[issue44952] list need to filter again because the continue empty str value?

[py_ok]

New submission from py_ok <1979239...@qq.com>:

I`m poor in english.please run my code,Thanks.

def rv(list):
for i in list:
#print(type(i))
#print(i.__len__())
if (i.isspace() or i=='' or len(i)==0):
list.remove(i)
return list
list=['k', '', '', '', 'v', '', 'e', '', '', '', '73', '', 'p', '76', '']
print(rv(list))#['k', 'v', 'e', '73', '', 'p', '76', '']
The result still have empty str,I need to filter again.The reason is more empty 
val is linked.is a bug?or some reason?

--
components: Build
messages: 399882
nosy: py_ok
priority: normal
severity: normal
status: open
title: list need to filter again because the continue empty str value?
type: performance
versions: Python 3.8

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[issue44952] list need to filter again because the continue empty str value?

[py_ok]

py_ok <1979239...@qq.com> added the comment:

Thanks,Very timely resolve my problem

--
stage:  -> resolved
status: open -> closed

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[issue44952] list need to filter again because the continue empty str value?

[py_ok]

py_ok <1979239...@qq.com> added the comment:

Yes,I remember that my error in Java,like you say it`s skiped

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