Re: Unable to make ironpython run in browser with silverlight
On May 26, 9:44 am, Jimmy Schementi wrote: > You need to run it from a web-server; it doesn't work when running from > file:// due to Silverlight's security sandbox. Read the comments on my > blog-post, it mentions the web-server there. I see.. But here: http://silverlighttest.zzl.org/silverlighttest.html , it runs from a web server, but still gives error. And it has the same source code as your example, except that I replace repl.py with the direct link, as you advise on your blog. I think the problem is with this part: http://github.com/jschementi/pycon2010/ raw/master/repl.py"> Because when I delete it, it runs properly. Do you know why is that? -- http://mail.python.org/mailman/listinfo/python-list
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Job Title: Python developers Duration: 6 months; Location: Austin TX Responsibilities / Skills: 1) distributed complex application experience 2) prefer experience with enterprise class identity management systems, particularly around auth/credentials 3) experience with openstack 4) experience with large scale systems 5) Proficiency with Linux, ability to write Bash / Perl / Python scripts to run CRON jobs 6) Experience working in an agile environment and with a distributed team If interested, please reply with your updated Resume at sunny_nar...@persistent.co.in Regards, Sunny Narang Talent Acquisition sunny_nar...@persistent.co.in Persistent Systems Ltd. | 20 Glorious Years | www.persistentsys.com -- http://mail.python.org/mailman/listinfo/python-list
Re: ValueError: invalid literal for int():
Hi Chris,
Thanks for your help. but i need to to convert the whole string to int.
heres my full code,
ptid = 'item_01bom'
so item_01bom is a field name in form, so i get its value,
partintid = int(form[ptid]). # the value of form[ptid] is 'Screw plugg
(91_10 - untitled)'
Hence i get the error. hope i am clear now.
-
Sunny
On Mon, Jul 26, 2010 at 4:25 PM, Chris Rebert wrote:
> On Mon, Jul 26, 2010 at 3:25 AM, lee wrote:
> > Hi,
> >
> > I have a value,
> >
> > partintid = int(Screw plugg (91_10 -> untitled))
> >
> > but i get ValueError: invalid literal for int(): Screw plugg (91_10 -
> >> untitled)
> > any help?
>
> That is most certainly not your actual exact code, since it has a few
> SyntaxErrors and thus Python would have bailed-out long before it ever
> got the chance to raise ValueError. Please copy-and-paste the *actual
> exact code* and exact error message.
> Also, next time say what the desired output/behavior you're seeking is.
>
> That being said, if your code is (as I suspect) in actuality:
>
> partintid = int("Screw plugg (91_10 -> untitled)")
>
> then I would agree with int() and say that that string is nowhere
> close to representing an integer (how precisely is "Screw" to be
> interpreted as an integer, pray tell?); so what's so surprising about
> getting an error when trying to convert it to one?
>
> I suspect you're trying to extract 91 or 10 from the string. Use
> string methods[1] to parse the desired numerical section out of the
> string, and then pass the resulting numerical string to int(), which
> will accept it without error and properly convert it.
>
> If you want more detailed help, please provide a specification of
> typical input strings and desired output integers.
>
> [1]: http://docs.python.org/library/stdtypes.html#string-methods
>
> Regards,
> Chris
> --
> http://blog.rebertia.com
>
--
All that we are is the result of what we have thought. The mind is
everything. What we think we become.
Regards,
Sunny
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Tkinter problem
I am using Colab. How could solve this problem.
import tkinter as Tk
from tkinter import *
import sys
import os
#create main window
master = Tk()
master.title("tester")
master.geometry("300x100")
#make a label for the window
label1 = tkinter.Label(master, text='Hello')
# Lay out label
label1.pack()
# Run forever!
master.mainloop()
The error shows that :
in ()
9
10 #create main window
---> 11 master = Tk()
12 master.title("tester")
13 master.geometry("300x100")
/usr/lib/python3.7/tkinter/__init__.py in __init__(self, screenName, baseName,
className, useTk, sync, use)
2021 baseName = baseName + ext
2022 interactive = 0
-> 2023 self.tk = _tkinter.create(screenName, baseName, className,
interactive, wantobjects, useTk, sync, use)
2024 if useTk:
2025 self._loadtk()
TclError: couldn't connect to display ":0.0"
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Anaconda navigator not working
After installing Anaconda, I tried to open the anaconda navigator but it did not work. When i check in anaconda prompt by running code >>>anaconda it got error like this (base) C:\Users\Acer>anaconda Traceback (most recent call last): File "C:\Users\Acer\anaconda3\Scripts\anaconda-script.py", line 6, in from binstar_client.scripts.cli import main File "C:\Users\Acer\anaconda3\lib\site-packages\binstar_client\__init__.py", line 17, in from .utils import compute_hash, jencode, pv File "C:\Users\Acer\anaconda3\lib\site-packages\binstar_client\utils\__init__.py", line 17, in from .config import (get_server_api, dirs, load_token, store_token, File "C:\Users\Acer\anaconda3\lib\site-packages\binstar_client\utils\config.py", line 54, in USER_LOGDIR = dirs.user_log_dir File "C:\Users\Acer\anaconda3\lib\site-packages\binstar_client\utils\appdirs.py", line 257, in user_log_dir return user_log_dir(self.appname, self.appauthor, File "C:\Users\Acer\anaconda3\lib\site-packages\binstar_client\utils\appdirs.py", line 205, in user_log_dir path = user_data_dir(appname, appauthor, version); version = False File "C:\Users\Acer\anaconda3\lib\site-packages\binstar_client\utils\appdirs.py", line 67, in user_data_dir path = os.path.join(_get_win_folder(const), appauthor, appname) File "C:\Users\Acer\anaconda3\lib\site-packages\binstar_client\utils\appdirs.py", line 284, in _get_win_folder_with_pywin32 from win32com.shell import shellcon, shell ImportError: DLL load failed while importing shell: %1 is not a valid Win32 application. what is its solution? -- https://mail.python.org/mailman/listinfo/python-list
