New submission from giumas:
On Windows, I am getting a `SyntaxError` when I try to input commands after
having launched a Python 2.7.x interpreter with `subprocess.call`.
This is a minimal example:
import os
import subprocess
def python_env_path(python_path):
env = os.environ.copy()
python_scripts = os.path.join(python_path, "Scripts")
python_bin = os.path.join(python_path, "Library", "bin")
path_env = "%s;%s;%s;" % (python_path, python_scripts, python_bin)
env['PATH'] = path_env.encode()
return env
def open_python_prompt(python_path):
env = python_env_path(python_path)
prc = subprocess.call(["start", "python"],
shell=True, cwd=python_path, env=env)
if prc != 0:
print("Unable to open a Python prompt")
return False
return True
open_python_prompt("C:\Py27x64")
When I try to write whatever simple command for the interpreter I get:
>>> a = 0
File "", line 1
a = 0
^
SyntaxError: invalid syntax
I did not find SO questions that solve my issue.
The same code works fine with Python 3.x.
The same Python installation works fine if I open a shell and call the
interpreter using a batch file.
--
components: Extension Modules, Windows
messages: 260612
nosy: giumas, paul.moore, steve.dower, tim.golden, zach.ware
priority: normal
severity: normal
status: open
title: SyntaxError when running Python 2.7 interpreter with subprocess.call
type: crash
versions: Python 2.7
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