First python program, syntax error in while loop

[ryankoch38]

title = "Guess my number game:"
print title.title()
raw_input("Press any key to continue..")

import random

tries = 0
number = random.randrange(99) + 1
guess = int(raw_input("Guess my number! Secret - It is between 1 and 100 :")

while (guess != number):
if (guess > number):
number = int(raw_input("Sorry, my number is lower than that! \n Try again:")
   tries += 1
else if (guess < number):
number = int(raw_input("Sorry, my number is higher than that! \n Try 
again:")
tries += 1
print "Congratulations, you guessed my number! \n And it only took you" tries 
"tries!"

raw_input("\n\n Press any key to exit..")

## what is wrong with this script? I'm just trying to understand while loops 
and ## this is not a real project :P
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Re: First python program, syntax error in while loop

[ryankoch38]

Okay, thank you very much for the timely replies, heres what i have now:

title = "Guess my number game:"
print title.title()
raw_input("Press any key to continue..")

import random

number = random.randrange(99) + 1
tries = 0
guess = int(raw_input("Guess my number! Secret - It is between 1 and 100 :"))

while (guess != number):
if (guess > number):
number = int(raw_input("Sorry, my number is lower than that! \n Try 
again:"))
tries += 1
else:
number = int(raw_input("Sorry, my number is higher than that! \n Try 
again:"))
tries += 1

print "good job, you won!"



raw_input("\n\n Press any key to exit..")


## it seems to stick with "higher" or "lower" after my first guess, whichever 
it 
## is
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Re: First python program, syntax error in while loop

[ryankoch38]

Oh wow I can't believed I derped that hard
Thanks Lol.
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Re: First python program, syntax error in while loop

[ryankoch38]

I've got it working! I'm really enjoying python :) But now i'd like to make it 
break out of the while loop when the user guesses more than 5 numbers and 
fails..

title = "Guess my number game:" 
print title.title() 
raw_input("Press any key to continue..") 

import random 

number = random.randrange(99) + 1 
tries = 0 
guess = int(raw_input("Guess my number! Secret - It is between 1 and 100 :")) 

while (guess != number): 
if (guess > number): 
guess = int(raw_input("Sorry, my number is lower than that! \n Try 
again:")) 
tries += 1 
if (guess < number): 
guess = int(raw_input("Sorry, my number is higher than that! \n Try 
again:")) 
tries += 1
if (tries > 5):
print "Sorry, you lost!"
break

print "\nCongratulations! You guessed my number in", tries, "tries"


raw_input("\n\n Press any key to exit..") 

## this results in the congratulations printing after the second/third guess 
and ## continuing
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Re: First python program, syntax error in while loop

[ryankoch38]

Thank you! It's 100% functional now, here's the final project:

title = "Guess my number game:" 
print title.title() 
raw_input("Press any key to continue..") 

import random 

number = random.randrange(99) + 1 
tries = 0 
guess = int(raw_input("Guess my number! Secret - It is between 1 and 100 :")) 

while (guess != number) and (tries <5): 
if (guess > number): 
guess = int(raw_input("Sorry, my number is lower than that! \n Try 
again:")) 
tries += 1 
if (guess < number): 
guess = int(raw_input("Sorry, my number is higher than that! \n Try 
again:")) 
tries += 1 

if (tries <5):
print "\nCongratulations! You guessed my number in", tries, "tries"
else:
print "\nSorry, you took too many tries to guess my number!"


raw_input("\n\n Press any key to exit..")

## Maybe now I can work on a useful project
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