empty stdout (subprocess.run)
I'm trying to run a shell command but the stdout is empty:
import subprocess
torrentno=8
cmd="/usr/bin/transmission-remote --torrent %s --info", str(torrentno)
res=subprocess.run(cmd, shell=True, check=True, universal_newlines=True,
capture_output=True)
print(res)
CompletedProcess(args=('/usr/bin/transmission-remote --torrent %s --info',
'1'), returncode=0, stdout='', stderr='')
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Re: empty stdout (subprocess.run)
On Wednesday, January 19, 2022 at 11:08:58 PM UTC-5, Dennis Lee Bieber wrote: > Don't you need to provide for that %s? Perhaps > > cmd="/usr/bin/transmission-remote --torrent %s --info" % torrentno That works, thanks. -- https://mail.python.org/mailman/listinfo/python-list
Re: empty stdout (subprocess.run)
On Wednesday, January 19, 2022 at 11:14:28 PM UTC-5, cameron...@gmail.com wrote: > But I recommend you use shell=False and make: > > cmd = ["/usr/bin/transmission-remote", "--torrent", str(torrentno), "--info"] I like that. :-) -- https://mail.python.org/mailman/listinfo/python-list
=+ for strings
I tried:
dt=+"{:02d}".format(day)
but I got:
dt=+"{:02d}".format(day)
TypeError: bad operand type for unary +: 'str'
This works:
dt=dt+"{:02d}".format(day)
Why can't I do the shortcut on strings?
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pickle and then object changes
Say an object like this exists: class test: a = "" b = "" You pickle it. You change the object definition to have a new field: class test a = "" b = "" c = "" You read the pickled object. Will it load but ignore the new field? That is what I want. -- https://mail.python.org/mailman/listinfo/python-list
regex line by line over file
I can't get this to work.
It runs but there is no output when I try it on a file.
#!/usr/bin/python
import os
import sys
import re
from datetime import datetime
#logDir = '/nfs/projects/equinox/platformTools/RTLG/RTLG_logs';
#os.chdir( logDir );
programName = sys.argv[0]
fileName = sys.argv[1]
#pattern = re.compile('\s*\\"SHELF-.*,SC,.*,:\\"Log Collection In Progress\\"')
re.M
p = re.compile('^\s*\"SHELF-.*,SC,.*,:\\\"Log Collection In Progress\\\"')
l = '"SHELF-17:LOG_COLN_IP,SC,03-25,01-18-58,NEND,NA,,,:\"Log Collection In
Progress\",NONE:170035-6364-1048,:YEAR=2014,MODE=NONE"'
# this works :-)
m = p.match( l )
if m:
print( l )
# this doesn't match anything (or the if doesn't work) :-(
with open(fileName) as f:
for line in f:
# debug code (print the line without adding a linefeed)
# sys.stdout.write( line )
if p.match(line):
print(line)
The test file just has one line:
"SHELF-17:LOG_COLN_IP,SC,03-25,01-18-58,NEND,NA,,,:\"Log Collection In
Progress\",NONE:170035-6364-1048,:YEAR=2014,MODE=NONE"
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Re: regex line by line over file
On Wednesday, March 26, 2014 11:23:29 PM UTC-4, James Smith wrote:
> I can't get this to work.
>
> It runs but there is no output when I try it on a file.
>
>
>
>
>
> #!/usr/bin/python
>
>
>
> import os
>
> import sys
>
> import re
>
> from datetime import datetime
>
>
>
> #logDir = '/nfs/projects/equinox/platformTools/RTLG/RTLG_logs';
>
> #os.chdir( logDir );
>
>
>
> programName = sys.argv[0]
>
> fileName = sys.argv[1]
>
>
>
> #pattern = re.compile('\s*\\"SHELF-.*,SC,.*,:\\"Log Collection In
> Progress\\"')
>
> re.M
>
> p = re.compile('^\s*\"SHELF-.*,SC,.*,:\\\"Log Collection In Progress\\\"')
>
> l = '"SHELF-17:LOG_COLN_IP,SC,03-25,01-18-58,NEND,NA,,,:\"Log Collection
> In Progress\",NONE:170035-6364-1048,:YEAR=2014,MODE=NONE"'
>
>
>
> # this works :-)
>
> m = p.match( l )
>
> if m:
>
> print( l )
>
>
>
> # this doesn't match anything (or the if doesn't work) :-(
>
> with open(fileName) as f:
>
> for line in f:
>
> # debug code (print the line without adding a linefeed)
>
> # sys.stdout.write( line )
>
> if p.match(line):
>
> print(line)
>
>
>
>
>
> The test file just has one line:
>
> "SHELF-17:LOG_COLN_IP,SC,03-25,01-18-58,NEND,NA,,,:\"Log Collection In
> Progress\",NONE:170035-6364-1048,:YEAR=2014,MODE=NONE"
I tried the re.M in the compile and that didn't help.
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Re: regex line by line over file
On Thursday, March 27, 2014 1:32:03 AM UTC-4, Steven D'Aprano wrote: > - are you mistaken about the content of the file? > > I can't help you with the first. But the second: try running this: > > # line2 and pat as defined above > filename = sys.argv[1] > with open(filename) as f: > for line in f: > print(len(line), line==line2, repr(line)) > print(repr(pat.match(line))) > > which will show you what you have and whether or not it matches > what you think it has. I expect that the file contents is not what > you think it is, because the regex is matching the sample line. > > Good luck! > > -- > > Steven It should match this: (134, False, '\' "SHELF-17:LOG_COLN_IP,SC,03-25,01-18-58,NEND,NA,,,:"Log Collection In Progress",NONE:170035-6364-1048,:YEAR=2014,MODE=NONE"\\r\\n\'') Is the \r\n on the end of the line screwing it up? -- https://mail.python.org/mailman/listinfo/python-list
Re: regex line by line over file
On Thursday, March 27, 2014 9:41:55 AM UTC-4, James Smith wrote: > (134, False, '\' > "SHELF-17:LOG_COLN_IP,SC,03-25,01-18-58,NEND,NA,,,:"Log Collection In > Progress",NONE:170035-6364-1048,:YEAR=2014,MODE=NONE"\\r\\n\'') > > > > Is the \r\n on the end of the line screwing it up? Got it. I needed an extra \ where I had 3 in the compile. It's kinda weird it didn't need the extra \ when I ran it manually from the shell. -- https://mail.python.org/mailman/listinfo/python-list
help with regex
I want the last "1" I can't this to work: >>> pattern=re.compile( "(\d+)$" ) >>> match=pattern.match( "LINE: 235 : Primary Shelf Number (attempt 1): 1") >>> print match.group() -- https://mail.python.org/mailman/listinfo/python-list
