[jQuery] stop function by mouseOver

2008-12-18 Thread tarnsfor...@googlemail.com

Hello,
i m real desperate about this.

with my function i displayed the content of my 3 DIV elements in a
interval. it works fine.

since a long time im trying to prog a feature wich make a displayStop
by a mouseover. i need this to listen the long content in a div. after
i moved out of the div the function should be run again.

but how?

here is my code:


 http://www.w3.org/1999/xhtml";>



http://code.jquery.com/jquery-latest.js";>
  
  function fadeEngine(x) {
var total_divs=3;
var y=x;
if(x==total_divs) {y=1;}

else {y++; }

$("#fade"+x).css("display","none");
$("#fade"+y).fadeIn("slow");
setTimeout('fadeEngine('+y+')',3000);
  }
fadeEngine(0);
  




Content  one
Content  
two
Content 
three

 



can someone help me please i dont know how to fineshed the code in jQ

thanks a lot


[jQuery] stop by mouseover and run by mouseout

2008-12-18 Thread tarnsfor...@googlemail.com

hi,
i have a function who displayed alternate content from 3 DIVs with a
fadeIn

Now i want to try, that the display rotation stoped if my mousepointer
goes in the DIV but i doesnt work.
 whats my misstake?


 http://www.w3.org/1999/xhtml";>



http://code.jquery.com/jquery-latest.js";>
  
function fadeEngine(x) {
var total_divs=3;
var y=x;
if ( !over ) {
if(x==total_divs) y=1; else y++;
$("#fade"+x).css("display","none");
$("#fade"+y).fadeIn("slow");
$("#container").hover(
function() { over = this.id; },
function() { over = false; });
}
setTimeout('fadeEngine('+y+')',3000);
}
fadeEngine(0);
  



Content  one
Content  
two
Content 
three