parsing text from a file
If I read a windows registry file with a line like this:
"{C15039B5-C47C-47BD-A698-A462F4148F52}"="v2.0|Action=Allow|Active=TRUE|Dir=In|Protocol=6|Profile=Public|App=C:\\Program
Files\\LANDesk\\LDClient\\tmcsvc.exe|Name=LANDesk Targeted
Multicast|Edge=FALSE|"
with this code:
f=open('fwrules.reg2.txt')
for s in f:
if s.find('LANDesk') <0:
print s,
LANDesk is not found.
Also this does not work:
for s in f:
try:
i=s.index('L')
print s[i:i+7]
except:
pass
all it prints is "LAND"
how do I find LANDesk in a string like this. is the "\\" messing things up?
thx,
-wj
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how to conditionally add a dict in-line
I have this line:
navs.append(A(' '+str(i+1)+'
',_href=self.action(args=request.args,vars={'_page':i,'_query':request.vars._query
or ''})))
How do I do something like this:
vars={'_page':i, if request.vars._query not None then insert this
key/value pair ('_query':request.vars._query) else insert nothing }
thx,
-wj
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Re: how to conditionally add a dict in-line
On Mon, Feb 23, 2009 at 9:35 PM, Wes James wrote:
> I have this line:
>
> navs.append(A(' '+str(i+1)+'
> ',_href=self.action(args=request.args,vars={'_page':i,'_query':request.vars._query
> or ''})))
>
> How do I do something like this:
>
> vars={'_page':i, if request.vars._query not None then insert this
> key/value pair ('_query':request.vars._query) else insert nothing }
Nevermind, this seems to work:
navs.append(A(' '+str(i+1)+'
',_href=self.action(args=request.args,vars={'_page':i,'_query':request.vars._query}
if request.vars._query else {'_page':i})))
-wj
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Re: how to conditionally add a dict in-line
Steven. Thx
(see my question below...)
On Mon, Feb 23, 2009 at 9:47 PM, Steven D'Aprano
wrote:
> On Mon, 23 Feb 2009 21:35:38 -0700, Wes James wrote:
>
>> I have this line:
>>
>> navs.append(A(' '+str(i+1)+'
>> ',_href=self.action(args=request.args,vars=
> {'_page':i,'_query':request.vars._query
>> or ''})))
>
> What a mess. How can you read it?
>
>
>> How do I do something like this:
>>
>> vars={'_page':i, if request.vars._query not None then insert this
>> key/value pair ('_query':request.vars._query) else insert nothing }
>
> vars = {'_page': i}
> if request.vars._query is not None:
> vars['_query'] = request.vars._query
Could this be:
vars = {'_page': i}
if request.vars._query:
vars['_query'] = request.vars._query
>
> See how simple and clear things are when you give up the insistence on
> making everything a one-liner?
-wj
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Re: Upgrade Python on a Mac
On Mon, Mar 2, 2009 at 2:53 PM, Rey Bango wrote: > Hi, > > I'd like to upgrade the installed version of Python that came standard > on OS X (Leopard) with either 2.6.1 or 3.0.1. Before I stick my foot > in it, I just wanted to get a better understanding of the process. I'd recommend you put your new versions in to /usr/local Leave the OS X one alone. -wj -- http://mail.python.org/mailman/listinfo/python-list
Re: file open fails.
On Tue, Mar 24, 2009 at 4:04 PM, Scott David Daniels wrote: > Atul. wrote: > In your case, '\r' is a return (a single character), not two > characters long. I think its sad that 'C:\Thesis' doesn't cause > an error because there is no such character as '\T', but I am > probably excessively pedantic. \T might mean the same thing as \t (tab), but I thought it would be different... -wj -- http://mail.python.org/mailman/listinfo/python-list
Re: file open fails.
On Tue, Mar 24, 2009 at 4:32 PM, Wes James wrote: > On Tue, Mar 24, 2009 at 4:04 PM, Scott David Daniels > wrote: >> Atul. wrote: > > > >> In your case, '\r' is a return (a single character), not two >> characters long. I think its sad that 'C:\Thesis' doesn't cause >> an error because there is no such character as '\T', but I am >> probably excessively pedantic. > > \T might mean the same thing as \t (tab), but I thought it would be > different... I guess not: http://docs.python.org/reference/lexical_analysis.html#string-literals Wonder why when I do print "test\Ttest" vs print "test\ttest" \T just get printed? -wj -- http://mail.python.org/mailman/listinfo/python-list
python twitter
Anyone know if there is a twit for python? I did http://twitter.com/python, but nope on that I was looking for twit py announcements, etc... thx, -wj -- http://mail.python.org/mailman/listinfo/python-list
Re: Best Python Web Framework ?
On Tue, Apr 21, 2009 at 12:46 PM, SKYLAB wrote: > Greetings.. > > First , my english is not good . > > I heard that was written in python ( Youtube Programming Language : > PYTHON :S ) Correct ? > > That's not correct ? Then youtube is PHP application ? > > That's correct ; Which python web framework in friendfeed ? Web.py ? > Django ? web2py ? > You'll need to do some homework to see what fits. Here's a starter point: http://wiki.python.org/moin/WebFrameworks Try some or all. I used perl for a long time, went looking for a framework, tried django for a few days then found web2py and web2py fits for me. good luck -wj -- http://mail.python.org/mailman/listinfo/python-list
string to list when the contents is a list
I have been trying to create a list form a string. The string will be
a list (this is the contents will look like a list). i.e. "[]" or
"['a','b']"
The "[]" is simple since I can just check if value == "[]" then return []
But with "['a','b']" I have tried and get:
a="['a','b']"
b=a[1:-1].split(',')
returns
[ " 'a' "," 'b' " ]
when I want it to return ['a','b'].
How can I do this?
thx,
-wes
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error trying to join #python on irc.freenode.net
When I try to join #python on irc.freenode.net it keeps saying: You need to identify with network services to join the room "#python" on "irc.freenode.net". Server Details: Cannot join channel (+r) - you need to be identified with services What does this mean? thx, -wes -- http://mail.python.org/mailman/listinfo/python-list
Re: error trying to join #python on irc.freenode.net
On Wed, Feb 17, 2010 at 4:53 PM, Wes James wrote: > When I try to join #python on irc.freenode.net it keeps saying: > > You need to identify with network services to join the room "#python" > on "irc.freenode.net". > > Server Details: > Cannot join channel (+r) - you need to be identified with services > > What does this mean? Nevermind, I think it means I need to register with the service and supply real username/password. -wes -- http://mail.python.org/mailman/listinfo/python-list
Re: string to list when the contents is a list
On Thu, Feb 18, 2010 at 8:18 AM, Tim Chase
wrote:
> Wes James wrote:
>
> Just to add to the list of solutions I've seen, letting the built-in csv
> module do the heavy lifting:
>
> >>> s = "['a','b']"
> >>> import csv
> >>> no_brackets = s[1:-1] # s.strip(' \t[]')
> >>> c = csv.reader([no_brackets], quotechar="'")
> >>> c.next()
> ['a', 'b']
>
> This also gives you a bit of control regarding how escaping is done, and
> other knobs & dials to twiddle if you need. Additionally, if you have more
> than one string to process coming from an iterable source (such as a file),
> you can just pass that iterator to csv.reader() instead of concocting a
> one-element list.
Thx, I think this will work for what I want.
-wes
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Re: string to list when the contents is a list
On Thu, Feb 18, 2010 at 12:32 PM, Wes James wrote:
> On Thu, Feb 18, 2010 at 8:18 AM, Tim Chase
> wrote:
>> Wes James wrote:
>
>
>>
>> Just to add to the list of solutions I've seen, letting the built-in csv
>> module do the heavy lifting:
>>
>> >>> s = "['a','b']"
>> >>> import csv
>> >>> no_brackets = s[1:-1] # s.strip(' \t[]')
>> >>> c = csv.reader([no_brackets], quotechar="'")
>> >>> c.next()
>> ['a', 'b']
Hmm. When I put csv.reader in a class:
import csv
class IS_LIST():
def __init__(self, format='', error_message='must be a list!'):
self.format = format
self.error_message = error_message
def __call__(self, value):
try:
if value=='[]' or value=='':
value=[]
else:
no_brackets = value[1:-1] # s.strip(' \t[]')
c = csv.reader([no_brackets], quotechar="'")
value=c.next()
return (value, None)
except:
return (value, self.error_message)
def formatter(self, value):
return value
I get an error (when I take the "try" out):
AttributeError: 'function' object has no attribute 'reader'
Why?
-wes
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Re: python dowload
> > > NEW QUESTION if y'all are still reading: > > Is there an integer increment operation in Python? I tried > using i++ but had to revert to 'i = i + 1' i+=1 -- http://mail.python.org/mailman/listinfo/python-list
Re: WANTED: Regular expressions for breaking TeX/LaTeX document into tokens
On Wed, Feb 24, 2010 at 5:03 AM, Jonathan Fine wrote: > Hi > > Does anyone know of a collection of regular expressions that will break a > TeX/LaTeX document into tokens? Assume that there is no verbatim or other > category code changes. I'm not sure how this does it, but it might help: http://plastex.sourceforge.net/plastex/sect0025.html -wes -- http://mail.python.org/mailman/listinfo/python-list
