__init__() not called automatically
hi, i come from a c++ background. i ws happy to find myself on quite familiar grounds with Python. But, what surprised me was the fact that the __init__(), which is said to be the equivlent of the constructor in c++, is not automatically called. I'm sure there must be ample reason for this. I would like to know why this is so? This is my view is more burden on the programmer. Similarly, why do we have to explicitly use the 'self' keyword everytime? Every kind of help would be welcome. -- http://mail.python.org/mailman/listinfo/python-list
Re: __init__() not called automatically
Tim pointed out rightly that i missed out the most crucial part of my question. i should have said that __init__() is not called automatically only for the inheritance hierarchy. we must explicitly call all the base class __init__() fuctions explicitly. i wanted a reason for that. Thanks Tim. -- http://mail.python.org/mailman/listinfo/python-list
Re: __init__() not called automatically
if i understand C++ right, in c++ you CAN explicitly call the base constructor ( for eg. if it requires some particular arguements ), but, the compiler automatically has to call the base class constructor ( see the rules for constructing an object of the derived classes ). But, yes, C++ can be too disgusting sometimes. But, i like the C++ design philosophy ( read D & E of C++ ? ), the rasons for various features are intellgently put inplace. Correct me if i am wrong about both the paragraphs. ok? T Thanks -- http://mail.python.org/mailman/listinfo/python-list
Re: __init__() not called automatically
maybe like this: we can have the default behaviour as calling the default constructor ( with default arguements where required ). Along with this, keep the option open to call constructors explicitly. My only contention is that there may be a greater reason for this rule in the Python Language. thats it. -- http://mail.python.org/mailman/listinfo/python-list
