Drilling down in a dict with "complex" objects

[Six]

I am trying to access an objects sub-object attributes. I can boil the
code I am working with down to this problem section:
(snip)
class Pt:
  x = None
  y = None
  def __init__(self, x, y):
self.x, self.y = x, y
  pass

class Pts:
  curr_point = None
  next_point = None
  def __init__(self, n, m):
self.next_point = Pt(n, m)
  def update(self, point):
self.curr_point = self.next_point
self.next_point = point

class PtManage:
  points = {}
  def __init__(self):
pass

point = Pts(3,5)
pman = PtManage()
pman.points["odds"] = point
print dir(pman)

print pman["odds"].next_point.x

(snip)

It's this last line that doesn't work. What am I doing wrong? Is this
a failure of the design or am I missing something obvious? How do I
get down and see that "Pt" classes x attribute within the PtManage
dict?
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Announcing Methodfinder

[Bill Six]

Sometimes you know the inputs and outputs for a procedure, but you don't
remember the name. methodfinder.find tries to find the name.

https://github.com/billsix/methodfinder

>>> import methodfinder
>>> methodfinder.find([]) == 0
len([])
sum([])
>>> methodfinder.find([]) == False
any([])
bool([])
callable([])
>>> methodfinder.find(3) == "3"
ascii(3)
format(3)
repr(3)
str(3)
>>> methodfinder.find([1,2,6,7], 6) == True
6 in [1, 2, 6, 7]
[1, 2, 6, 7].__contains__(6)
>>> methodfinder.find(" ",["foo", "bar"]) == "foo bar"
' '.join(['foo', 'bar'])
>>> methodfinder.find([1,2,3]) == 6
sum([1, 2, 3])
>>> methodfinder.find([1,2,3]) == 7
>>> methodfinder.find('1 + 1') == 2
eval('1 + 1')
>>> methodfinder.find(0) == 1
0.denominator
math.factorial(0)
>>> methodfinder.find(0.0) == 1.0
math.cos(0.0)
math.cosh(0.0)
math.erfc(0.0)
math.exp(0.0)
>>> methodfinder.find([1,2]) == [[1,2],[2,1]]
itertools.permutations([1, 2])
>>> methodfinder.find([1,2], [3,4]) == [[1,3],[2,4]]
itertools.zip_longest([1, 2], [3, 4])
zip([1, 2], [3, 4])
>>> methodfinder.find([1,2], lambda x, y: x + y) == 3
functools.reduce( at 0x7efca8f8f4d0>, [1, 2])
>>> methodfinder.find(-1,3) == 2
-1%3
-1+3
3+-1
>>> methodfinder.find(3,2) == 1.5
3/2
>>> methodfinder.find(-1) == 1
-(-1)
-1.bit_length()
-1.denominator
abs(-1)
>>> methodfinder.find(1,2) == 3
1+2
1^2
1|2
2+1
2^1
2|1
>>> methodfinder.find(1,1) == 1
1&1
1**1
1*1
1.__class__(1)
1.denominator
1.numerator
1.real
1//1
1|1
math.gcd(1, 1)
max(1, 1)
min(1, 1)
pow(1, 1)
round(1, 1)
>>> methodfinder.find([1,2], '__iter__') == True
hasattr([1, 2], '__iter__')


Bill Six
-- 
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