problem with the logic of read files

2005-04-12 Thread m_tach
I am new to python and I am not in computer science. In fact I am a biologist 
and I ma trying to learn python. So if someone can help me, I will appreciate 
it.
Thanks


#!/cbi/prg/python/current/bin/python
# -*- coding: iso-8859-1 -*-
import sys
import os
from progadn import *

ab1seq = raw_input("Entrez le répertoire où sont les fichiers à analyser: ") or 
None
if ab1seq == None :
print "Erreur: Pas de répertoire! \n"
"\nAu revoir \n"
sys.exit()

listrep = os.listdir(ab1seq)
#print listrep

extseq=[]

for f in listrep:
 if f[-4:]==".Seq":
 extseq.append(f)
# print extseq  

for x in extseq:
 f = open(x, "r")
 seq=f.read()
 f.close()
 s=seq

def checkDNA(seq):
"""Retourne une liste des caractères non conformes à l'IUPAC."""

junk=[]
for c in range (len(seq)):
if seq[c] not in iupac:
junk.append([seq[c],c])
#print junk
print "ATTN: Il y a le caractère %s en position %s " % (seq[c],c)
if junk == []:
 indinv=range(len(seq))
 indinv.reverse()
 resultat=""
 for i in indinv:
 resultat +=comp[seq[i]]
 return resultat

seq=checkDNA(seq)
print seq


#I got the following ( as you see only one file is proceed by the function even 
if more files is in extseq

['B1-11_win3F_B04_04.ab1.Seq']
['B1-11_win3F_B04_04.ab1.Seq', 'B1-11_win3R_C04_06.ab1.Seq']
['B1-11_win3F_B04_04.ab1.Seq', 'B1-11_win3R_C04_06.ab1.Seq', 
'B1-18_win3F_D04_08.ab1.Seq']
['B1-11_win3F_B04_04.ab1.Seq', 'B1-11_win3R_C04_06.ab1.Seq', 
'B1-18_win3F_D04_08.ab1.Seq', 'B1-18_win3R_E04_10.ab1.Seq']
['B1-11_win3F_B04_04.ab1.Seq', 'B1-11_win3R_C04_06.ab1.Seq', 
'B1-18_win3F_D04_08.ab1.Seq', 'B1-18_win3R_E04_10.ab1.Seq', 
'B1-19_win3F_F04_12.ab1.Seq']
..
['B1-11_win3F_B04_04.ab1.Seq', 'B1-11_win3R_C04_06.ab1.Seq', 
'B1-18_win3F_D04_08.ab1.Seq', 'B1-18_win3R_E04_10.ab1.Seq', 
'B1-19_win3F_F04_12.ab1.Seq', 'B1-19_win3R_G04_14.ab1.Seq', 
'B90_win3F_H04_16.ab1.Seq', 'B90_win3R_A05_01.ab1.Seq', 
'DL2-11_win3F_H03_15.ab1.Seq', 'DL2-11_win3R_A04_02.ab1.Seq', 
'DL2-12_win3F_F03_11.ab1.Seq', 'DL2-12_win3R_G03_13.ab1.Seq', 
'M7757_win3F_B05_03.ab1.Seq', 'M7757_win3R_C05_05.ab1.Seq', 
'M7759_win3F_D05_07.ab1.Seq', 'M7759_win3R_E05_09.ab1.Seq', 
'TCR700-114_win3F_H05_15.ab1.Seq', 'TCR700-114_win3R_A06_02.ab1.Seq', 
'TRC666-100_win3F_F05_11.ab1.Seq', 'TRC666-100_win3R_G05_13.ab1.Seq']

after this listing my programs proceed only the last element of this listing 
(TRC666-100_win3R_G05_13.ab1.Seq)

NNTCCCGAAGTGTCCCAGAGCAAATAAATGGACCCGTAGAATACTTGAACGTGTAATCTCAAA


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ATTN : Georges ( gry@ll.mit.edu)

2005-04-12 Thread m_tach
First of all thanks for helping me out.

I have to admit I dont understand some of your suggestiosn, sorry.
I dont know what is the "3D" thing... Is there another way to make it
work something more simple for a newbie like me? Thanks

What I want to do is:
First check all the files from a folder and analyze only the one with the .Seq 
extension.
What I want to do is to get the reverse complement of the DNA sequence. If 
their is a problem
with some characters in the DNA Sequence I want the function to tell it to me.

Here are the comp and iupac:

iupac ="GgAaTtCcRrYyMmKkSsWwHhBbVvDdNn"

comp={"A":"T", "T":"A", "G":"C", "C":"G", "R":"Y", "Y":"R", "M":"K",
"K":"M", "S":"W", "W":"S", "B":"V", "V":"B", "D":"H", "H":"D", "r":"y",
"y":"r", "m":"k", "k":"m", "s":"w", "w":"s", "b":"v", "v":"b", "d":"h",
"h":"d", "a":"t", "t":"a", "g":"c", "c":"g", "N":"N","n":"n"}

So if a $ or Z appears in the DNA sequence, I want to know it. 

My code so far:
# -*- coding: iso-8859-1 -*-
import sys
import os
from progadn import *

ab1seq = raw_input("Entrez le répertoire où sont les fichiers à analyser: ") or 
None
if ab1seq == None :
print "Erreur: Pas de répertoire! \n" \
"\nAu revoir \n"
sys.exit()

listrep = os.listdir(ab1seq)
#print listrep

extseq=[]

for f in listrep:
 if f[-4:]==".Seq":
 extseq.append(f)
 #print extseq

for x in extseq:
 f=open(x, "r")
 seq=f.read()
 f.close()
 #s=seq


def checkDNA(seq):
"""Retourne une liste des caractères non conformes à l'IUPAC."""

junk=[]
for c in range (len(seq)):
if seq[c] not in iupac:
junk.append([seq[c],c])
#print junk
print "ATTN: Il y a le caractère %s en position %s " % (seq[c],c)
if junk == []:
 indinv=range(len(seq))
 indinv.reverse()
 resultat=""
 for i in indinv:
 resultat +=comp[seq[i]]
 return resultat

seq=checkDNA(seq)

-

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From: gry@ll.mit.edu
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Subject: Re: problem with the logic of read files
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<[EMAIL PROTECTED]> wrote:
> I am new to python and I am not in computer science. In fact I am a
biologist and I ma trying to learn python. So if someone can help me, I
will appreciate it.
> Thanks
>
>
> #!/cbi/prg/python/current/bin/python
> # -*- coding: iso-8859-1 -*-
> import sys
> import os
> from progadn import *
>
> ab1seq =3D raw_input("Entrez le r=E9pertoire o=F9 sont les fichiers =E0
analyser: ") or None
> if ab1seq =3D=3D None :
> print "Erreur: Pas de r=E9pertoire! \n"
> "\nAu revoir \n"
> sys.exit()
>
> listrep =3D os.listdir(ab1seq)
> #print listrep
>
> extseq=3D[]
>
> for f in listrep:
## Minor -- this is better said as:  if f.endswith(".Seq"):
>  if f[-4:]=3D=3D".Seq":
>  extseq.append(f)
> # print extseq
>
> for x in extseq:
>  f =3D open(x, "r")
## seq=3D... discards previous data and refers only to that just
read.
## It would be simplest to process each file as it is read:
@@ seq=3Df.read()
@@ checkDNA(seq)
>  seq=3Df.read()
>  f.close()
>  s=3Dseq
>
> def checkDNA(seq):
> """Retourne une liste des caract=E8res non conformes =E0
l'IUPAC."""
>
> junk=3D[]
> for c in range (len(seq)):
> if seq[c] not in iupac:
> junk.append([seq[c],c])
> #print junk
> print "ATTN: Il y a le caract=E8re %s en position %s " %
(seq[c],c)
> if junk =3D=3D []:
>  indinv=3Drange(len(seq))
>  indinv.reverse()
>  resultat=3D""
>  for i in indinv:
>  resultat +=3Dcomp[seq[i]]
>  return resultat
>
> seq=3DcheckDNA(seq)
> print seq

# The program segment you posted did not define "comp" or "iupac",
# so it's a little hard to guess how it's supposed to work.  It
would
# be helpful if you gave a concise description of what you want the

# program to do, as well as brief sample of input data.
# I hope this helps!  -- Geor

Re: problem with the logic of read files.. Thanks to all for your help

2005-04-12 Thread m_tach
Everything is fine now, thanks to all for your time


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