Newbie question - leading zeros
I have looked around and cannot seem to find a way to strip leading zeros off of values in a dictionary. Basically, I am looking to do a for loop and any value that has one or more leading zeros would be stripped. Any pointers would be appreciated. Thanks -- Randomly generated signature ICMP: The protocol that goes PING! -- http://mail.python.org/mailman/listinfo/python-list
Re: Newbie question - leading zeros
On Fri, 13 Oct 2006, Rainy wrote:
>
> eldorado wrote:
>> I have looked around and cannot seem to find a way to strip leading zeros
>> off of values in a dictionary. Basically, I am looking to do a for loop
>> and any value that has one or more leading zeros would be stripped. Any
>> pointers would be appreciated. Thanks
>>
>> --
>> Randomly generated signature
>> ICMP: The protocol that goes PING!
>
> import string
>>>> string.lstrip('0001', '0')
> '1'
>
> Hope this willhelp
Perfect. Thank you and everyone else who answered.
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value exists (newbie question)
Hello,
I am trying to parse some files so that if a postal code exists, but is
longer than five digits it will return me only the first five digits:
...
for insDict in insureDict:
insDict['postalcode'] = insDict.get('postalcode')[:5]
...
This works, except for when I get a blank postalcode. In which case I get
the following error.
ERR exceptions.TypeError: iteration over non-sequence
What I would like to do is to check to make sure a value exists. I just
cannot seem to find the syntax to do that. (not asking anyone to write my
code, just looking for a pointer)
Thanks
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getting a process's PID
Hello,
I am trying to get python to give me the PID of a process (in this case
HUB). I have it working, except for the fact that the output includes
\012 (newline). Is there a way to ask python not to give me a newline?
Python 1.4 (Oct 14 1997) [C]
Copyright 1991-1995 Stichting Mathematisch Centrum, Amsterdam
>>> import os
>>> g = os.popen("ps -ef | grep HUB | grep -v grep | awk '{ print $2 }'")
>>> h = g.readlines()
>>> g.close()
>>> h
['87334\012']
Thanks in advanced for any guidance.
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Re: getting a process's PID
On Wed, 27 Dec 2006, Erik Johnson wrote:
> "eldorado" <[EMAIL PROTECTED]> wrote in message
> news:[EMAIL PROTECTED]
>> Hello,
>>
>> I am trying to get python to give me the PID of a process (in this case
>> HUB). I have it working, except for the fact that the output includes
>> \012 (newline). Is there a way to ask python not to give me a newline?
>>
>> Python 1.4 (Oct 14 1997) [C]
>> Copyright 1991-1995 Stichting Mathematisch Centrum, Amsterdam
>>>>> import os
>>>>> g = os.popen("ps -ef | grep HUB | grep -v grep | awk '{ print $2 }'")
>>>>> h = g.readlines()
>>>>> g.close()
>>>>> h
>> ['87334\012']
>
>
> There's more than one way to do it! (Oh, sorry, that's Perl...)
>
> The two most standard ways would be to call strip() on your string to get
> one sans both leading and trialing whitespace
>
>print h.strip()
>
> or if you know exactly what you've got (i.e., the newline you don't want is
> just the last character), you can just get rid of it:
>
>h = h[:-1]
>
Thanks for the help, however it doesnt look like those two solutions quite
work:
>>> g = os.popen("ps -ef | grep HUB | grep -v grep | awk '{ print $2 }'")
>>> h = g.readlines()
>>> g.close()
>>> h
['87334\012']
>>> h = h[:-1]
>>> h
[]
>>>
>>> import string
>>> g = os.popen("ps -ef | grep HUB | grep -v grep | awk '{ print $2 }'")
>>> h = g.readlines()
>>> g.close()
>>> print h.strip()
File "", line 1
print h.strip()
^
SyntaxError: invalid syntax
I looked up the syntax for print and it looks correct (at least to me ;)
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Re: getting a process's PID
On Wed, 27 Dec 2006, Erik Johnson wrote:
>
> "eldorado" <[EMAIL PROTECTED]> wrote in message
> news:[EMAIL PROTECTED]
>
>>>>> g = os.popen("ps -ef | grep HUB | grep -v grep | awk '{ print $2 }'")
>>>>> h = g.readlines()
>>>>> g.close()
>>>>> h
>> ['87334\012']
>>>>> h = h[:-1]
>>>>> h
>> []
>
> Oh, sorry... h is a list here because you are using readlines().
> I am used to doing this:
>
> fd = os.popen('ps -ef | grep python')
> s = fd.read()
>
> to get a single string. You can do something like
>
> s = h[0]
>
> and then operate on s, or you can use read() in place of readlines() to get
> h as a single string, or you can operate on the first element of h:
>
>>>> h = ['87334\012']
>>>> h[0][:-1]
> '87334'
>>>> h[0].rstrip('\n')
> '87334'
>
> All the error handling to do in the case where you actually have multiple
> processes being matched is up to you. ;)
Erik,
Thank you very much. Works perfect. I am now off to work on the multiple
process issue.
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Re: getting a process's PID
On Wed, 27 Dec 2006, Sebastian 'lunar' Wiesner wrote:
> eldorado <[EMAIL PROTECTED]> typed
>
>> Hello,
>>
>> I am trying to get python to give me the PID of a process (in this
>> case
>> HUB). I have it working, except for the fact that the output includes
>> \012 (newline). Is there a way to ask python not to give me a
>> newline?
>>
>> Python 1.4 (Oct 14 1997) [C]
>> Copyright 1991-1995 Stichting Mathematisch Centrum, Amsterdam
>>>>> import os
>>>>> g = os.popen("ps -ef | grep HUB | grep -v grep | awk '{ print $2
>>>>> }'") h = g.readlines()
>>>>> g.close()
>>>>> h
>> ['87334\012']
>>
>> Thanks in advanced for any guidance.
>
> Well, you could do everything in python itself, without using grep and
> awk at all:
>
>>>>> g = os.popen("ps -e -o pid,command")
>>>>> for line in g.readlines():
>>>>> if 'HUB' in line:
>>>>> pid = line.strip().split(' ')[0]
>>>>> break
>>>>> print pid
>
This looks cleaner than the way I was going. I created a file
called ps.py
#!/usr/local/bin/python
import os
g = os.popen("ps -e -o pid,command")
for line in g.readlines():
if 'HUB' in line:
pid = line.strip().split(' ')[0]
break
print pid
When I run ps.py I get the following error.
Traceback (innermost last):
File "./ps.py", line 5, in ?
if 'HUB' in line:
TypeError: string member test needs char left operand
I googled this error, but wasn't smart enough to figure out exactly what
it means.
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Re: getting a process's PID
On Wed, 27 Dec 2006, Sebastian 'lunar' Wiesner wrote: > eldorado <[EMAIL PROTECTED]> typed > > Strange!? On my system with Python 2.4 I don't get this error. It is > likely to be a problem of your really ancient python version. Do I > guess correctly from your previous postings, that you're still using > version 1.4?. Sebastian, Yes, I was running this on a box that had 1.4 - I just tested it on a box that has 2.3.5 and it runs perfect. Your changes also allow it to be run on the boxes that still have 1.4 Thanks for all your help. -- Randomly generated signature "I have opinions of my own -- strong opinions --but I don't always agree with them."-G.W.Bush -- http://mail.python.org/mailman/listinfo/python-list
