grouping array
hi if I have an array say x = [[2,2,0,0,1,1], [1,1,0,0,1,1], [1,1,0,0,1,1]] I basically want to group regions that are non zero like I want to get the coordinates of non zero regions..as (x1,y1,x2,y2) [(0,0,2,1),(0,4,2,5)] which show the top left(x1,y1) and bottom right(x2,y2) corners of each group.hope i am clear. Thanks -- http://mail.python.org/mailman/listinfo/python-list
Re: grouping array
sure: basically I am looking for clustering of non zero groups in that 2D list...so in the above array the first non zero cluster is 2,2 in row 0, 1,1 in row 1 and 1,1 in row 1 so if we think of this as one group we have the first element of the group is at (0,0) in the list and last is at (2,1) in the list so we have that group represented as (0,0,2,1) similarly the second non group...and finally we get the result list with the location of that group in the whole list as [(0,0,2,1),(0,4,2,5)...] hope I am clear. -- http://mail.python.org/mailman/listinfo/python-list
Re: grouping array
1. why are you creating an Image object here? cant this be done by handling lists? 2. What exactly is getprojection doing? -- http://mail.python.org/mailman/listinfo/python-list
Re: grouping array
fredrick's solutions seems to be more closer to what I was looking for.But I am still not sure if that could be done without the use of Image module. Also in your solution I cannot follow this [[1, 1, 2, 1, 2, 0], [2, 0, 0, 2, 0, 1], [1, 2, 2, 0, 2, 0], [0, 1, 0, 0, 0, 0], [2, 0, 0, 1, 1, 0], [2, 2, 2, 0, 1, 0]] >>> print "\n".join(str(reg) for reg in getregions(x)) [(0, 1), (0, 0), (0, 2), (1, 0), (0, 3), (2, 0), (1, 3), (0, 4), (2, 1), (3, 1), (2, 2)] [(5, 4), (4, 4), (4, 3)] [(5, 0), (5, 1), (4, 0), (5, 2)] [(1, 5)] [(2, 4)] This is kind of confusing...could you please correlate the grid to the result and explain -- http://mail.python.org/mailman/listinfo/python-list
Searching files in directories
can anyone help me with this... I want to search for a list for files in a given directory and if it exists copy them to destination directory so what i am looking for is : file = 'file1.txt' source_directory = '/tmp/source/' destination_directory = '/tmp/destination/' so If the file exists in source_directory cp that file to the destination_directory.. hope I am clear -- http://mail.python.org/mailman/listinfo/python-list
help make it faster please
I wrote this function which does the following:
after readling lines from file.It splits and finds the word occurences
through a hash table...for some reason this is quite slow..can some one
help me make it faster...
f = open(filename)
lines = f.readlines()
def create_words(lines):
cnt = 0
spl_set = '[",;<>{}_&?!():-[\.=+*\t\n\r]+'
for content in lines:
words=content.split()
countDict={}
wordlist = []
for w in words:
w=string.lower(w)
if w[-1] in spl_set: w = w[:-1]
if w != '':
if countDict.has_key(w):
countDict[w]=countDict[w]+1
else:
countDict[w]=1
wordlist = countDict.keys()
wordlist.sort()
cnt += 1
if countDict != {}:
for word in wordlist: print (word+' '+
str(countDict[word])+'\n')
--
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Re: help make it faster please
Oh sorry indentation was messed here...the
wordlist = countDict.keys()
wordlist.sort()
should be outside the word loop now
def create_words(lines):
cnt = 0
spl_set = '[",;<>{}_&?!():-[\.=+*\t\n\r]+'
for content in lines:
words=content.split()
countDict={}
wordlist = []
for w in words:
w=string.lower(w)
if w[-1] in spl_set: w = w[:-1]
if w != '':
if countDict.has_key(w):
countDict[w]=countDict[w]+1
else:
countDict[w]=1
wordlist = countDict.keys()
wordlist.sort()
cnt += 1
if countDict != {}:
for word in wordlist: print (word+' '+
str(countDict[word])+'\n')
ok now this is the correct question I am asking...
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Re: help make it faster please
Actually I create a seperate wordlist for each so called line.Here line I mean would be a paragraph in future...so I will have to recreate the wordlist for each loop -- http://mail.python.org/mailman/listinfo/python-list
Re: help make it faster please
ok this sounds much better..could you tell me what to do if I want to leave characters like @ in words.So I would like to consider this as a part of word -- http://mail.python.org/mailman/listinfo/python-list
ignore specific data
Hi I need help. What I want to do is If I read a file with some text
content...
I would like to ignore a block of lines and consider the rest..
so if the block starts with
"start of block."
fjesdgsdhfgdlgjklfjdgkd
jhcsdfskdlgjkljgkfdjkgj
"end of block"
I want to ignore this while processing the file .This block could
appear anywhere in the file.It could at the start or end or even middle
of file content.
Hope I'm clear...
somethin like
f = open("file")
clean_data = ignore_block(f)
here ignore_data should filter the block
def ignore_data(f):
.
return data # may be an array of remaining lines...
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Re: ignore specific data
thanks for that. But this will check for the exact content of the "start of block.." or "end of block". How about if the content is anywhere in the line? -- http://mail.python.org/mailman/listinfo/python-list
Re: ignore specific data
I tried the solutions you provided..these are not as robust as i thought would be... may be i should put the problem more clearly... here it goes I have a bunch of documents and each document has a header which is common to all files. I read each file process it and compute the frequency of words in each file. now I want to ignore the header in each file. It is easy if the header is always at the top. but apparently its not. it could be at the bottom as well. So I want a function which goes through the file content and ignores the common header and return the remaining text to compute the frequencies..Also the header is not just one line..it includes licences and all other stuff and may be 50 to 60 lines as well..This "remove_header" has to be much more efficient as the files may be huge. As this is a very small part of the whole problem i dont want this to slow down my entire code... -- http://mail.python.org/mailman/listinfo/python-list
