[issue45456] operator 'pass' in 'if-else' linear expression
New submission from Evgeniy Ivanov : Why operator 'pass' not implement to 'if-else' linear expression? Construction ' if else pass' throws SyntaxError in Python 3.9 -- messages: 403793 nosy: evgnor86 priority: normal severity: normal status: open title: operator 'pass' in 'if-else' linear expression type: compile error versions: Python 3.6, Python 3.7, Python 3.8, Python 3.9 ___ Python tracker <https://bugs.python.org/issue45456> ___ ___ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
[issue45456] operator 'pass' in 'if-else' linear expression
Change by Evgeniy Ivanov : -- resolution: not a bug -> status: closed -> open type: compile error -> ___ Python tracker <https://bugs.python.org/issue45456> ___ ___ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
[issue45456] operator 'pass' in 'if-else' linear expression
Evgeniy Ivanov added the comment: ok, but what you say for this? x += x*2 if math.pow(x) > 386 else pass and if math.pow(x) > 386: x += x*2 1 line vs 2 line now i'm use this x += x*2 if math.pow(x) > 386 else '' -- ___ Python tracker <https://bugs.python.org/issue45456> ___ ___ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
[issue45456] operator 'pass' in 'if-else' linear expression
Evgeniy Ivanov added the comment: it is more readable -- ___ Python tracker <https://bugs.python.org/issue45456> ___ ___ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
[issue45456] operator 'pass' in 'if-else' linear expression
Evgeniy Ivanov added the comment: or another example: def my_func(x): something_do my_func(x) if x > 100 else -- ___ Python tracker <https://bugs.python.org/issue45456> ___ ___ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
[issue45456] operator 'pass' in 'if-else' linear expression
Evgeniy Ivanov added the comment: this wrong example now i'm use this x += x*2 if math.pow(x) > 386 else '' wanted to say that doing this now my_func(x) if x > 100 else '' -- ___ Python tracker <https://bugs.python.org/issue45456> ___ ___ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
[issue45456] operator 'pass' in 'if-else' linear expression
Evgeniy Ivanov added the comment: formaly it's not bug, this is future request ok? -- ___ Python tracker <https://bugs.python.org/issue45456> ___ ___ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
[issue45456] 'pass' in 'if-else' linear expression
Change by Evgeniy Ivanov : -- title: operator 'pass' in 'if-else' linear expression -> 'pass' in 'if-else' linear expression ___ Python tracker <https://bugs.python.org/issue45456> ___ ___ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
[issue45456] operator 'pass' in 'if-else' linear expression
Evgeniy Ivanov added the comment: What about this? if x > 2: my_func(x) ok this code at 1 line, this code work, but... PEP 8: E701 multiple statements on one line (colon) Well f//k it with a pass Why not add an empty action operator? What is the problem? Such an instruction has existed since the days of assembler - nop -- status: closed -> open ___ Python tracker <https://bugs.python.org/issue45456> ___ ___ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
