13, 2011 at 6:32 PM, Kumar Bibek wrote:
> AFAIK, you cant do it.
>
>
I have tried the below code.
WebView webview = new WebView(this);
setContentView(webview);
byte[] post = EncodingUtils.getBytes("un=us...@gmail.com",
"BASE64");
webview.postUrl("http:
AFAIK, you cant do it.
*Thanks and Regards,
Kumar Bibek*
*
http://techdroid.kbeanie.com
http://www.kbeanie.com*
On Mon, Jun 13, 2011 at 5:11 PM, Shashidhar wrote:
> Hi,
> I need to open a browser with a URL when I click on a button in my
> activity.
> The URL has some parameters which I need
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