Reflectiong capabilityof Python

[goatold]

Can Python create object by name? Like
clsName = "ClassA"
aObj = createObjectByName(clsName)
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socket and subprocess problem

[goatold]

Hi all,

Here is my problem, see if any one else met this before
In my python code I use subprocess.Popen to run and external program
who will listen to a TCP port. And I also create a socket to connect
to the TCP port that the external program is listening.
I will get 'Connection refused, errno=111' when I try to socket.connect
().
But if I run my subprocess.Popen code and socket code in two separate
python process. Socket will connect just fine. OS is RHEL5 x86_64,
python version is 2.6.1 Pseudo code as below


Class a:
  def run()
subprocess.Popen(..)
Class b:
  def run():
sock = socket.socket()
sock.connect(..)
#
test.py
# socket connect will fail here
a.run()
b.run()
###
test1.py
if __name__ = '__main__':
  a.run()

test2.py
# socket will connect fine
if __name__ = '__main__':
  b.run
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Re: socket and subprocess problem

[goatold]

Guys thanks to point it out.
Yes, it's a race problem. I tried sleep long enough, then I can
connect to the socket. I should add code to try to connect to the
socket for a given time out.

Roy Smith wrote:
> In article
> <6d3291c3-4e12-4bdd-884a-21f15f38d...@a12g2000pro.googlegroups.com>,
>  goat...@gmail.com wrote:
>
> > In my python code I use subprocess.Popen to run and external program
> > who will listen to a TCP port. And I also create a socket to connect
> > to the TCP port that the external program is listening.
> > I will get 'Connection refused, errno=111' when I try to
> > socket.connect().
>
> > Class a:
> >   def run()
> > subprocess.Popen(..)
> > Class b:
> >   def run():
> > sock = socket.socket()
> > sock.connect(..)
> > #
> > test.py
> > # socket connect will fail here
> > a.run()
> > b.run()
> > ###
> > test1.py
> > if __name__ = '__main__':
> >   a.run()
> >
> > test2.py
> > # socket will connect fine
> > if __name__ = '__main__':
> >   b.run
>
> Sounds like a timing problem.  I assume that the process started by a.run()
> creates a socket and does a bind/listen/accept sequence on it.  The problem
> is, there's nothing in your code which guarantees that this happens before
> b.run() executes the connect() call.
>
> The cheesy way to test this is to sleep for a second somewhere between
> a.run() and b.run().  See if that helps.
>
> If it doesn't, then it's possible the process started by a.run() isn't
> doing what it's supposed to do.  Try running test1.py, and while it's
> running, run netstat to see if you've got something listening on the port
> you expect.
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