Print function not working

[Atri Mahapatra]

I have installed IDLE 3.5.1 and wrote the following  to check if print is 
working. When it runs, I do not see anything is printed:

class Base: #{
def __init__( self ): #{
print("Hello, world: \n\n");

#}

#}


if ( __name__ == " __main__"): #{
root = Base();
#}

Can anyone please point out the reason?

Thanks,
Atri
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Print function not working

[Atri Mahapatra]

I have installed IDLE 3.5.1 and wrote the following print command to see if it 
is working. When I ran the code nothing is printed. Can you please point the 
reason- anything wrong with the code?



class Base: #{
def __init__( self ): #{
print("Hello, world: \n\n");

#}

#}


if ( __name__ == " __main__"): #{
root = Base();
#}

Thanks,
Atri
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Creating dictionary of items from Excel with mutliple keys

[Atri Mahapatra]

I am trying to create a following dictionary. I am reading data from excel 
which has data in the following format:

Sl no:  Name Thickness Length Material Width Quantity Side 

It has 20 rows of data.


The dictionary for the 20 rows, I would like to make is 

Data_Dict = [ 
{ 'Name': 'X', 'Length': '10' , 'Width': '5', 'Quantity': 2 'Area': 50};
{ 'Name': 'Y', 'Length': '20' , 'Width': 10', 'Quantity': 1 'Area': 200};
.
.
.
.
till 20 rows
];

I would like to add another key 'Area' as shown above. I used the following 
code(s):

using openpyxl:
d={}
for i  in range(3,sheet.max_row+1):
#for j in range(3,9):
#for k in range(0,5):
  Name = sheet.cell(row= i,column=3).value
  Length =sheet.cell(row =i,column=6).value
  Breadth= sheet.cell(row=i,column=7).value
  Quantity = sheet.cell (row=i,column=8).value
  Area = sheet.cell(row 
=i,column=6).value*sheet.cell(row=i,column=7).value
  d[Name]= Length,Breadth,Quantity,Area

which gave an output like: 
['X': (10, 5, 2, 50), 'Y': (20, 10, 1, 2232600), 'Z': (5, 2, 1, 10), 
.]

Another code using xlrd:

keys = [sheet.cell(2, col_index).value for col_index in range(0,8)]
print (keys)
dict_list = []
d = {}
for row_index in range(1, xl_sheet.nrows):
   for col_index in range(0,8):
   d = {keys[col_index]: xl_sheet.cell(row_index, col_index).value 
   for col_index in range(0,8)}
   dict_list.append(d)

print (dict_list)
which did not have the area and neither the output was little messy.



The main purpose is to sort the dictionary based on different criteria like 
Length or Area. I think the first one may be easier to sort. However if there 
are any better way to represent  the dictionary  and the code so that it can be 
sorted later based on different attributes please feel free to suggest. 


Thanks,
Atri 
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Finding the first index in a list greater than a particular value

[Atri Mahapatra]

I have a list of dictionaries which look like this:
[{'Width': 100, 'Length': 20.0, 'Object': 'Object1'}, {'Width': 12.0, 'Length': 
40.0, 'Object': 'Object2'}.. so on till 10] 

I would like to find the first index in the list of dictionaries whose length 
is greater than a particular value

f=lambda seq, m: [ii for ii in range(0, len(seq)) if seq[ii]['Length'] > m][0] 
and it throws an error

can  anyone suggest a way  to do it?

Thanks,
Atri
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Re: Finding the first index in a list greater than a particular value

[Atri Mahapatra]

On Monday, 15 August 2016 00:03:59 UTC+5:30, MRAB  wrote:
> On 2016-08-14 19:17, Atri Mahapatra wrote:
> > I have a list of dictionaries which look like this:
> > [{'Width': 100, 'Length': 20.0, 'Object': 'Object1'}, {'Width': 12.0, 
> > 'Length': 40.0, 'Object': 'Object2'}.. so on till 10]
> >
> > I would like to find the first index in the list of dictionaries whose 
> > length is greater than a particular value
> >
> > f=lambda seq, m: [ii for ii in range(0, len(seq)) if seq[ii]['Length'] > 
> > m][0] and it throws an error
> >
> > can  anyone suggest a way  to do it?
> >
> What is the error?

Traceback (most recent call last):
  File "", line 1, in 
f(lengthlist, 10)
   f=lambda seq, m: [ii for ii in range(0, len(seq)) if seq[ii] > m][0]
TypeError: unorderable types: dict() > int()
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