Formula construction help

2023-11-02 Thread Donald Town
Hi everyone

I'm working on a database that has a group of basic formulas to get needed 
values.

I'd like to configure a "Yes / No' location (set of adjacent cells) to identify 
if a value is greater than / less than a boundary.
If > 14 then report "No".
If < or = 10 then report "Yes".

My only issue is not knowing how to construct the formula correctly.
Any help appreciated.

Thanks
Don

Using a couple different versions of OO on 3 different older Macs.


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Re: Formula construction help

2023-11-02 Thread David Robley

On 2023-11-02 18:25, Donald Town wrote:

Hi everyone

I'm working on a database that has a group of basic formulas to get needed 
values.

I'd like to configure a "Yes / No' location (set of adjacent cells) to identify 
if a value is greater than / less than a boundary.
If > 14 then report "No".
If < or = 10 then report "Yes".

My only issue is not knowing how to construct the formula correctly.
Any help appreciated.

Thanks
Don

Using a couple different versions of OO on 3 different older Macs.


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You haven't said which component of AOO you are working with. You 
mention database but then mention adjacent cells, which would suggest Calc.


Assuming the latter, a formula like the following should achieve what 
you seem to want. You haven't mentions what to display if value is 
between 10 and 14 so I've used UNDEFINED; replace with whatever you 
want. Assuming your "value" is in A1, place in B1


=IF( A1 > 14; "NO"; IF( A1 <= 10; "YES" ; "UNDEFINED"))


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Re: Formula construction help

2023-11-02 Thread Robin Lord
The IIF function will do what you want easily

On Thu, 2 Nov 2023, at 09:57, David Robley wrote:
> On 2023-11-02 18:25, Donald Town wrote:
>> Hi everyone
>>
>> I'm working on a database that has a group of basic formulas to get needed 
>> values.
>>
>> I'd like to configure a "Yes / No' location (set of adjacent cells) to 
>> identify if a value is greater than / less than a boundary.
>> If > 14 then report "No".
>> If < or = 10 then report "Yes".
>>
>> My only issue is not knowing how to construct the formula correctly.
>> Any help appreciated.
>>
>> Thanks
>> Don
>>
>> Using a couple different versions of OO on 3 different older Macs.
>>
>>
>> -
>> To unsubscribe, e-mail: users-unsubscr...@openoffice.apache.org
>> For additional commands, e-mail: users-h...@openoffice.apache.org
>>
> You haven't said which component of AOO you are working with. You 
> mention database but then mention adjacent cells, which would suggest Calc.
>
> Assuming the latter, a formula like the following should achieve what 
> you seem to want. You haven't mentions what to display if value is 
> between 10 and 14 so I've used UNDEFINED; replace with whatever you 
> want. Assuming your "value" is in A1, place in B1
>
> =IF( A1 > 14; "NO"; IF( A1 <= 10; "YES" ; "UNDEFINED"))
>
>
> -
> To unsubscribe, e-mail: users-unsubscr...@openoffice.apache.org
> For additional commands, e-mail: users-h...@openoffice.apache.org

-- 
Best Regards

Robin

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Re: Formula construction help

2023-11-02 Thread David Robley

Unfortunately IIF isn't implemented in AOO Calc.

On 2023-11-02 22:06, Robin Lord wrote:

The IIF function will do what you want easily

On Thu, 2 Nov 2023, at 09:57, David Robley wrote:

On 2023-11-02 18:25, Donald Town wrote:

Hi everyone

I'm working on a database that has a group of basic formulas to get needed 
values.

I'd like to configure a "Yes / No' location (set of adjacent cells) to identify 
if a value is greater than / less than a boundary.
If > 14 then report "No".
If < or = 10 then report "Yes".

My only issue is not knowing how to construct the formula correctly.
Any help appreciated.

Thanks
Don

Using a couple different versions of OO on 3 different older Macs.


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You haven't said which component of AOO you are working with. You
mention database but then mention adjacent cells, which would suggest Calc.

Assuming the latter, a formula like the following should achieve what
you seem to want. You haven't mentions what to display if value is
between 10 and 14 so I've used UNDEFINED; replace with whatever you
want. Assuming your "value" is in A1, place in B1

=IF( A1 > 14; "NO"; IF( A1 <= 10; "YES" ; "UNDEFINED"))


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