problem with opening Python IDLE

2006-02-07 Thread Bennie Tilma
I'm having trouble with opening the python IDLE-program. When I try to start 
it, it gives an errormessage wich states that it can not make a connection, 
possibly because of a firewall. However, adding it to firewalls exeptions or 
even disabeling the firewall has no effect.


These are the errors:
1st. 'Socket error: Connection refused', with the name IDLE subprocess Error
2nd. 'IDLE's subprocess didn't make connection. Either IDLE can't start a 
subprocess or personal firewall software is blocking the connection.


The program I am trying to use is included with this message (it's purpose 
is to get a letter from the user and then pick a letter two places forward 
in the line, alphabetical order).


Bennie Tilma
[EMAIL PROTECTED]

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letter = -1
letter_number = 0
message = []
print 'this program converts all letters into two letters forward'
print 'type 0(zero) to stop and show the message'
while letter != 'stop':
   letter = raw_input("type a letter: ")
   if letter == 'a':
   letter_number = 1
   if letter == 'b':
   letter_number = 2
   if letter == 'c':
   letter_number = 3
   if letter == 'd':
   letter_number = 4
   if letter == 'e':
   letter_number = 5
   if letter == 'f':
   letter_number = 6
   if letter == 'g':
   letter_number = 7
   if letter == 'h':
   letter_number = 8
   if letter == 'i':
   letter_number = 9
   if letter == 'j':
   letter_number = 10
   if letter == 'k':
   letter_number = 11
   if letter == 'l':
   letter_number = 12
   if letter == 'm':
   letter_number = 13
   if letter == 'n':
   letter_number = 14
   if letter == 'o':
   letter_number = 15
   if letter == 'p':
   letter_number = 16
   if letter == 'q':
   letter_number = 17
   if letter == 'r':
   letter_number = 18
   if letter == 's':
   letter_number = 19
   if letter == 't':
   letter_number = 20
   if letter == 'u':
   letter_number = 21
   if letter == 'v':
   letter_number = 22
   if letter == 'w':
   letter_number = 23
   if letter == 'x':
   letter_number = 24
   if letter == 'y':
   letter_number = 25
   if letter == 'z':
   letter_number = 26
   if letter == ' ':
   letter_number = 0
alphabet = [' 
','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z','a','b']

print 'the letter is: ', alphabet[letter_number]
message.append(alphabet[letter_number])
print message

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problems opening IDLE

2006-02-09 Thread Bennie Tilma
I'm having trouble with opening the IDLE and running programs. Every time I 
try to open it, it says:
1. Socket error: Connection refused
2. IDLE's subprocess didn't make connection. Either IDLE can't start a 
subprocess or personal firewall software is blocking the connection.

Point is, I allready entered python as an exception to my firewall and when 
I disable it, the messages keep apearing. Can anyone help?

Bennie Tilma

_
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