dynamically loaded libraries
I have a question about how dynamically loaded C++ modules work, which I will phrase as a hypothetical scenario involving the Numeric module. Please understand that I don't really care about Numeric per se, it's just a useful example of a module that defines a generally useful data type. Let's say I want to create a C++ Python extension module that has methods accepting the Numeric array type as input, and also create these arrays as output. In order to make this work, do I have to statically link against the Numeric source, or do I only have to include the headers, under the assumption (??) that the Numeric functionality will be available because the Python executable has dynamically loaded it? Thanks! Mike -- http://mail.python.org/mailman/listinfo/python-list
Re: where do I put resources (images, audio files) when I wrote Python program?
On Jul 27, 12:43 pm, Piotrek wrote:
> Hello,
>
> I write a Python program. It will contain some images (in .png format), some
> audio files (as .ogg) etc. Now I think where should my installer put these
> files and how should I access them. What is the normal Python way of doing
> that? I think about puting these files in /usr/share/myprogram and then
> reading it the normal way (so the path "/usr/share/myprogram" would be just
> hardwired in my program). Is it the way one usually does it in Python
> program or is there any more sofisticated way?
Usually the preferred method is either distutils (http://
docs.python.org/library/distutils.html#module-distutils) or setuptools
(http://peak.telecommunity.com/DevCenter/setuptools). Either of these
will allow you to create source (".tar.gz") or binary distributions
that can be installed relatively easily on a target machine.
Good luck,
Mike
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Decorator behavior
I am just trying to wrap my head around decorators in Python, and I'm confused about some behavior I'm seeing. Run the code below (slightly adapted from a Bruce Eckel article), and I get the following output: inside myDecorator.__init__() inside aFunction() Finished decorating aFunction() inside myDecorator.__call__() My question: Why isn't the first print statement in "__main__" the first line of code executed? Is aFunction() not closed somehow? #!/usr/bin/env python class myDecorator(object): def __init__(self, f): print "inside myDecorator.__init__()" f() # Prove that function definition has completed def __call__(self): print "inside myDecorator.__call__()" @myDecorator def aFunction(): print "inside aFunction()" if __name__ == '__main__': print "Finished decorating aFunction()" aFunction() -- http://mail.python.org/mailman/listinfo/python-list
accessing parts of large files with File.seek()
I'm having a problem with the File object's seek() method. Specifically, I cannot use it to seek to a location in a binary file that is greater than 2^31 (2147483648). This seems unnecessarily limiting, as it is common these days to have files larger than 2 GB. Is there some LargeFile object out there that I can use to read my file, which is approximately 3.3 GB in size? Python version (freshly built from source this morning): Python 2.5.1 (r251:54863, Aug 8 2007, 09:23:05) [GCC 4.0.1 (Apple Computer, Inc. build 5363)] on darwin Thanks, Mike -- http://mail.python.org/mailman/listinfo/python-list
Re: accessing parts of large files with File.seek()
On Aug 8, 7:37 pm, "[EMAIL PROTECTED]" <[EMAIL PROTECTED]>
wrote:
> On Aug 8, 11:46 am, "mhearne808[insert-at-sign-here]gmail[insert-dot-
>
>
>
> here]com" <[EMAIL PROTECTED]> wrote:
> > I'm having a problem with the File object's seek() method.
> > Specifically, I cannot use it to seek to a location in a binary file
> > that is greater than 2^31 (2147483648). This seems unnecessarily
> > limiting, as it is common these days to have files larger than 2 GB.
>
> > Is there some LargeFile object out there that I can use to read my
> > file, which is approximately 3.3 GB in size?
>
> > Python version (freshly built from source this morning):
> > Python 2.5.1 (r251:54863, Aug 8 2007, 09:23:05)
> > [GCC 4.0.1 (Apple Computer, Inc. build 5363)] on darwin
>
> > Thanks,
>
> > Mike
>
> I use large files quite a bit, but in Windows & Linux. Here's a quick
> excerpt of a local ubuntu-linux session...
>
> [EMAIL PROTECTED]:/var/virtualbox/VDI$ ls -l
> total 1682536
> -rw-rwx--- 1 jaime vboxusers 40960 2007-07-20 21:41 windows
> xp.vdi
> -rw-rwx--- 1 jaime vboxusers 3591387136 2007-07-20 21:53 winxp.vdi
> [EMAIL PROTECTED]:/var/virtualbox/VDI$ ipython
> Python 2.5.1 (r251:54863, May 2 2007, 16:27:44)
> Type "copyright", "credits" or "license" for more information.
>
> IPython 0.7.3 -- An enhanced Interactive Python.
> ? -> Introduction to IPython's features.
> %magic -> Information about IPython's 'magic' % functions.
> help-> Python's own help system.
> object? -> Details about 'object'. ?object also works, ?? prints more.
>
> In [1]: f = file('winxp.vdi')
>
> In [2]: f.seek(3591387132)
>
> In [3]: f.read()
> Out[3]: '\x00\x00\x00\x00'
>
> In [4]:
>
> What exception are you receiving? (Not that I can offer any advice,
> as I don't have a Mac to use for testing.)...
>
> jw
I think I've figured out what the problem must be (not at Mac anymore,
so will have to test tomorrow). According to this link:
http://docs.python.org/lib/posix-large-files.html
I probably need to compile in large file support on my Mac. I get it
for free on my Ubuntu linux box...
FYI, it was an OverFlow Error.
--
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fcntl problems
I'm having a number of problems with the fcntl module. First off, my
system info:
Mac OS X
Darwin igskcicglthearn.cr.usgs.gov 8.10.1 Darwin Kernel Version
8.10.1: Wed May 23 16:33:00 PDT 2007; root:xnu-792.22.5~1/RELEASE_I386
i386 i386
Python 2.5.1 (built from source)
OK, the weirdness:
First of all, if I try this:
file = open("counter.txt","w+")
fcntl.flock(file.fileno(), fcntl.LOCK_NB)
I get this:
---
Traceback (most recent call
last)
/Users/mhearne/src/python/ in ()
: [Errno 9] Bad file descriptor
However, if I try this:
fcntl.flock(file.fileno(), fcntl.LOCK_EX)
I get no errors.
Proceeding forward with the locked file, let's say I do the above in
Python interactive Process A. Then in python interactive Process B, I
repeat the "open" function on the same file with the same
permissions. Then, in each process, I write some text to the file
using the write() method. After closing the file in both processes,
the only text I see in the file is from Process B!
According to my Python Cookbook:
"Exclusive lock: This denies all _other_ processes both read and write
access to the file."
I seem to be experiencing the reverse of that description. Is this my
lack of understanding, or have I discovered a bug?
Thanks,
Mike
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Re: fcntl problems
On Aug 30, 4:19 pm, "mhearne808[insert-at-sign-here]gmail[insert-dot-
here]com" <[EMAIL PROTECTED]> wrote:
> I'm having a number of problems with the fcntl module. First off, my
> system info:
>
> Mac OS X
> Darwin igskcicglthearn.cr.usgs.gov 8.10.1 Darwin Kernel Version
> 8.10.1: Wed May 23 16:33:00 PDT 2007; root:xnu-792.22.5~1/RELEASE_I386
> i386 i386
> Python 2.5.1 (built from source)
>
> OK, the weirdness:
>
> First of all, if I try this:
> file = open("counter.txt","w+")
> fcntl.flock(file.fileno(), fcntl.LOCK_NB)
>
> I get this:
> ---
>Traceback (most recent call
> last)
> /Users/mhearne/src/python/ in ()
> : [Errno 9] Bad file descriptor
>
> However, if I try this:
> fcntl.flock(file.fileno(), fcntl.LOCK_EX)
>
> I get no errors.
>
> Proceeding forward with the locked file, let's say I do the above in
> Python interactive Process A. Then in python interactive Process B, I
> repeat the "open" function on the same file with the same
> permissions. Then, in each process, I write some text to the file
> using the write() method. After closing the file in both processes,
> the only text I see in the file is from Process B!
>
> According to my Python Cookbook:
> "Exclusive lock: This denies all _other_ processes both read and write
> access to the file."
>
> I seem to be experiencing the reverse of that description. Is this my
> lack of understanding, or have I discovered a bug?
>
> Thanks,
>
> Mike
I've been doing some experiments, and here are some specific examples
to try. I'll designate the two interactive python processes as PA and
PB. Both processes were started in the same directory. Here goes:
PA: import fcntl
PA: f = open("foo.txt","w+")
PA: fcntl.flock(f.fileno(),fcntl.LOCK_EX)
PA: f.write("text1\n")
PB: f = open("foo.txt","w+")
PB: f.write("text2\n")
PA: f.close()
PB: f.close()
contents of foo.txt are:
text2
Second experiment:
PA: f = open("foo.txt","w+")
PA: fcntl.flock(f.fileno(),fcntl.LOCK_EX)
PB: f = open("foo.txt","w+")
PA: f.write("text1\n")
PB: f.write("text2\n")
PA: f.write("text3\n")
PB: f.close()
PA: f.write("text4\n")
PA: f.close()
contents of foo.txt are:
text1
text3
text4
Third experiment:
PA: f = open("foo.txt","w+")
PA: fcntl.flock(f.fileno(),fcntl.LOCK_EX)
PA: f.write("text1\n")
PB: f = open("foo.txt","w+")
PB: f.write("text2\n")
PB: f.close()
PA: f.close()
contents of foo.txt are:
text1
Fourth experiment:
PA: f = open("foo.txt","w+")
PA: f.write("text1\n")
PB: f = open("foo.txt","w+")
PB: f.write("text2\n")
PB: f.close()
PA: f.close()
contents of foo.txt are:
text1
>From these last two experiments I can only conclude that file locking
isn't doing a durned thing.
What's going on?
--Mike
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Re: fcntl problems
On Aug 31, 12:23 am, Miles <[EMAIL PROTECTED]> wrote: > Sorry, that last quote-only reply was accidental. :) > > On 8/30/07, mhearne808 wrote: > > I've been doing some experiments, and here are some specific examples > > to try. > > [snipped examples] > > > From these last two experiments I can only conclude that file locking > > isn't doing a durned thing. > > > What's going on? > > File locking isn't doing a durned thing in those cases because you're > only obtaining the lock from a single process. > > > According to my Python Cookbook: > > "Exclusive lock: This denies all _other_ processes both read and write > > access to the file." > > This is only for mandatory locking; POSIX flock is advisory locking, > which states: "Only one process may hold an exclusive lock for a given > file at a given time." Advisory locks don't have any effect on > processes that don't use locks. Mandatory locks are kernel enforced, > but non-POSIX and not available in Mac OS X. > > -Miles I think I'm still confused. Maybe I should explain the behavior that I want, and then figure out if it is possible. I have a script that will be run from a cron job once a minute. One of the things this script will do is open a file to stash some temporary results. I expect that this script will always finish its work in less than 15 seconds, but I didn't want to depend on that. Thus I started to look into file locking, which I had hoped I could use in the following fashion: Process A opens file foo Process A locks file foo Process A takes more than a minute to do its work Process B wakes up Process B determines that file foo is locked Process B quits in disgust Process A finishes its work Since I couldn't figure out file locking, I decided to just have Process A create a "pid" file in the directory - analogous to the "Occupied" sign on an airplane bathroom. This works, but it seems a little hacky. --Mike -- http://mail.python.org/mailman/listinfo/python-list
Re: fcntl problems
On Aug 31, 8:42 am, Miles <[EMAIL PROTECTED]> wrote:
> On 8/31/07, mhearne808 wrote:
> > I have a script that will be run from a cron job once a minute. One
> > of the things this script will do is open a file to stash some
> > temporary results. I expect that this script will always finish its
> > work in less than 15 seconds, but I didn't want to depend on that.
> > Thus I started to look into file locking, which I had hoped I could
> > use in the following fashion:
>
> > Process A opens file foo
> > Process A locks file foo
> > Process A takes more than a minute to do its work
> > Process B wakes up
> > Process B determines that file foo is locked
> > Process B quits in disgust
> > Process A finishes its work
>
> That would look like (untested):
>
> importfcntl, sys
> f = open('foo', 'w+')
> try:
>fcntl.flock(f.fileno(),fcntl.LOCK_EX |fcntl.LOCK_NB)
> except IOError, e:
> if e.args[0] == 35:
> sys.exit(1)
> else:
> raise
> f.seek(0, 2) # seek to end
> # do your thing with the file
> f.flush()fcntl.flock(f.fileno(),fcntl.LOCK_UN)
> f.close()
>
> -Miles
I tested that, and it works! Thanks!
Looking at my flock(3) man page, I'm guessing that "35" is the error
code for EWOULDBLOCK. Which system header file am I supposed to look
in to figure that magic number out?
I would make the argument that this module could be either more
pythonic, or simply documented more completely. The open source
response, of course, would be "go for it!".
--Mike
--
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Don't understand module search path...
I think I don't understand how the module search path works... Let's say I have a folders called 'test'. Underneath it, I create two more folders called 'foo' and 'bar'. In 'foo', I create an empty '__init__.py' file, indicating that this folder is a package 'foo'. I then create a simple python script 'foo.py' consisting of the following code: #!/usr/bin/python def printhello(): print 'Hello world!' Then in test/bar, I create 'bar.py' consisting of the following code: #!/usr/bin/python import sys import os (curpath,thisdir) = os.path.split(os.getcwd()) foopath = os.path.join(curpath,'foo') sys.path.append(foopath) print sys.path os.chdir(os.path.join(os.getcwd(),'..')) print os.getcwd() from foo.foo import printhello When I try to run bar.py, I get the following: [sys.path search path, including full path to 'foo' folder] path/to/test Traceback (most recent call last): File "/path/to/test/bar/testfoo.py", line 16, in from foo.foo import printhello ImportError: No module named foo Why? If 'foo' is in sys.path, shouldn't it appear when I try to import the foo module from it? Incidentally, when I move the script up to 'test' and modify it so that it just says: #!/usr/bin/python from foo.foo import printhello I get no errors. I don't understand the difference... Incidentally, my platform info: Python 2.5.1 Darwin Kernel Version 8.10.1 (Mac OS X) Help! --Mike -- http://mail.python.org/mailman/listinfo/python-list
PYTHONPATH on OS X
I'm missing something major here. I'm trying to add a directory to my python path using the PYTHONPATH environment variable, and it's being ignored by the Python interactive shell. Below is a capture of what I did. Note that my newfolder appears nowhere on the list of directories in sys.path. How do I get Python to pay attention to my shell variables? Using bash on OS X 10.4.10. %:~ user$ echo $PYTHONPATH %:~ user$ PYTHONPATH=/Users/user/newfolder %:~ user$ echo $PYTHONPATH /Users/user/newfolder %:~ user$ python Python 2.5.1 (r251:54863, Aug 10 2007, 10:46:58) [GCC 4.0.1 (Apple Computer, Inc. build 5363)] on darwin Type "help", "copyright", "credits" or "license" for more information. >>> import sys >>> sys.path ['', '/usr/local/lib/python2.5/site-packages/ setuptools-0.7a1dev_r56320-py2.5.egg', '/usr/local/lib/python2.5/site- packages/ipython1-0.9alpha2-py2.5.egg', '/usr/local/lib/python2.5/site- packages/SQLAlchemy-0.4.0beta5-py2.5.egg', '/usr/local/lib/python2.5/ site-packages/MySQL_python-1.2.2-py2.5-macosx-10.3-i386.egg', '/usr/ local/lib/python25.zip', '/usr/local/lib/python2.5', '/usr/local/lib/ python2.5/plat-darwin', '/usr/local/lib/python2.5/plat-mac', '/usr/ local/lib/python2.5/plat-mac/lib-scriptpackages', '/usr/local/lib/ python2.5/lib-tk', '/usr/local/lib/python2.5/lib-dynload', '/usr/local/ lib/python2.5/site-packages', '/usr/local/lib/python2.5/site-packages/ PIL'] -- http://mail.python.org/mailman/listinfo/python-list
Re: PYTHONPATH on OS X
On Oct 10, 4:59 pm, Graham Dumpleton <[EMAIL PROTECTED]> wrote: > On Oct 11, 8:00 am, "mhearne808[insert-at-sign-here]gmail[insert-dot- > > > > here]com" <[EMAIL PROTECTED]> wrote: > > I'm missing something major here. I'm trying to add a directory to my > > python path using the PYTHONPATH environment variable, and it's being > > ignored by the Python interactive shell. > > > Below is a capture of what I did. Note that my newfolder appears > > nowhere on the list of directories in sys.path. How do I get Python > > to pay attention to my shell variables? > > > Using bash on OS X 10.4.10. > > > %:~ user$ echo $PYTHONPATH > > > %:~ user$ PYTHONPATH=/Users/user/newfolder > > %:~ user$ echo $PYTHONPATH > > /Users/user/newfolder > > %:~ user$ python > > Python 2.5.1 (r251:54863, Aug 10 2007, 10:46:58) > > [GCC 4.0.1 (Apple Computer, Inc. build 5363)] on darwin > > Type "help", "copyright", "credits" or "license" for more information.>>> > > import sys > > >>> sys.path > > > ['', '/usr/local/lib/python2.5/site-packages/ > > setuptools-0.7a1dev_r56320-py2.5.egg', '/usr/local/lib/python2.5/site- > > packages/ipython1-0.9alpha2-py2.5.egg', '/usr/local/lib/python2.5/site- > > packages/SQLAlchemy-0.4.0beta5-py2.5.egg', '/usr/local/lib/python2.5/ > > site-packages/MySQL_python-1.2.2-py2.5-macosx-10.3-i386.egg', '/usr/ > > local/lib/python25.zip', '/usr/local/lib/python2.5', '/usr/local/lib/ > > python2.5/plat-darwin', '/usr/local/lib/python2.5/plat-mac', '/usr/ > > local/lib/python2.5/plat-mac/lib-scriptpackages', '/usr/local/lib/ > > python2.5/lib-tk', '/usr/local/lib/python2.5/lib-dynload', '/usr/local/ > > lib/python2.5/site-packages', '/usr/local/lib/python2.5/site-packages/ > > PIL'] > > You need to export the environment variable. > > export PYTHONPATH > > Graham Thanks all - I'm recently back to using Unix (Mac) after 5 years of being on a PC. I guess I thought export was just another way of doing assignment. My bad. --Mike -- http://mail.python.org/mailman/listinfo/python-list
Creating installer with external extension modules
I'm creating a piece of software which will be used by in-house users. My code will all be written in pure Python; however, it depends heavily on a number of third-party Python modules, many of which have C/C++ dependencies (numpy, scipy, etc.) Installing these packages on my machine involved a morning of several serial "./ configure;make;sudo make install" steps. I'd prefer to automate all of this for my users, but I'm not clear how to do this - I'm in an environment of mixed Mac (desktops) and Linux (servers) and I'll need to install on both platforms, and would prefer not to run around to each computer making sure the dependencies are met. I've looked through the documentation for distutils and setuptools, and it's not obvious to me that there are hooks in either one for passing in configure and make calls. The fallback, I suppose, presuming that the correct version of Python is already installed, is to write a custom Python script that "knows" about each dependency, and takes the appropriate action. I should be able to depend on everyone having gcc and make installed, I think. Does anyone have any suggestions on the best way to approach this? Thanks, Mike -- http://mail.python.org/mailman/listinfo/python-list
Getting file timestamp from url
Is is possible to get the timestamp of a file on a web server if it has a URL? For example, let's say that I want to know when the following file was created: http://www.w3schools.com/xml/note.xml I can get an HTTPMessage object using urllib2, like this: --- #!/usr/bin/python import urllib2 url = 'http://www.w3schools.com/xml/note.xml' f = urllib2.urlopen(url) finfo = f.info() --- My finfo is an HTTPMessage object, which has getdate() and getdate_tz() methods. However, they both require a 'name' argument. I can't figure out what this is... Am I going down the wrong path? Is there a path I can go down to get what I want? Thanks, Mike -- http://mail.python.org/mailman/listinfo/python-list
compiling python 2.5, missing zlib
I'm trying to compile Python 2.5 on a RHEL system, using "./ configure;make;make install". The build seems to go alright, but the zlib module is missing. I've tried the following: 1) Download and build the zlib libraries myself 2) Specify '--without-system-zlib' to ./configure Neither seems to work. What am I missing here? Thanks, Mike -- http://mail.python.org/mailman/listinfo/python-list
Re: compiling python 2.5, missing zlib
On Nov 19, 2:19 pm, "Martin v. Löwis" <[EMAIL PROTECTED]> wrote: > > Neither seems to work. What am I missing here? > > You forgot to install the zlib header files, which come in > an RPM provided by Redhat (probably called zlib-dev or some > such). > > Regards, > Martin Those headers are already installed, according to "up2date". Is there a way to specify the header files used? --Mike -- http://mail.python.org/mailman/listinfo/python-list
Re: compiling python 2.5, missing zlib
On Nov 19, 8:22 pm, "Martin v. Löwis" <[EMAIL PROTECTED]> wrote: > > Those headers are already installed, according to "up2date". Is there > > a way to specify the header files used? > > It will automatically use them if they are good. What's the value of > ZLIB_VERSION in /usr/include/zlib.h? > > Regards, > Martin I got my Python compile to work, by setting recompiling the zlib source I downloaded with a --shared configure option. Now I'm having trouble getting the Python MySQL module to install. That'll be a separate post! --Mike -- http://mail.python.org/mailman/listinfo/python-list
Problems building zlib module on RHEL
I can't seem to get the zlib module to build on an RHEL box. I did the following: 1) Download zlib 1.2.3 2) configure;make;make install 3) Download python 2.5.2 4) configure;make;make install 5) >>> import zlib => "ImportError: No module named zlib" In the make install step for python, I notice there are the following errors: building 'zlib' extension gcc -pthread -shared build/temp.linux-x86_64-2.5/home/shake/python/ Python-2.5.2/Modules/zlibmodule.o -L/usr/local/lib -lz -o build/ lib.linux-x86_64-2.5/zlib.so /usr/bin/ld: /usr/local/lib/libz.a(crc32.o): relocation R_X86_64_32 against `a local symbol' can not be used when making a shared object; recompile with -fPIC /usr/local/lib/libz.a: could not read symbols: Bad value collect2: ld returned 1 exit status Does anyone have any hints on how to get around this? system info: kernel : 2.6.9-67.0.1.ELsmp gcc : 3.4.6 Thanks, Mike -- http://mail.python.org/mailman/listinfo/python-list
Re: Problems building zlib module on RHEL
On Mar 18, 8:42 am, "mhearne808[insert-at-sign-here]gmail[insert-dot- here]com" <[EMAIL PROTECTED]> wrote: > I can't seem to get the zlib module to build on an RHEL box. > > I did the following: > 1) Download zlib 1.2.3 > 2) configure;make;make install > 3) Download python 2.5.2 > 4) configure;make;make install > 5) >>> import zlib => "ImportError: No module named zlib" > > In the make install step for python, I notice there are the following > errors: > > building 'zlib' extension > gcc -pthread -shared build/temp.linux-x86_64-2.5/home/shake/python/ > Python-2.5.2/Modules/zlibmodule.o -L/usr/local/lib -lz -o build/ > lib.linux-x86_64-2.5/zlib.so > /usr/bin/ld: /usr/local/lib/libz.a(crc32.o): relocation R_X86_64_32 > against `a local symbol' can not be used when making a shared object; > recompile with -fPIC > /usr/local/lib/libz.a: could not read symbols: Bad value > collect2: ld returned 1 exit status > > Does anyone have any hints on how to get around this? > > system info: > kernel : 2.6.9-67.0.1.ELsmp > gcc : 3.4.6 > > Thanks, > > Mike I figured it out, although it wasn't obvious... You have to compile zlib as a shared library by running "configure -s". -- http://mail.python.org/mailman/listinfo/python-list
Appending to sys.path
I have an application where I would like to append to the python path
dynamically. Below is a test script I wrote. Here's what I thought
would happen:
1) I run this script in a folder that is NOT already in PYTHONPATH
2) The script creates a subfolder called foo.
3) The script creates a file called foo.py, with a foo() method
defined in it.
4) The script attempts to import this module, which fails because the
current folder is not in PYTHONPATH.
5) The script then adds the current folder to the end of sys.path
6) The script again attempts to import foo.foo, and succeeds.
#6 never happens, but I can't figure out why. I'm running on Mac OS
10.5, with python 2.5.1.
Anybody have any tips?
Thanks,
Mike
Here's the script:
#!/usr/bin/python
import sys
import os.path
txt = 'def foo(): print "Hello world!"\n'
if not os.path.isdir('foo'):
os.mkdir('foo')
f = open('foo/foo.py','wt')
f.write(txt)
f.close()
try:
__import__('foo.foo')
except ImportError:
homedir = os.path.abspath(sys.path[0]) #where is this script?
print 'Adding %s to sys.path' % (homedir)
sys.path.append(homedir)
try:
__import__('foo.foo')
print 'Import now successful'
except ImportError:
print "Why didn't this work?"
sys.exit(1)
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returning all matching groups with re.search()
Here's a scenario:
import re
m = re.search('e','fredbarneybettywilma')
Now, here's a stupid question:
why doesn't m.groups() return ('e','e','e').
I'm trying to figure out how to match ALL of the instances of a
pattern in one call - the group() and groups() return subgroups... how
do I get my search to get me all of the matching subgroups?
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