How to I access the filename with TkFileDialog?
I'm writing a python program to open a file, and display it onscreen, but I can't seem to find the var that "tkOpenFileName" returns to. It's not much use if you can't get the filename you just chose, so there must be a way to get it. Could anyone help me? Thanks, Alex -- http://mail.python.org/mailman/listinfo/python-list
Using open() inside a subroutine
Whenever I try to open a file inside a subroutine, like so: def open(): filePath=askopenfilename() fileOpen = open(filePath, "r") fileContent = fileOpen.read() fileOpen.close() it tells me that "open() takes no arguments (2 given)" Why is that? and how can I get around that so I can open a file in a subroutine? Thanks, Alex -- http://mail.python.org/mailman/listinfo/python-list
Re: Using open() inside a subroutine
DUH. Thanks. can't beleive I missed that one... Alex -- http://mail.python.org/mailman/listinfo/python-list