Re: [Alsa-user] Re: Keeping multiple cards in sync

2005-12-31 Thread Morten Nilsen
Jon B wrote: You're just running both devices off the same crystal. That's certainly one way to do it, but wouldn't work with devices that use different circuits or crystals, and I don't think it can be extended to more than 2 or 3 cards. sure it can.. just build a small timer circuit on a pro

[Alsa-user] Re: Keeping multiple cards in sync

2005-12-31 Thread Jon B
> Hi. The only solution I saw to this problem was in a HOW-TO that a guy posted. > Sadly I can't find it, but it was a soldering iron job on the soundcards. Right here: http://www.djcj.org/LAU/quicktoots/toots/el-cheapo/ You're just running both devices off the same crystal. That's certainly on

Re: [Alsa-user] Re: Keeping multiple cards in sync

2005-12-31 Thread Bill Unruh
Hi. The only solution I saw to this problem was in a HOW-TO that a guy posted. Sadly I can't find it, but it was a soldering iron job on the soundcards. For 3 cards, disable the crystals on 2 cards, and link the crystal from the first card to the 2 cards with the disabled crystals. this logically

Re: [Alsa-user] Re: Keeping multiple cards in sync

2005-12-31 Thread Nigel Henry
On Saturday 31 December 2005 17:54, Jon B wrote: > > I would've thought though that if you had a software buffer of X > > milliseconds, then you should be sending that buffer to the card every X > > milliseconds (according to some other timer in the system.) If it takes > > longer before the card

[Alsa-user] Re: Keeping multiple cards in sync

2005-12-31 Thread Jon B
> I would've thought though that if you had a software buffer of X > milliseconds, then you should be sending that buffer to the card every X > milliseconds (according to some other timer in the system.) If it takes > longer before the card is ready for the next buffer then you need to > drop some

[Alsa-user] Re: Keeping multiple cards in sync

2005-12-30 Thread Jon B
> For starters, one may start measuring average frequency of interrupt > requests generated by both cards provided both of the play the same > length buffer. > > The measure of the average frequency will be the computers RTC. > > I am not saying that it is simple, and yes, prior knowledge, like NTP