On 2024-10-12 08:51:57 -0400, Thomas Passin via Python-list wrote:
> On 10/12/2024 6:59 AM, Peter J. Holzer via Python-list wrote:
> > On 2024-10-11 17:13:07 -0400, AVI GROSS via Python-list wrote:
> > > Is there some utility function out there that can be called to show what
> > > the
> > > regular expression you typed in will look like by the time it is ready to
> > > be
> > > used?
> >
> > I assume that by "ready to be used" you mean the compiled form?
> >
> > No, there doesn't seem to be a way to dump that. You can
> >
> > p = re.compile("sout{")
> > print(p.pattern)
> >
> > but that just prints the input string, which you could do without
> > compiling it first.
>
> It prints the escaped version,
Did you mean the *un*escaped version? Well, yeah, that's what print
does.
> so you can see if you escaped the string as you intended. In this
> case, the print will display '\\sout{'.
print("sout{")
will do the same.
It seems to me that for any string s which is a valid regular expression
(i.e. re.compile doesn't throw an exception)
assert re.compile(s).pattern == s
holds.
So it doesn't give you anything you didn't already know.
As a trivial example, the regular expressions r"\\sout{" and r"\\sout\{"
are equivalent (the \ before the { is redundant). Yet
re.compile(s).pattern preserves the difference between the two strings.
hp
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_ | Peter J. Holzer| Story must make more sense than reality.
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| | | h...@hjp.at |-- Charles Stross, "Creative writing
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