a.index(float('nan')) fails

2012-10-25 Thread mamboknave 
>>> a = [float('nan'), 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>>> a
[nan, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>>> a.index(float('nan'))
Traceback (most recent call last):
  File "", line 1, in 
ValueError: list.index(x): x not in list

That means, the function .index() cannot detect nan values.
It happens on both Python 2.6 and Python 3.1

Is this a bug? Or I am not using .index() correctly?

Thanks!
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Re: a.index(float('nan')) fails

2012-10-25 Thread mamboknave 
On Thursday, October 25, 2012 7:16:02 PM UTC-7, Cameron Simpson wrote:

Of course!! How could I get into that trap??

Thanks to you & to Terry
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global vars across modules

2012-04-22 Thread mamboknave 
I need to use global var across files/modules:

# file_1.py
a = 0
def funct_1() :
a = 1   # a is global
print(a)


# file_2.py
from file_1 import *
def main() :
funct_1()
a = 2   # a is local, it's not imported
print(a)

Here above 'a' is not imported from file_1, it's local.
The only way I was able to access the global 'a' is the following:

# file_2.py
from file_1 import *
import file_1
def main() :
funct_1()
file_1.a = 2# a is the global from file_1
print(file_1.a)


Question:
How can I access to the global 'a' in file_2 without resorting to the whole 
name 'file_1.a' ?

Thanks!
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Re: global vars across modules

2012-04-22 Thread mamboknave 
On Sunday, April 22, 2012 12:48:23 PM UTC-7, Roy Smith wrote:

> Answer 1: You can't.
> 
> Answer 2: You might want to look at thread local storage 
> (http://docs.python.org/library/threading.html#threading.local).
> 
> Answer 3: Are you sure you really want to do this?

Thanks! Here is what I need to do, perhaps you can give me some hints.

A generic module, used across different independent programs, puts its 
computing results in a var fairly big, ~50KB.

I need the functions in these programs to access that var. No assignment will 
be made to that var, it will just be accessed to parse its content.

How can I do? I cannot think of making that var local and 'returning' ~50KB all 
the times the module is called.

Any hint...?
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Sorting (deeply) nested lists

2013-03-02 Thread mamboknave 
I cannot resolve this on my own. Need help, please...

nestedTuples = [
[ (L0t0e0, L0t0e1, L0t0e2), (L0t1e0, 2, L0t1e2), (L0t2e0, L0t2e1, L0t2e2) ],
[ (L1t0e0, L1t0e1, L1t0e2), (L1t1e0, 0, L1t1e2), (L1t2e0, L1t2e1, L1t2e2) ],
[ (L2t0e0, L2t0e1, L2t0e2), (L2t1e0, 1, L2t1e2), (L2t2e0, L2t2e1, L2t2e2) ] ]

With LNtXeY I mean the element Y in the tuple X of the list N.

How can I sort nestedTuples by, say, the 2nd element in the 2nd tuple of each 
list?

The above should get sorted as :

nestedTuples = [
[ (L1t0e0, L1t0e1, L1t0e2), (L1t1e0, 0, L1t1e2), (L1t2e0, L1t2e1, L1t2e2) ],
[ (L2t0e0, L2t0e1, L2t0e2), (L2t1e0, 1, L2t1e2), (L2t2e0, L2t2e1, L2t2e2) ],
[ (L0t0e0, L0t0e1, L0t0e2), (L0t1e0, 2, L0t1e2), (L0t2e0, L0t2e1, L0t2e2) ] ]

Thanks so much!!
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Re: Sorting (deeply) nested lists

2013-03-02 Thread mamboknave 
On Saturday, March 2, 2013 9:36:43 AM UTC-8, Peter Otten wrote:
>
> You can also write this as
> 
> namedTuples.sort(key=lambda item: item[1][1])
>

That's exactly what I did before and got "IndexError: list index out of range".

So, I thought my lambda was wrong and posted here.

Now, having seen you reply, I dug deeper and... of course I had IndexError: the 
list was horribly empty!

Thanks so much for replying so quickly, Peter!
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