[issue42518] Error Message
New submission from Kshitish : print (5 + 2 == 7 and 10 <= 1232 and 100 ^ 1000 >= 128) # Incorrect Output: True This argument should be false but it prints true. This is the logical error vulnerability. Try this code in another language too. You find out they print false because the argument is false but unfortunately Python prints true. Because Python does not understand this. -- components: Windows files: main.py messages: 382216 nosy: blue555, paul.moore, steve.dower, tim.golden, zach.ware priority: normal severity: normal status: open title: Error Message versions: Python 3.8 Added file: https://bugs.python.org/file49640/main.py ___ Python tracker <https://bugs.python.org/issue42518> ___ ___ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
[issue42518] Error Message
Kshitish added the comment: Please do not talk like behave properly. I know here I am wrong but it is not way to talk to some one like that. I respect your knowledge but maintain your language. Okay! I send you new file with full research. Please check it out and thank you -- resolution: not a bug -> status: closed -> open type: behavior -> security Added file: https://bugs.python.org/file49641/main.py ___ Python tracker <https://bugs.python.org/issue42518> ___ ___ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
[issue42518] Error Message
Kshitish added the comment: Look tell why you close this In the argument: print (5 + 2 == 7 and 10 <= 1232 != 10 ^ 100 <= 100) 10 <= 1232 != 10 ^ 100 <= 100 10 <= 1232 is true 10 ^ 100 <= 100 is false These two argument compares by != So, this statement must be true. Overall: print (5 + 2 == 7 and 10 <= 1232 != 10 ^ 100 <= 100) This is the argument is true but is print false. -- resolution: not a bug -> status: closed -> open type: behavior -> ___ Python tracker <https://bugs.python.org/issue42518> ___ ___ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
[issue42570] Try and Except doesn't work properly
New submission from Kshitish : Try & Except doesn't work probably. In the except continue keyword doesn't work probably. -- files: main.py messages: 382515 nosy: blue555 priority: normal severity: normal status: open title: Try and Except doesn't work properly type: behavior versions: Python 3.6, Python 3.7, Python 3.8, Python 3.9 Added file: https://bugs.python.org/file49656/main.py ___ Python tracker <https://bugs.python.org/issue42570> ___ ___ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
[issue42570] Try and Except doesn't work properly
Kshitish added the comment:
for i in range(1,11):
try:
if i == i:
print(i)
if i == 5:
continue
print(i,'poc')
except:
print("Out")
Output:
1
2
3
4
5
6
7
8
9
10
As you can see the continue keyword is not working. The out put should be like
that:
1
2
3
4
6
7
9
10
But it is not and this is the bug because every keyword must work as their
task. if they they not then may be the code will be affected by this
vulnerability.
Thank you
--
status: closed -> open
Added file: https://bugs.python.org/file49657/main.py
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[issue44272] DeprecationWarning: The *random* parameter to shuffle() has been deprecated since Python 3.9 and will be removed in a subsequent version
New submission from Kshitish Kumar : Code: import random as ran x = ran.shuffle(10,random=1) Output: DeprecationWarning: The *random* parameter to shuffle() has been deprecated since Python 3.9 and will be removed in a subsequent version. x = ran.shuffle(10,random=1) File "C:\Users\nisha\AppData\Local\Programs\Python\Python39\lib\random.py", line 369, in shuffle for i in reversed(range(1, len(x))): TypeError: object of type 'int' has no len() -- files: main.py messages: 394792 nosy: Kkshitish priority: normal severity: normal status: open title: DeprecationWarning: The *random* parameter to shuffle() has been deprecated since Python 3.9 and will be removed in a subsequent version versions: Python 3.9 Added file: https://bugs.python.org/file50075/main.py ___ Python tracker <https://bugs.python.org/issue44272> ___ ___ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
[issue44272] DeprecationWarning: The *random* parameter to shuffle() has been deprecated since Python 3.9 and will be removed in a subsequent version
Kshitish Kumar added the comment: I was expecting a proper result from this code. Because If you do same thing in other computer language. You will get a proper answer. -- ___ Python tracker <https://bugs.python.org/issue44272> ___ ___ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
