Re: learning Python
On 10/27/24 16:51, o1bigtenor via Python-list wrote: Greetings There are mountains of books out there. Any suggestions for documents for a just learning how to program and starting with Python (3)? Preference to a tool where I would be learning by doing - - - that works well for me. TIA Frankly, the mountain of resources is so vast that none of us can have experience of more than a small fraction, and effective learning is a factor not only of the quality of the teacher/book/training course, but how it meshes with your own learning style. If you like learn-by-doing, you might take a look at PyBites (https://pybit.es/). But they're by no means the only players in that space! -- https://mail.python.org/mailman/listinfo/python-list
Re: learning Python
On Tue, 29 Oct 2024 16:05:53 -0600, Mats Wichmann wrote: > Frankly, the mountain of resources is so vast that none of us can have > experience of more than a small fraction, and effective learning is a > factor not only of the quality of the teacher/book/training course, but > how it meshes with your own learning style. It isn't a beginners tutorial but at some point 'Python Distilled' is helpful. https://www.dabeaz.com/python-distilled/ Usual disclaimer: i don't know Beazley and am not getting any kickback. -- https://mail.python.org/mailman/listinfo/python-list
Re: Using 'with open(...) as ...' together with configparser.ConfigParser.read
On 2024-10-29, Loris Bennett wrote: > Hi, > > With Python 3.9.18, if I do > > try: > with open(args.config_file, 'r') as config_file: > config = configparser.ConfigParser() > config.read(config_file) > print(config.sections()) > > i.e try to read the configuration with the variable defined via 'with > ... as', I get > >[] > > whereas if I use the file name directly > > try: > with open(args.config_file, 'r') as config_file: > config = configparser.ConfigParser() > config.read(args.config_file) > print(config.sections()) > I get > > ['loggers', 'handlers', 'formatters', 'logger_root', 'handler_fileHandler', > 'handler_consoleHandler', 'formatter_defaultFormatter'] > > which is what I expect. > > If I print type of 'config_file' I get > > > > whereas 'args.config_file' is just > > > > Should I be able to use the '_io.TextIOWrapper' object variable here? If so > how? > > Here > > https://docs.python.org/3.9/library/configparser.html > > there are examples which use the 'with open ... as' variable for writing > a configuration file, but not for reading one. As per the docs you link to, the read() method only takes filename(s) as arguments, if you have an already-open file you want to read then you should use the read_file() method instead. -- https://mail.python.org/mailman/listinfo/python-list
Re: Using 'with open(...) as ...' together with configparser.ConfigParser.read
On 2024-10-29 13:56, Loris Bennett via Python-list wrote: Hi, With Python 3.9.18, if I do try: with open(args.config_file, 'r') as config_file: config = configparser.ConfigParser() config.read(config_file) print(config.sections()) i.e try to read the configuration with the variable defined via 'with ... as', I get [] whereas if I use the file name directly try: with open(args.config_file, 'r') as config_file: config = configparser.ConfigParser() config.read(args.config_file) print(config.sections()) I get ['loggers', 'handlers', 'formatters', 'logger_root', 'handler_fileHandler', 'handler_consoleHandler', 'formatter_defaultFormatter'] which is what I expect. If I print type of 'config_file' I get whereas 'args.config_file' is just Should I be able to use the '_io.TextIOWrapper' object variable here? If so how? Here https://docs.python.org/3.9/library/configparser.html there are examples which use the 'with open ... as' variable for writing a configuration file, but not for reading one. Cheers, Loris 'config.read' expects a path or paths. If you give it a file handle, it treats it as an iterable. (It might be reading the line as paths of files, but I haven't tested it). If you want to read from an open file, use 'config.read_file' instead. -- https://mail.python.org/mailman/listinfo/python-list
Using 'with open(...) as ...' together with configparser.ConfigParser.read
Hi, With Python 3.9.18, if I do try: with open(args.config_file, 'r') as config_file: config = configparser.ConfigParser() config.read(config_file) print(config.sections()) i.e try to read the configuration with the variable defined via 'with ... as', I get [] whereas if I use the file name directly try: with open(args.config_file, 'r') as config_file: config = configparser.ConfigParser() config.read(args.config_file) print(config.sections()) I get ['loggers', 'handlers', 'formatters', 'logger_root', 'handler_fileHandler', 'handler_consoleHandler', 'formatter_defaultFormatter'] which is what I expect. If I print type of 'config_file' I get whereas 'args.config_file' is just Should I be able to use the '_io.TextIOWrapper' object variable here? If so how? Here https://docs.python.org/3.9/library/configparser.html there are examples which use the 'with open ... as' variable for writing a configuration file, but not for reading one. Cheers, Loris -- This signature is currently under constuction. -- https://mail.python.org/mailman/listinfo/python-list
