how to run another file inside current file?
hi, I want to run a another file inside a ached.add_cron_job(..). how is it possible, please help me, I have a file otherFile.py for execution inside current file. I know it is very easy question but i m unable to get anything, please help me. example -- import otherFile from apscheduler.scheduler import Scheduler sched = Scheduler() sched.start() def job_function(): # Can I here add that file for execution, Or can i add that file directly inside cron? sched.add_cron_job(job_function, month='1-12', day='1-31', hour='0-23',minute='44-49') -- http://mail.python.org/mailman/listinfo/python-list
python script is not running
hi,
i want to run python script which generating data into json fromat, I am
using crontab, but it's not executing...
my python code--
try.py --
import json
import simplejson as json
import sys
def tryJson():
saved = sys.stdout
correctFile = file('data.json', 'a+')
sys.stdout = correctFile
result = []
i = 1
for i in range(5):
info = {
'a': i+1,
'b': i+2,
'c': i+3,
}
result.append(info)
if result:
print json.dumps(result, indent=6)
sys.stdout = saved
correctFile.close()
tryJson()
now i m doing ion terminal-
avin@hp:~$ crontab -e
then type -
*/2 * * * * python /home/avin/data/try.py
and save
but it's not executing.
--
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How to run a python script twice randomly in a day?
hi, How to run a python script twice randomly in a day? Actually I want to run my script randomly in a day and twice only. Please help me.. how is it possible. Thanks -- http://mail.python.org/mailman/listinfo/python-list
Re: How to run a python script twice randomly in a day?
Thanks a lot. I got it. On Tue, May 21, 2013 at 6:42 AM, Cameron Simpson wrote: > On 20May2013 15:05, Avnesh Shakya wrote: > | Thanks a lot. > > No worries, but ... > > AGAIN: > - please DO NOT top post. Post below, trimming the quoted material. > - please POST TO THE LIST, not just to me. This is a public discussion. > > Now... > > | I did something. > | I have created test.sh file in which i put- > | > | #!/bin/bash > | cd /home/avin/cronJob > | python try.py > > Ok, good. Some minor remarks: > > Personally, I always use: > > #!/bin/sh > > instead of requiring bash. All UNIX systems have sh, bash is only > common. And even when present, it may not be in /bin. /bin/sh is > always there, and unless you're doing something quite unusual, it > works just fine. > > | then i went on terminal - > | and run crontab -e > | and wrote- > | */2 * * * * bash /home/avin/cronJob/test.sh > | and saved it. > > IIRC, this runs every two minutes. Good for testing, but not your original > spec. > > Also, if you make the shell script (test.sh) executable you do not > need to specify the interpreter. Treat your script like any other > command! So: > > chmod +rx /home/avin/cronJob/test.sh > > and then your cron line can look like this: > > */2 * * * * /home/avin/cronJob/test.sh > > Also, treat your script the same way as your shell script, start > it with a #! like this: > > #!/usr/bin/python > > Make it executable: > > chmod +rx /home/avin/cronJob/try.py > > and then you don't need to say "python" in your shell script: > > ./try.py > > (You need the ./ because the current directory is not in your command > search path ($PATH).) > > | It's working fine. > | but when I m using like > | > | import random > | a = random.randrange(0, 59) > | */a * * * * bash /home/avin/cronJob/test.sh > | then it's showing error becose of varable 'a', so now how can i take > | variable? > > I take it that this is your python program intended to schedule the two > randomly timed runs? > > As a start, it must all be python. The first two lines are. The third line > is > a crontab line. > > So as a start, you need to look more like this: > > #!/usr/bin/python > import random > a = random.randrange(0, 59) > cronline = '*/%d * * * * /home/avin/cronJob/test.sh' % (a,) > print(cronline) > > At least then you can see the cron line you're making. It still > does not add it to a cron job. > > Some remarks: > > - randrange() is like other python ranges: it does not include the end > value. > So your call picks a number from 0..58, not 0..59. > Say randrange(0,60). Think "start, length". > > - My recollection is that you wanted to run a script twice a day at random > times. > Your cron line doesn't do that. > > - If you're picking random run times you want to schedule a once-off > job for each to run at a particular times. Cron schedules repeating > jobs. To run at a particular time you want an "at" job. > > - You need to do one of two things in the pick-a-time script: > - pick a time, then sleep until that time and then directly > invoke the try.py script > or > - pick a time, then use the "at" command to schedule the try.py > (or test.sh) script. > > The first approach would look a bit like this (totally untested): > > #!/usr/bin/python > import random > import subporcess > import time > # choose range time in the next 24 hours > when = random.randrange(0, 24 * 3600) > # sleep that many seconds > time.sleep(when) > subprocess.call(['/home/avin/cronJob/test.sh']) > > For two runs, pick two times. Swap them into order. Sleep twice, > once until the first time and then once until the second time. Etc. > > The second approach (using "at") would not sleep. instead, compute > (using the datetime module) the date and time each job should run, > and invoke "at" using the subprocess module, piping the text > "/home/avin/cronJob/test.sh\n" to it. > > Cheers, > -- > Cameron Simpson > > On a related topic, has anyone looked at doing a clean-room copy of CSS > a la RC2 and RC4 a few years back? I know one or two people have > looked at this in an informal manner, but we couldn't find anyone who > hadn't already seen the DeCSS code to act as the clean person (it says > a lot for the status of their "trade secret" that we couldn't actually > find anyone who didn't already know it). > - Peter Gutmann > -- http://mail.python.org/mailman/listinfo/python-list
how to compare two json file line by line using python?
hi,
how to compare two json file line by line using python? Actually I am doing
it in this way..
import simplejson as json
def compare():
newJsonFile= open('newData.json')
lastJsonFile= open('version1.json')
newLines = newJsonFile.readlines()
print newLines
sortedNew = sorted([repr(x) for x in newJsonFile])
sortedLast = sorted([repr(x) for x in lastJsonFile])
print(sortedNew == sortedLast)
compare()
But I want to compare line by line and value by value. but i found that json
data is unordered data, so how can i compare them without sorting it. please
give me some idea about it. I am new for it.
I want to check every value line by line.
Thanks
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Re: how to compare two json file line by line using python?
Actually, I am extracting data from other site in json format and I want to
put it in my database and when I extract data again then I want to compare
last json file, if these are same then no issue otherwise i will add new
data in database, so here may be every time data can be changed or may be
not so I think sorting is required, but if i compare line by line that will
be good, I am thinking in this way...
On Mon, May 27, 2013 at 10:21 AM, rusi wrote:
> On May 27, 9:32 am, Avnesh Shakya wrote:
> > hi,
> >how to compare two json file line by line using python? Actually I am
> doing it in this way..
> >
> > import simplejson as json
> > def compare():
> > newJsonFile= open('newData.json')
> > lastJsonFile= open('version1.json')
> > newLines = newJsonFile.readlines()
> > print newLines
> > sortedNew = sorted([repr(x) for x in newJsonFile])
> > sortedLast = sorted([repr(x) for x in lastJsonFile])
> > print(sortedNew == sortedLast)
> >
> > compare()
> >
> > But I want to compare line by line and value by value. but i found that
> json data is unordered data, so how can i compare them without sorting it.
> please give me some idea about it. I am new for it.
> > I want to check every value line by line.
> >
> > Thanks
>
> It really depends on what is your notion that the two files are same
> or not.
>
> For example does extra/deleted non-significant white-space matter?
>
> By and large there are two approaches:
> 1. Treat json as serialized python data-structures, (and so) read in
> the data-structures into python and compare there
>
> 2. Ignore the fact that the json file is a json file; just treat it as
> text and use string compare operations
>
> Naturally there could be other considerations: the files could be huge
> and so you might want some hybrid of json and text approaches
> etc etc
> --
> http://mail.python.org/mailman/listinfo/python-list
>
--
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Re: how to compare two json file line by line using python?
Thanks a lot, I got it.
On Mon, May 27, 2013 at 11:03 AM, Steven D'Aprano <
steve+comp.lang.pyt...@pearwood.info> wrote:
> On Sun, 26 May 2013 21:32:40 -0700, Avnesh Shakya wrote:
>
> > But I want to compare line by line and value by value. but i found that
> > json data is unordered data, so how can i compare them without sorting
> > it. please give me some idea about it. I am new for it. I want to check
> > every value line by line.
>
> Why do you care about checking every value line by line? As you say
> yourself, JSON data is unordered, so "line by line" is the wrong way to
> compare it.
>
>
> The right way is to decode the JSON data, and then compare whether it
> gives you the result you expect:
>
> a = json.load("file-a")
> b = json.load("file-b")
> if a == b:
> print("file-a and file-b contain the same JSON data")
>
> If what you care about is the *data* stored in the JSON file, this is the
> correct way to check it.
>
> On the other hand, if you don't care about the data, but you want to
> detect changes to whitespace, blank lines, or other changes that make no
> difference to the JSON data, then there is no need to care that this is
> JSON data. Just treat it as text, and use the difflib library.
>
> http://docs.python.org/2/library/difflib.html
>
>
> --
> Steven
> --
> http://mail.python.org/mailman/listinfo/python-list
>
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How to create new python file with increament number, if doesn't exist?
hi,
I want to create a new python file like 'data0.0.5', but if it is already
exist then it should create 'data0.0.6', if it's also exist then next like
'data0.0.7'. I have done, but with range, please give me suggestion so that I
can do it with specifying range.
I was trying this way and it's working also..
i = 0
for i in range(100):
try:
with open('Data%d.%d.%d.json'%(0,0,i,)): pass
continue
except IOError:
edxCorrectDataFile = file('Data%d.%d.%d.json'%(0,0,i,), 'a+')
break
But here I have defined range 100, Is it possible without range it create many
required files?
Thanks
--
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Re: How to create new python file with increament number, if doesn't exist?
Thanks
On Mon, May 27, 2013 at 4:19 PM, Denis McMahon wrote:
> On Mon, 27 May 2013 02:27:59 -0700, Avnesh Shakya wrote:
>
> > I want to create a new python file like 'data0.0.5', but if it is
> > already exist then it should create 'data0.0.6', if it's also exist
> > then next like 'data0.0.7'. I have done, but with range, please give
> > me suggestion so that I can do it with specifying range.
>
> Try and put your description into the sequence of instructions you want
> the computer follow.
>
> For this problem, my sequence of instructions would be:
>
> 1) Find the highest numbered existing file that matches the filename
> data0.0.[number]
>
> 2) Create a new file that is one number higher.
>
> Now the solution is easy. Find the list of filenames in the directory
> that match a suitable regular expression, take the numeric value of a
> substring of the filename for each file and find the highest, add one to
> it, then create the new file name.
>
> Something like the following (untested) with the relevant imports etc:
>
> nfn="data0.0."+str(max([int(f[8:])for f in os.listdir(p)if re.match
> ('^data0.0.[0-9]+$',f)])+1)
>
> --
> Denis McMahon, denismfmcma...@gmail.com
> --
> http://mail.python.org/mailman/listinfo/python-list
>
--
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Output is not coming with defined color
hi,
I am trying to display my output with different colour on terminal, but it's
coming with that colour code.
Please help me how is it possible?
my code is -
from fabric.colors import green, red, blue
def colorr():
a = red('This is red')
b = green('This is green')
c = blue('This is blue')
d = {a, b, c}
print d
colorr()
output -
set(['\x1b[32mThis is green\x1b[0m', '\x1b[34mThis is blue\x1b[0m',
'\x1b[31mThis is red\x1b[0m'])
Thanks
--
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How to store a variable when a script is executing for next time execution?
hi,
I am running a python script and it will create a file name like
filename0.0.0 and If I run it again then new file will create one more like
filename0.0.1.. my code is-
i = 0
for i in range(1000):
try:
with open('filename%d.%d.%d.json'%(0,0,i,)): pass
continue
except IOError:
dataFile = file('filename%d.%d.%d.json'%(0,0,i,), 'a+')
break
But It will take more time after creating many files, So i want to store value
of last var "i" in a variable so that when i run my script again then I can use
it. for example-
my last created file is filename0.0.27 then it should store 27
in a variable and when i run again then new file should be created 0.0.28
according to last value "27", so that i could save time and it can create file
fast..
Please give me suggestion for it.. How is it possible?
Thanks
--
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Re: How to store a variable when a script is executing for next time execution?
Thanks.
On Thu, Jun 6, 2013 at 4:49 PM, Cameron Simpson wrote:
> On 06Jun2013 03:50, Avnesh Shakya wrote:
> | hi,
> |I am running a python script and it will create a file name like
> filename0.0.0 and If I run it again then new file will create one more like
> filename0.0.1.. my code is-
> |
> | i = 0
> | for i in range(1000):
> | try:
> | with open('filename%d.%d.%d.json'%(0,0,i,)): pass
> | continue
> | except IOError:
> | dataFile = file('filename%d.%d.%d.json'%(0,0,i,), 'a+')
> | break
> | But It will take more time after creating many files, So i want to store
> value of last var "i" in a variable so that when i run my script again then
> I can use it. for example-
> | my last created file is filename0.0.27 then it should
> store 27 in a variable and when i run again then new file should be created
> 0.0.28 according to last value "27", so that i could save time and it can
> create file fast..
> |
> | Please give me suggestion for it.. How is it possible?
>
> Write it to a file? Read the file next time the script runs?
>
> BTW, trying to open zillions of files is slow.
> But using listdir to read the directory you can see all the names.
> Pick the next free one (and then test anyway).
> --
> Cameron Simpson
>
> The mark must be robust enough to survive MP3 transmission over the
> Internet,
> but remain inaudible when played on the yet to be launched DVD-Audio
> players.
> - the SDMI audio watermarkers literally ask for the impossible, since all
> audio compressors aim to pass _only_ human perceptible data
> http://www.newscientist.com/news/news.jsp?id=ns224836
> --
> http://mail.python.org/mailman/listinfo/python-list
>
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how to install indico software?
please tell me someone, how to install indico software? I have link-- http://indico-software.org/wiki/Admin/Installation0.98 but i have problem, i have no sites-available folder inside apache, i m using window 7, please help me.. Thanks in advance -- http://mail.python.org/mailman/listinfo/python-list
trying to open index.py using Indico software......
hi, please help me... I have installed indico software and apache2,when i try to run it using http://indico/index.py,then it's downloading index.py, when i put http://indico, then it's showing all thing properly,but it's not showing index.py but downloading it it's not showing any error, even i have tried error.log.. Please help me, I m unable to get this thing Thanks -- http://mail.python.org/mailman/listinfo/python-list
Warning in python file when i m using pychecker.
hi, I am trying to run my file using pychecker, but it's showing warning. I am unable to get these warning. Please help me, how to remove these warning. I am using pychecker first time. avin@HP:~/github/UdacitySiteData$ pychecker udacity_to_jsonFinal.py Processing module udacity_to_jsonFinal (udacity_to_jsonFinal.py)... Warnings... [system path]/dist-packages/bs4/__init__.py:206: Parameter (successor) not used [system path]/dist-packages/bs4/__init__.py:209: Parameter (successor) not used [system path]/dist-packages/bs4/__init__.py:213: Local variable (tag) not used [system path]/dist-packages/bs4/element.py:306: Parameter (kwargs) not used [system path]/dist-packages/bs4/element.py:507: (id) shadows builtin [system path]/dist-packages/bs4/element.py:791: (next) shadows builtin [system path]/dist-packages/bs4/element.py:903: Invalid arguments to (__repr__), got 2, expected 1 Thanks. -- http://mail.python.org/mailman/listinfo/python-list
