Re: %token-table doesn't seem to be working for C++?
On Feb 18, 2019, at 9:59 PM, Akim Demaille wrote:
>
> Hi Derek,
>
>> Le 18 févr. 2019 à 21:07, Derek Clegg a écrit :
>>
>> Perhaps I’m doing something wrong, but it appears that, in C++, %token-table
>> doesn’t work: instead of yytname, I only see yytname_. It also appears that
>> YYNTOKENS, YYNNTS, YYNRULES, and YYNSTATES are not defined, contrary to the
>> documentation. Am I missing something, or is this broken?
>
> Let me answer with a question: what are you trying to achieve?
> What do you need these for?
What I’d actually like to do is get the string name associated with a symbol.
For example, if I had
%token PLUS_ASSIGN "+="
%token MINUS_ASSIGN"-="
...
then I could write something akin to
assignment-expression:
name assignment-op expression
{
std::cout << "Assignment: " << get_name_of_op($2) << "\n";
$$ = build_assignment(get_name_of_op($2), $name, $expression);
}
;
assignment-op: "+=" | "-=" | ... ;
Derek
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Re: %token-table doesn't seem to be working for C++?
Alas, the scanner is allowed to return an integer only. It cannot
return a string.
Anyhow, your sample %token statement declares two tokens, not one; the
last being meaningless.
On 3/2/19 21:13, Derek Clegg wrote:
On Feb 18, 2019, at 9:59 PM, Akim Demaille wrote:
Hi Derek,
Le 18 févr. 2019 à 21:07, Derek Clegg a écrit :
Perhaps I’m doing something wrong, but it appears that, in C++, %token-table
doesn’t work: instead of yytname, I only see yytname_. It also appears that
YYNTOKENS, YYNNTS, YYNRULES, and YYNSTATES are not defined, contrary to the
documentation. Am I missing something, or is this broken?
Let me answer with a question: what are you trying to achieve?
What do you need these for?
What I’d actually like to do is get the string name associated with a symbol.
For example, if I had
%token PLUS_ASSIGN "+="
%token MINUS_ASSIGN"-="
...
then I could write something akin to
assignment-expression:
name assignment-op expression
{
std::cout << "Assignment: " << get_name_of_op($2) << "\n";
$$ = build_assignment(get_name_of_op($2), $name, $expression);
}
;
assignment-op: "+=" | "-=" | ... ;
Derek
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Re: %token-table doesn't seem to be working for C++?
Thanks for your response. I suggest you read through the bison manual,
particularly the section on token type names, in order to better understand my
question.
Derek
> On Mar 2, 2019, at 12:26 PM, John P. Hartmann wrote:
>
> Alas, the scanner is allowed to return an integer only. It cannot return a
> string.
>
> Anyhow, your sample %token statement declares two tokens, not one; the last
> being meaningless.
>
> On 3/2/19 21:13, Derek Clegg wrote:
>> On Feb 18, 2019, at 9:59 PM, Akim Demaille wrote:
>>>
>>> Hi Derek,
>>>
Le 18 févr. 2019 à 21:07, Derek Clegg a écrit :
Perhaps I’m doing something wrong, but it appears that, in C++,
%token-table doesn’t work: instead of yytname, I only see yytname_. It
also appears that YYNTOKENS, YYNNTS, YYNRULES, and YYNSTATES are not
defined, contrary to the documentation. Am I missing something, or is this
broken?
>>>
>>> Let me answer with a question: what are you trying to achieve?
>>> What do you need these for?
>> What I’d actually like to do is get the string name associated with a symbol.
>> For example, if I had
>> %token PLUS_ASSIGN "+="
>> %token MINUS_ASSIGN"-="
>> ...
>> then I could write something akin to
>> assignment-expression:
>> name assignment-op expression
>> {
>> std::cout << "Assignment: " << get_name_of_op($2) << "\n";
>> $$ = build_assignment(get_name_of_op($2), $name, $expression);
>> }
>> ;
>> assignment-op: "+=" | "-=" | ... ;
>> Derek
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>
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