How to install matplotlib in Debian 9

2018-06-08 Thread Markos

Hi,

I'm starting my studies with Python 3 on Debian 9 that I just installed.

I have to install the matplotlib module, but I am in doubt what is the 
difference of the commands:


pip3 install matplotlib

or

apt-get install python3-matplotlib

Is there any difference in the packages which are installed?

Thanks,

Markos

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Re: How to install matplotlib in Debian 9

2018-06-11 Thread Markos



Em 08-06-2018 20:11, Jim Lee escreveu:


On 06/08/2018 11:54 AM, Markos wrote:

Hi,

I'm starting my studies with Python 3 on Debian 9 that I just installed.

I have to install the matplotlib module, but I am in doubt what is 
the difference of the commands:


pip3 install matplotlib

or

apt-get install python3-matplotlib

Is there any difference in the packages which are installed?

Thanks,

Markos

It's generally preferable to use your distribution's package manager 
(apt-get) to install packages, as you will then receive updates as 
they become available.  However, Debian is notorious for having 
stale/outdated packages in its repository.  If you need the latest 
version of matplotlib, use pip (you'll have to update it manually).  
If you want old but stable, use apt-get.


-Jim




Hi Jim,

As I prefer more stability than "updability" I will install the package:

apt-get install python3-matplotlib

Best Regards,
Markos

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Difference between array( [1,0,1] ) and array( [ [1,0,1] ] )

2019-06-20 Thread Markos


Hi,

I'm studying Numpy and I don't understand the difference between


vector_1 = np.array( [ 1,0,1 ] )


with 1 bracket and


vector_2 = np.array( [ [ 1,0,1 ] ] )


with 2 brackets

The shape of vector_1 is:


vector_1.shape

(3,)

But the shape of vector_2 is:


vector_2.shape

(1, 3)

The transpose on vector_1 don't work:


vector_1.T

array([1, 0, 1])

But the transpose method in vector_2 works fine:


vector_2.T

array([[1],
   [0],
   [1]])


I thought that both vectors would be treated as an matrix of 1 row and 3 
columns.


Why this difference?

Any tip?

Thank you,
Markos
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Re: Difference between array( [1,0,1] ) and array( [ [1,0,1] ] )

2019-06-22 Thread Markos

Thanks Edmondo, Stephen, Mats and Steven you for the tips,

I studied linear algebra many years ago and I remember only a few rudiments.

But I was trying to visualize (in a geometric way) how the numpy 
represents arrays, and what the geometrical meaning of the transpose 
operation made by numpy.


I think I understood a little bit more.

The number of nested brackets indicates the number of array dimensions.
the vector ( [1,2] ) is one-dimensional, but the vector ( [ [1,2] ] ) is 
two-dimensional.


v_1 = np.array( [1,2] )
> v_1.shape
(2,)
> v_1
v_1
> v_1
array( [1, 2] )
> v_2 = np.array( [ [1,2] ] )
> v_2.shape
(1, 2)

And it does not make sense to transpose a one-dimensional array.

> v_1.T
array( [1, 2] )
> v_2.T
array( [ [1],
 [2] ] )

Anothe example:

vector_1 = np.array( [   1,   2,   3,   4,   5,   6,   7,   8  ] )

  ^

vector_2 = np.array( [    [1, 2, 3, 4],    [5, 6, 7, 8]  ]  )

  ^  ^

vector_3 = np.array( [   [   [1,2],  [3,4]  ], [  [5,6],   [7,8] ]  ]  )

  ^ ^ ^

> vector_1
array([1, 2, 3, 4, 5, 6, 7, 8])
> vector_2
array( [ [1, 2, 3, 4],
 [5, 6, 7, 8] ] )
> vector_3
array( [ [ [1, 2],
   [3, 4] ],

 [ [5, 6],
   [7, 8] ] ] )

And looking for some tutorial about geometric aspects of matrices and 
the geometric meaning of the transpose I found that transposed is 
"mirrored along the diagonal" at:


https://www.coranac.com/documents/geomatrix/

>vector_1.T
array([1, 2, 3, 4, 5, 6, 7, 8])
> vector_2.T
array( [ [1, 5],
 [2, 6],
 [3, 7],
 [4, 8] ] )
> vector_3.T
array( [ [ [1, 5],
   [3, 7]],

 [ [2, 6],
   [4, 8] ] ] )

Thank you,
Markos

Em 21-06-2019 07:44, edmondo.giovanno...@gmail.com escreveu:

Every array in numpy has a number of dimensions,
"np.array" is a function that can create an array numpy given a list.

when  you write
vector_1  = np.array([1,2,1])
you are passing a list of number to thet function array that will create a 1D 
array.
As you are showing:
vector_1.shape
will return a tuple with the sizes of each dimension of the array that is:
(3,)
Note the comma thta indicate that is a tuple.
While if you write:
vector_2 = np.array([[1,2,3]])
You are passing a list of list to the function array that will instruct it to 
crete a 2D array, even though the size of the first dimension is 1:
vector_2.shape
(1,3)
It is still a tuple as you can see.
Try:
vector_3 = np.array([[1,2,3],[4,5,6]])
And you'll see that i'll return a 2D array with a shape:
vector_3.shape
(2,3)
As the external list has 2 elements that is two sublists each with 3 elements.
The vector_2 case is just when the external list has only 1 element.

I hope it is more clear now.
Cherrs,

   

   
   


Il giorno venerdì 21 giugno 2019 08:29:36 UTC+2, Markos ha scritto:

Hi,

I'm studying Numpy and I don't understand the difference between


vector_1 = np.array( [ 1,0,1 ] )

with 1 bracket and


vector_2 = np.array( [ [ 1,0,1 ] ] )

with 2 brackets

The shape of vector_1 is:


vector_1.shape

(3,)

But the shape of vector_2 is:


vector_2.shape

(1, 3)

The transpose on vector_1 don't work:


vector_1.T

array([1, 0, 1])

But the transpose method in vector_2 works fine:


vector_2.T

array([[1],
     [0],
     [1]])


I thought that both vectors would be treated as an matrix of 1 row and 3
columns.

Why this difference?

Any tip?

Thank you,
Markos


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Matplotlib import image as float32

2019-07-01 Thread Markos

Hi,

I observed that matplotlib reads an image file (PNG) as float32:

Please, how to read this file as int8 to get RGB in range of 0-255?

Thank you,

Markos


import numpy as np



import matplotlib.pyplot as plt



import matplotlib.image as mpimg



imagem = mpimg.imread('lenna.png')



print (imagem)


[[[0.8862745  0.5372549  0.49019608]
  [0.8862745  0.5372549  0.49019608]
  [0.8745098  0.5372549  0.52156866]
  ...


print (imagem.dtype)


float32


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Re: Matplotlib import image as float32

2019-07-02 Thread Markos

Em 01-07-2019 18:03, Chris Angelico escreveu:

On Tue, Jul 2, 2019 at 6:59 AM Markos  wrote:

Hi,

I observed that matplotlib reads an image file (PNG) as float32:

Please, how to read this file as int8 to get RGB in range of 0-255?

Thank you,

Markos


import numpy as np
import matplotlib.pyplot as plt
import matplotlib.image as mpimg
imagem = mpimg.imread('lenna.png')
print (imagem)

[[[0.8862745  0.5372549  0.49019608]
[0.8862745  0.5372549  0.49019608]
[0.8745098  0.5372549  0.52156866]
...


print (imagem.dtype)

float32


Seems like matplotlib is rescaling everything to be on the range 0 to 1.

https://matplotlib.org/users/image_tutorial.html

ChrisA

Hi Chris,

I found a workaround at:

www.programcreek.com/python/example/99442/matplotlib.image.imread

I don't know if is the most elegant  but it worked.

I replaced:

imagem = mpimg.imread('lenna.png')


by the command:


 imagem = (mpimg.imread('lenna.png') * 255).astype('uint8')

Thanks,

Markos

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Most efficient way to replace "," with "." in a array and/or dataframe

2019-09-21 Thread Markos

Hi,

I have a table.csv file with the following structure:

, Polyarene conc ,, mg L-1 ,,,
Spectrum, Py, Ace, Anth,
1, "0,456", "0,120", "0,168"
2, "0,456", "0,040", "0,280"
3, "0,152", "0,200", "0,280"

I open as dataframe with the command:

data = pd.read_csv ('table.csv', sep = ',', skiprows = 1)

and the variable "data" has the structure:

Spectrum,  Py,  Ace, Anth,
0  1 0,456  0,120  0,168
1  2 0,456 0,040 0,280
2  3 0,152 0,200 0,280

I copy the numeric fields to an array with the command:

data_array = data.values [:, 1:]

And the data_array variable gets the fields in string format:

[['0,456' '0,120' '0,168']
['0,456' '0,040' '0,280']
['0,152' '0,200' '0,280']]

The only way I found to change comma "," to dot "." was using the method 
replace():


for i, line in enumerate (data_array):
data_array [i] = ([float (element.replace (',', '.')) for element in 
data_array [i]])


But I'm wondering if there is another, more "efficient" way to make this 
change without having to "iterate" all elements of the array with a loop 
"for".


Also I'm also wondering if there would be any benefit of making this 
modification in dataframe before extracting the numeric fields to the array.


Please, any comments or tip?

Thanks you,

Markos

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Re: Most efficient way to replace ", " with "." in a array and/or dataframe

2019-09-22 Thread Markos


Em 22-09-2019 13:10, Piet van Oostrum escreveu:

Markos  writes:


Hi,

I have a table.csv file with the following structure:

, Polyarene conc ,, mg L-1 ,,,
Spectrum, Py, Ace, Anth,
1, "0,456", "0,120", "0,168"
2, "0,456", "0,040", "0,280"
3, "0,152", "0,200", "0,280"

I open as dataframe with the command:

data = pd.read_csv ('table.csv', sep = ',', skiprows = 1)


[snip]


Also I'm also wondering if there would be any benefit of making this
modification in dataframe before extracting the numeric fields to the
array.

Please, any comments or tip?

data = pd.read_csv ('table.csv', sep = ',', skiprows = 1, decimal=b',', 
skipinitialspace=True)


Thank you for the tip.

I didn't realize that I could avoid formatting problems in the dataframe 
or array simply by using the read_csv command with the correct 
parameters (sep and decimal).


I searched for information about the meaning of the letter "b" in the 
parameter decimal=b','  but didn't find.


I found that it also works without the letter b.

Best Regards,
Markos
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Re: Most efficient way to replace ", " with "." in a array and/or dataframe

2019-09-22 Thread Markos




Em 22-09-2019 13:10, Piet van Oostrum escreveu:

Markos  writes:


Hi,

I have a table.csv file with the following structure:

, Polyarene conc ,, mg L-1 ,,,
Spectrum, Py, Ace, Anth,
1, "0,456", "0,120", "0,168"
2, "0,456", "0,040", "0,280"
3, "0,152", "0,200", "0,280"

I open as dataframe with the command:

data = pd.read_csv ('table.csv', sep = ',', skiprows = 1)


[snip]


Also I'm also wondering if there would be any benefit of making this
modification in dataframe before extracting the numeric fields to the
array.

Please, any comments or tip?

data = pd.read_csv ('table.csv', sep = ',', skiprows = 1, decimal=b',', 
skipinitialspace=True)



Thank you very much for all the contributions.

I didn't realize that I could avoid formatting problems in the dataframe 
or array simply by using the read_csv command with the correct 
parameters (sep and decimal).


I searched for information about the meaning of the letter b in the 
parameter but did not find it.


I found that it also works without the letter b.

Best Regards,
Markos
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I can't access dataframe fields

2020-02-15 Thread Markos

Hi all,

I created the following data frame (updated_distance_matrix)

 P1    P2    P4    P5   (P3, P6)
P1 0,00 0,244307 0,367696 0,341760 0
P2 0.234307 0.00 0.194165 0.1443178 0
P4 0.366969 0.194165 0.00 0.284253 0
P5 0.341760 0.1443178 0.284253 0.00 0
(P3, P6) 0.00 0.00 0.00 0.00 0

I can change the fields of columns and rows P1-P5 without problems.

But when I try to access the fields of the row, or column, (P3, P6)

print (updated_distance_matrix_df.loc [clusters [i], last_cluster])

the message appears:

KeyError: 'the label [P3, P6] is not in the [index]'

If I change find the "loc" by "at" method appears the error:

print (updated_distance_matrix_df.at [clusters [i], last_cluster])

TypeError: unhashable type: 'list'

And if you simply leave:

print (updated_distance_matrix_df [clusters [i], last_cluster])

gives the error:

TypeError: unhashable type: 'list'

A last_cluster variable is of type list:

print (last_cluster, type (last_cluster))

['P3', 'P6'] 

And a variable cluster [i] is a string:

print (clusters [i], type (clusters [i]))

P5 

Any tip?

Thank you,

Markos

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Re: I can't access dataframe fields

2020-02-17 Thread Markos

Hi MRAB,

I changed last_cluster to tuple(last_cluster).

From:

print (updated_distance_matrix_df.loc [clusters [i], last_cluster])

to

print (updated_distance_matrix_df.loc [clusters [i], tuple(last_cluster)])

And worked.

Thank you,

Markos


Em 15-02-2020 23:36, MRAB escreveu:

On 2020-02-16 00:50, Markos wrote:

Hi all,

I created the following data frame (updated_distance_matrix)

   P1    P2    P4    P5 (P3, P6)
P1 0,00 0,244307 0,367696 0,341760 0
P2 0.234307 0.00 0.194165 0.1443178 0
P4 0.366969 0.194165 0.00 0.284253 0
P5 0.341760 0.1443178 0.284253 0.00 0
(P3, P6) 0.00 0.00 0.00 0.00 0

I can change the fields of columns and rows P1-P5 without problems.

But when I try to access the fields of the row, or column, (P3, P6)

print (updated_distance_matrix_df.loc [clusters [i], last_cluster])

the message appears:

KeyError: 'the label [P3, P6] is not in the [index]'

The rows and columns have "(P3, P6)", but you're looking for "[P3, 
P6]". They aren't the same.



If I change find the "loc" by "at" method appears the error:

print (updated_distance_matrix_df.at [clusters [i], last_cluster])

TypeError: unhashable type: 'list'

Is it expecting a tuple instead of a list? Tuples are hashable, lists 
are not.



And if you simply leave:

print (updated_distance_matrix_df [clusters [i], last_cluster])

gives the error:

TypeError: unhashable type: 'list'

A last_cluster variable is of type list:

print (last_cluster, type (last_cluster))

['P3', 'P6'] 

And a variable cluster [i] is a string:

print (clusters [i], type (clusters [i]))

P5 

Any tip?

Thank you,



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Errors in testing the SciPy installation

2020-02-22 Thread Markos

Hi,

Following the guidelines of the book Learning SciPy for Numerical and 
Scientific Computing Second Edition


I did the tests:

>>> import scipy
>>> scipy.test()

and got some errors:

Ran 23065 tests in 490.568s

FAILED (KNOWNFAIL=60, SKIP=1795, errors=29)


What should I do?

Thank you,
Markos

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Re: Covariance matrix syntax

2020-10-19 Thread Markos

Hi Meghna,

I organized some tutorials about Machine Learning for Chemistry with Python.

Where you can find some info about the use of Covariance Matrix that may 
help you.


The originals are in Portugueese, but you can read using Google Translator:

https://tinyurl.com/yybazx9n

https://tinyurl.com/y29mule6

https://tinyurl.com/yxtg4tce

Best Regards,
Markos

Em 19-10-2020 02:23, Meghna Karkera escreveu:

Dear Sir

I am unable to find the *formula for covariance* used in np.cov syntax in
PYTHON given in link
https://numpy.org/doc/stable/reference/generated/numpy.cov.html.  Could you
please help me out.

Thanks
Meghna

On Tue, Oct 13, 2020 at 11:46 AM Christian Gollwitzer 
wrote:


Am 13.10.20 um 06:52 schrieb Meghna Karkera:

Could you let me know what is the back end calculation of this covariance
matrix syntax np.cov


You can look it up yourself: Go to the docs
https://numpy.org/doc/stable/reference/generated/numpy.cov.html

At the right hand side, just right of the function signature, there is a
link [source]. Click there and it takes you to the implementation.

Apparently it is done in straightforward Python.

 Christian

PS: Snipped a lot of unrelated citation at the bottom


On Tue, Oct 13, 2020, 10:14 Bruno P. Kinoshita <

brunodepau...@yahoo.com.br>

wrote:
[...]

I think the np.cov is from the numpy module (imported/aliased as np?).

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How to install i1636

2015-03-09 Thread Markos

Please,

How to install the ia636 library on Debian (Squeeze) with Python 2.6?

Thank you,
Markos
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Idle - ImportError: No module named numpy

2015-03-09 Thread Markos

Hi,

I'm beginning to study the numpy.

When I open a terminal (Debian Squeeze) and run the python interpreter
the command "import numpy as np" run without errors.

But when I run the same command on idle3 the following error appears.


 import numpy as np

Traceback (most recent call last):
  File "", line 1, in
import numpy as np
ImportError: No module named numpy

How configure idle to load the numpy module?

Thanks,
Markos

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OpenCV with Python (cv or cv2)

2015-05-26 Thread Markos

Hi,

I want to use OpenCV with Python.

I installed version 2.4.9 
(http://sourceforge.net/projects/opencvlibrary/files/opencv-unix/2.4.9/opencv-2.4.9.zip/) 
in debian Squeeze running Python 2.6.6. Using the tutorial: 
http://indranilsinharoy.com/2012/11/01/installing-opencv-on-linux/


(I tried to install versions 2.4.11 and 2.4.10 (in Squeeze with python 
2.2.6) but I couldn't.)


I lost some time trying to load the module cv2:


>> Import cv2.cv the cv

Traceback (most recent call last):
File "", line 1, in >
ImportError: No module named cv2.cv

After a while I realized I could use the cv module. (import cv)

But still I do not understand the differences between the modules cv and 
cv2.


Do you suggest any good tutorial about the differences between cv and cv2?

I will have to make many changes in python programs using cv to reuse 
the code later with cv2?


Thanks,
Markos
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Re: OpenCV with Python (cv or cv2)

2015-05-27 Thread Markos

Hi Laura,

On 26-05-2015 11:21, Laura Creighton wrote:

In a message of Tue, 26 May 2015 10:24:30 -0300, Markos writes:
   

Hi,

I want to use OpenCV with Python.

I installed version 2.4.9
(http://sourceforge.net/projects/opencvlibrary/files/opencv-unix/2.4.9/opencv-2.4.9.zip/)
in debian Squeeze running Python 2.6.6. Using the tutorial:
http://indranilsinharoy.com/2012/11/01/installing-opencv-on-linux/

(I tried to install versions 2.4.11 and 2.4.10 (in Squeeze with python
2.2.6) but I couldn't.)
 

You mean python 2.6.6, right?
and this package: https://packages.debian.org/source/squeeze/opencv
which is 2.1.0-3 is too old for you?

   


I installed this package (python-opencv) but I thought this package 
would be only some API for python to use the opencv library and I 
imagined that I would still have to install the opencv library from source.



What do you mean that you
tried to install versions 2.4.11 and 2.4.10 but couldn't?  What
error messages did you get?

   

For example when trying to install the 2.4.11 version after running cmake:

cmake -D CMAKE_BUILD_TYPE=RELEASE -D CMAKE_INSTALL_PREFIX=/usr/local -D 
WITH_TBB=ON -D BUILD_NEW_PYTHON_SUPPORT=ON -D WITH_V4L=ON -D 
INSTALL_C_EXAMPLES=ON -D INSTALL_PYTHON_EXAMPLES=ON -D BUILD_EXAMPLES=ON 
-D WITH_QT=ON -D WITH_OPENGL=ON ..


(Output of cmake at the end of message.)

and make -j2 to compile, but an error occurred after compiling 55%:

[ 55%] Building CXX object 
modules/legacy/CMakeFiles/opencv_legacy.dir/src/facedetection.cpp.o

Linking CXX shared library ../../lib/libopencv_legacy.so
[ 55%] Built target opencv_legacy
make: ** [all] Erro 2


I lost some time trying to load the module cv2:

 

Import cv2.cv the cv
   

s/the/as/ ?
   


import cv2.cv as cv




   

Traceback (most recent call last):
File "", line 1, in>
ImportError: No module named cv2.cv

After a while I realized I could use the cv module. (import cv)

But still I do not understand the differences between the modules cv and
cv2.

Do you suggest any good tutorial about the differences between cv and cv2?

I will have to make many changes in python programs using cv to reuse
the code later with cv2?

Thanks,
Markos
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post the output you got from cmake
   


At the end of message.


It will probably complain that it is missing some headers, so couldn't
make libcv2.so

If you haven't installed python-dev (not just python) and numpy I
guarantee it will not find needed headers; if you have but it is
still not being made we will have to look harder at what is going wrong.

   

I installed the following packages:

apt-get install cmake
apt-get install build-essential
apt-get install pkg-config
apt-get install libgtk2.0-dev
apt-get install python-opencv python-dev python-numpy
apt-get install libpng12-0 libpng12-dev libpng++-dev libpng3 libpnglite-dev 
libpngwriter0-dev libpngwriter0c2 zlib1g-dbg
zlib1g zlib1g-dev pngtools libjasper-dev libjasper-runtime libjasper1 libjpeg8 libjpeg8-dbg libjpeg62 libjpeg62-dev 

libjpeg-progs libtiff4-dev libtiff4 libtiffxx0c2 libtiff-tools ffmpeg libavcodec-dev libavcodec52 libavformat52 


libavformat-dev libswscale0 libswscale-dev openexr libopenexr6 libopenexr-dev

apt-get install libgstreamer0.10-0-dbg libgstreamer0.10-0 libgstreamer0.10-dev libgstreamer-plugins-base0.10-dev 

libxine1-ffmpeg libxine-dev libxine1-bin libunicap2 libunicap2-dev libucil2 libucil2-dev libdc1394-22-dev 


libdc1394-22 libdc1394-utils libv4l-0 libv4l-dev
apt-get install libqt4-dev


If it made a libcv.so for you, did it put it in a place you can see
with your PYTHONPATH?

Laura


   

>>> import sys
>>> print sys.path
['', '/usr/lib/python2.6', '/usr/lib/python2.6/plat-linux2', 
'/usr/lib/python2.6/lib-tk', '/usr/lib/python2.6/lib-old', 
'/usr/lib/python2.6/lib-dynload', 
'/usr/local/lib/python2.6/dist-packages', 
'/usr/lib/python2.6/dist-packages', 
'/usr/lib/python2.6/dist-packages/PIL', 
'/usr/lib/python2.6/dist-packages/gst-0.10', 
'/usr/lib/pymodules/python2.6', '/usr/lib/pymodules/python2.6/gtk-2.0', 
'/usr/lib/python2.6/dist-packages/wx-2.8-gtk2-unicode']


import cv works fine but I didn't find libcv.so in my system.

I suppose that cv had already been installed by the package 
python-opencv, and the compilation of the opencv didn't install cv2.


Thanks for your attention,
Markos


Return of cmake
-- Linker flags (Release):
-- Linker flags (Debug):
-- Precompiled headers: YES
--
--   OpenCV modules:
-- To be built: core flann imgproc highgui 
features2d calib3d ml video legacy objdetect photo gpu ocl nonfree 
contrib stitching superres ts videostab

-- Disabled:world
-- Disabled by dependency:  -
-- Unavailable:  

Re: OpenCV with Python (cv or cv2)

2015-05-29 Thread Markos

Hi Laura,

I will follow your advice and install Debian 8.0. I was postponing this 
upgrade. :^)


I just find that Jessie is the new stable release.

According to the tutorial:

http://milq.github.io/install-opencv-ubuntu-debian/

the simplest way to install opencv in jessie is:

apt-get install python-dev libopencv-opencv

And from what I saw the opencv package available in the repository is 2.4.9

https://packages.debian.org/jessie/python-opencv

And from what I saw on the site:

https://packages.debian.org/jessie/python3
and
https://packages.debian.org/jessie/python

There are packages in the repository for python 3.4.2-2 and 2.7.9-1

My doubt is which version of Python (3.4.2-2 or 2.7.9-1) is compatible 
with the opencv library 2.4.9 available in the repository?


Thanks for your attention,
Markos


On 28-05-2015 01:47, Laura Creighton wrote:

Your cmake output doesn't mention that it tried to build libcv.so
so, I guess the reason you cannot find it is that it never tried
to make it.

You may already have fixed your problem by just installing the relevant
debian package.  If not, it may be that you need to install this one
https://packages.debian.org/squeeze/libcv-dev to get libcv.

You have another problem. Squeeze is _very_ old.
According to 
http://stackoverflow.com/questions/5212728/libcxcore-so-2-missing-in-opencv
the opencv project renamed a bunch of libraries, so if at all possible you
should upgrade your debian distribution.  You may have all sorts of
mismatches between the source you just built and the libraries you
need -- which you will only find by trial and error.

Laura

   


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