Cool, gotcha, thanks.
On Aug 27, 5:12 pm, "Megha Joshi" <[EMAIL PROTECTED]> wrote:
> You don't need to manually type the uris.. as I said before you can use
> ContentUris.withAppendedId(People.CONTENT_URI, )
>
> More in the docs/examples
> here:http://code.google.com/android/devel/data/contentpr
You don't need to manually type the uris.. as I said before you can use
ContentUris.withAppendedId(People.CONTENT_URI, )
More in the docs/examples here:
http://code.google.com/android/devel/data/contentproviders.html
Most of the times you could get the base URIs and use withApendedPath() or
withA
Got it, thanks. I just did Uri.parse() on that a string containing
"content://...".
It would certainly be nice if we didn't have to manually type that
entire URI address in... some way we could access the ENTIRE Uri for
People, Phones, etc. Even referencing People.CONTENT_URI.getPath()
fails to
Yes it would crash, because then the Uri value you get does not include the
base contacts uri...which is content://contacts.
The uri value should be something like:
content://contacts/people/
As long as the Uri value is in this format and the person_id is present in
the content provider it should
If you try that code in your demo (and print out the Uri for
debugging), it will crash with a null pointer exception.
I also tried using Uri.Builder to rebuild the contact Uri, and that
didn't work either.
On Aug 27, 4:31 pm, kingkung <[EMAIL PROTECTED]> wrote:
> /people/189 is the uri i get.
>
/people/189 is the uri i get.
On Aug 27, 4:24 pm, "Megha Joshi" <[EMAIL PROTECTED]> wrote:
> You definitely don't need to store the URI, what are the first and second
> URI values that you get?
>
> 2008/8/27 kingkung <[EMAIL PROTECTED]>
>
>
>
> > I added one simple line to the demo and it crashed
You definitely don't need to store the URI, what are the first and second
URI values that you get?
2008/8/27 kingkung <[EMAIL PROTECTED]>
>
> I added one simple line to the demo and it crashed with a null pointer
> exception. Apparently I can't recreate a second Uri from an original
> Uri.
>
>
I added one simple line to the demo and it crashed with a null pointer
exception. Apparently I can't recreate a second Uri from an original
Uri.
private void readContact(Uri uri) {
ImageView i = (ImageView) findViewById(R.id.image);
Uri uri2 = Uri.parse(uri.getEncodedPath());
Bitma
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