import error
Occured error while using url http://localhost/fllyp/
MOD_PYTHON ERROR
ProcessId: 844
Interpreter:'192.168.1.116'
ServerName: '192.168.1.116'
DocumentRoot: 'C:/Program Files/Apache Software Foundation/Apache2.2/
htdocs'
URI:'/fllyp/'
Location: '/fllyp/'
Directory: None
Filename: 'C:/Program Files/Apache Software Foundation/Apache2.2/
htdocs/fllyp/'
PathInfo: ''
Phase: 'PythonHandler'
Handler:'django.core.handlers.modpython'
Traceback (most recent call last):
File "C:\Python25\Lib\site-packages\mod_python\importer.py", line
1537, in HandlerDispatch
default=default_handler, arg=req, silent=hlist.silent)
File "C:\Python25\Lib\site-packages\mod_python\importer.py", line
1229, in _process_target
result = _execute_target(config, req, object, arg)
File "C:\Python25\Lib\site-packages\mod_python\importer.py", line
1128, in _execute_target
result = object(arg)
File "C:\Python25\Lib\site-packages\django\core\handlers
\modpython.py", line 228, in handler
return ModPythonHandler()(req)
File "C:\Python25\Lib\site-packages\django\core\handlers
\modpython.py", line 191, in __call__
self.load_middleware()
File "C:\Python25\Lib\site-packages\django\core\handlers\base.py",
line 33, in load_middleware
for middleware_path in settings.MIDDLEWARE_CLASSES:
File "C:\Python25\Lib\site-packages\django\utils\functional.py",
line 276, in __getattr__
self._setup()
File "C:\Python25\Lib\site-packages\django\conf\__init__.py", line
40, in _setup
self._wrapped = Settings(settings_module)
File "C:\Python25\Lib\site-packages\django\conf\__init__.py", line
75, in __init__
raise ImportError("Could not import settings '%s' (Is it on
sys.path? Does it have syntax errors?): %s" % (self.SETTINGS_MODULE,
e))
ImportError: Could not import settings 'settings.py' (Is it on
sys.path? Does it have syntax errors?): No module named
settings.py-
To configure Django with mod_python I added this in httpd.conf file
SetHandler python-program
PythonHandler django.core.handlers.modpython
SetEnv DJANGO_SETTINGS_MODULE settings.py
PythonOption django.root /mysite
PythonDebug On
PythonPath "['C:/mysite'] + sys.path"
what shoul i do now pls help me my project file is in C drive at this
location only i am not having file at C:/Program Files/Apache2.2/
htdocs/mysite'
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Re: question about django url
http://local host/wap/di/sub?word=check&type=00&submit=Submit i want to print word "check" and any word given in url pls give sugesstion pls -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re:
HI
THIS IS MY REQUIRED URL
http://localhost/flip/wap/di/sub?word=check&type=00&submit=Submit
here check should be displayed in my page we are using this for
dictionary but my task is to just display that word check in my page
, moreover its user defined
my urls.py is looking like this
urlpatterns = patterns('',
(r"^wap/di/sub",current_datetime),
And my view looks like this
from django.http import HttpResponse
def current_datetime(request):
word = request.GET['word']
return HttpResponse(word)
but it still showing Error
Exception Value:
unindent does not match any outer indentation level (view.py, line 7)
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[no subject]
my re reuested url is
http://localhost/wap/di/sub?word=check&type=00&submit=Submit
I want to print the word "CHECK" which will be given by user
my urls.py looks like this
from django.conf.urls.defaults import *
from flip.view import current_datetime
urlpatterns = patterns('',
(r"^wap/di/sub?word=(\w+)&type=00&submit=Submit",current_datetime),
)
My view.py look like this
from django.http import HttpResponse
def current_datetime(request):
html = "" + word + ""
return HttpResponse(html)
But the error shown is
SyntaxError: 'return' outside function
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Re:
HI Jirka Vejrazka sorry ya i am very new to this group and i am going through the python But it would be helpful to me if u convey me which part of python should i go throgh for time beingthank u -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re:
Sir, i got two way of suggestion s now i am bitter confused waht should i use now,now i will clearly tell my requirement http://m.broov.com/wap/di/sub?word=check&type=00&submit=Submit pls visit this site and replace the word check with any word u like it will display some rsults below now i don't want that results to be printed below i want only that word should be printed i got two suggestionfrom django users 1. So, your urls.py would look like this: (r"^wap/di/sub", hellow) And your view would contain the following code: def hellow(request): word = request.GET['word'] return HttpResponse(word) --- 2.So url looks like this (r"^wap/di/sub?word=(\w+)&type=00&submit=Submit",hellow), view look like this html = "" + word + "" which is the best to use but both getting error -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re:
THANK U GUYS AT LAST I GOT WHAT I NEED AND ITS WORKING THANK U FOR U R RESPONSE GREAT YA THANKS!!! -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re:
ISORRY YA AGAIN i got problem of
SyntaxError: 'return' outside function
now my view code
from django.http import HttpResponse
def current_datetime(request):
word = request.GET['word']
return HttpResponse(word)
now my url code
from django.conf.urls.defaults import *
from flip.view import current_datetime
# Uncomment the next two lines to enable the admin:
# from django.contrib import admin
# admin.autodiscover()
urlpatterns = patterns('',
# Example:
(r"^wap/di/sub",current_datetime)
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Re:
just before getting u r message i tried that it worked!! whats the best editor for django -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
WANT TO SEND REQ TO URL GET RESPONSE FROM THE SAME URL
i want to send my req from my url that
is"http://localhost/flip/wap/di/sub?word=formula&type=00&submit=Submit";
that i want to send only the word "formula" to the url
"http://m.broov.com/wap/di/sub?word=fomula&type=00&submit=Submit"and i
want to get response from the same url and display in my page
my view looks like this
from django.http import *
from django.template import loader, Context
def current_datetime(request):
word = request.GET['word']
message=HttpResponse('http://m.broov.com/wap/di/sub?word='+word+'&submit=Submit')
return HttpResponse(message)
MY url looks like this
from django.conf.urls.defaults import *
from flip.view import current_datetime
urlpatterns = patterns('',
:
(r"^wap/di/sub",current_datetime)
I AM GETTING RESPONSE HAS THE SAME URL IN MY DISPLAY PAGE
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Fwd: WANT TO SEND REQ TO URL GET RESPONSE FROM THE SAME URL
-- Forwarded message --
From: sami nathan
Date: Tue, Oct 12, 2010 at 3:37 PM
Subject: WANT TO SEND REQ TO URL GET RESPONSE FROM THE SAME URL
To: django-users@googlegroups.com
i want to send my req from my url that
is"http://localhost/flip/wap/di/sub?word=formula&type=00&submit=Submit";
that i want to send only the word "formula" to the url
"http://m.broov.com/wap/di/sub?word=fomula&type=00&submit=Submit"and i
want to get response from the same url and display in my page
my view looks like this
from django.http import *
from django.template import loader, Context
def current_datetime(request):
word = request.GET['word']
message=HttpResponse('http://m.broov.com/wap/di/sub?word='+word+'&submit=Submit')
return HttpResponse(message)
MY url looks like this
from django.conf.urls.defaults import *
from flip.view import current_datetime
urlpatterns = patterns('',
:
(r"^wap/di/sub",current_datetime)
I AM GETTING RESPONSE HAS THE URL IN MY DISPLAY PAGE
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Re: WANT TO SEND REQ TO URL GET RESPONSE FROM THE SAME URL
Hello sir,
I need to display the reult of
"http://m.broov.com/wap/di/sub?word=dog&type=00&submit=Submit";
in my url which is
http://localhost/flip/wap/di/sub?word=dog&type=00&submit=Submit
My view looks like this
from django.http import *
from django.template import loader, Context
from django.shortcuts import render_to_response
def current_datetime(request):
word = request.GET['word']
url=HttpResponse('http://m.broov.com/wap/di/sub?word='+word+"type=00submit=Submit')
return (url)
i want response from this site to be displayed not url of the site
i want to only return the response from this site but i am getting oly
url of this site displayed
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Re: WANT TO SEND REQ TO URL GET RESPONSE FROM THE SAME URL
Hello sir,
I need to display the reult of
"http://m.broov.com/wap/di/sub?word=dog&type=00&submit=Submit";
in my url which is
http://localhost/flip/wap/di/sub?word=dog&type=00&submit=Submit
My view looks like this
from django.http import *
from django.template import loader, Context
from django.shortcuts import render_to_response
def current_datetime(request):
word = request.GET['word']
url=HttpResponse('http://m.broov.com/wap/di/sub?word='+word+"type=00submit=Submit')
return (url)
i want response from this site to be displayed not url of the site
i want to only return the response from this site but i am getting oly
url of this site displayed
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how can i wsdl file in my django
After completing my project i need to use wsdl file for web service how could i use it any sugesstions -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: how can i wsdl file in my django
Can i use RESTfull insted of SOAP service -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: how can i wsdl file in my django
I think following is opt ans for my question Mr Brian Bouterse No matter the tools you have, it's hard to make a WSDL for a RESTful service. WSDL 1.1, after all, was specifically designed to describe services built using SOAP. In response, the Web Application Development Language (WADL) was created to easily describe RESTful services. But WSDL 2.0 is more compatible with both SOAP and REST and, with its W3C recommendation, competes stiffly with WADL for popularity among developers. -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
interface django and rest
Please Suggest me an tutorial for interfacing django and restfuli thanks -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: interface django and rest
But is telling about piston is i am very beginner of django i want to inerface django and RESTFULL service and i am also blinking with what to do with my wsdl file Please help by THANKS -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
django erest interfac
hi for django restfull interface i am using the link given below is it correct i am experiencing error in that steps http://code.google.com/p/django-restful-model-views/ please visit this and tell me -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
ATTRIBUTE ERROR
My occured Error is
Exception Value:
'str' object has no attribute 'resolve'
Exception Location:
C:\Python25\Lib\site-packages\django\core\urlresolvers.py in resolve,
line 217
~
MY URLS.PY LOOKS LIKE THIS
from django.conf.urls.defaults import *
from flip.view import current_datetime
urlpatterns = ('',
# Example:
(r"^wap/di/sub",current_datetime)
)
# Uncomment the admin/doc line below to enable admin documentation:
# (r'^admin/doc/', include('django.contrib.admindocs.urls')),
# Uncomment the next line to enable the admin:
# (r'^admin/', include(admin.site.urls))
My view .py Looks like this
from django.http import *
import urllib
def current_datetime(request):
word = request.GET['word']
message =
urllib.urlopen('http://m.broov.com/wap/di/sub?word='+word+'&type=00submit=Submit',)
return HttpResponse (message)
Please help me i dont na what happens it was running succesfully but
noow its not
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'str' object has no attribute 'resolve' Exception Location: C:\Python25\Lib\site-packages\django\core\urlresolvers.py in resolve,
-- Forwarded message --
From: sami nathan
Date: Thu, Oct 28, 2010 at 3:41 PM
Subject: ATTRIBUTE ERROR
To: django-users@googlegroups.com
My occured Error is
Exception Value:
'str' object has no attribute 'resolve'
Exception Location:
C:\Python25\Lib\site-packages\django\core\urlresolvers.py in resolve,
line 217
~
MY URLS.PY LOOKS LIKE THIS
from django.conf.urls.defaults import *
from flip.view import current_datetime
urlpatterns = ('',
# Example:
(r"^wap/di/sub",current_datetime)
)
# Uncomment the admin/doc line below to enable admin documentation:
# (r'^admin/doc/', include('django.contrib.admindocs.urls')),
# Uncomment the next line to enable the admin:
# (r'^admin/', include(admin.site.urls))
My view .py Looks like this
from django.http import *
import urllib
def current_datetime(request):
word = request.GET['word']
message =
urllib.urlopen('http://m.broov.com/wap/di/sub?word='+word+'&type=00submit=Submit',)
return HttpResponse (message)
Please help me i dont na what happens it was running succesfully but
noow its not
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can't open file 'django-admin.py': [Errno 2] No such file or directory'.
Whenever I try to execute a python script that is located in the /usr/local/bin, python gives me the error 'python: can't open file 'django-admin.py': [Errno 2] No such file or directory'. -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
cannot setup database
When i run the command python manage.py syncdb i got the follwing error
self.connection = Database.connect(**kwargs)
sqlite3.OperationalError: unable to open database file
Exception exceptions.AttributeError: '_shutdown' in ignoredDATABASES = {
'default': {
'ENGINE': 'django.db.backends.sqlite3', # Add
'postgresql_psycopg2', 'postgresql', 'mysql',
MY DB SETUP LOOKS LIKE THIS
'default': {
'ENGINE': 'django.db.backends.sqlite3', # Add
'postgresql_psycopg2', 'postgresql', 'mysql',
'sqlite3' or 'oracle'.
'NAME':
'D:\Python25\Lib\site-packages\django\bin\flyp\sqlite3',
# Or
path to database file if using sqlite3.
'USER': '', # Not used with sqlite3.
'PASSWORD': '', # Not used with sqlite3.
'HOST': '', # Set to empty string for
localhost. Not used with sqlite3.
'PORT': '', # Set to empty string for
default. Not used with sqlite3.
}
}
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Re: cannot setup database
My setting file looks like this
# Django settings for flyp project.
DEBUG = True
TEMPLATE_DEBUG = DEBUG
ADMINS = (
# ('Your Name', 'your_em...@domain.com'),
)
MANAGERS = ADMINS
DATABASES = {
'default': {
'ENGINE': 'django.db.backends.sqlite3', # Add
'postgresql_psycopg2', 'postgresql', 'mysql', 'sqlite3' or 'oracle'.
'NAME':
'D:\Python25\Lib\site-packages\django\bin\flyp\sqlite3.db',
# Or path to database file if using sqlite3.
'USER': '', # Not used with sqlite3.
'PASSWORD': '', # Not used with sqlite3.
'HOST': '', # Set to empty string for
localhost. Not used with sqlite3.
'PORT': '', # Set to empty string for
default. Not used with sqlite3.
}
}
# Local time zone for this installation. Choices can be found here:
# http://en.wikipedia.org/wiki/List_of_tz_zones_by_name
# although not all choices may be available on all operating systems.
# On Unix systems, a value of None will cause Django to use the same
# timezone as the operating system.
# If running in a Windows environment this must be set to the same as your
# system time zone.
TIME_ZONE = 'America/Chicago'
# Language code for this installation. All choices can be found here:
# http://www.i18nguy.com/unicode/language-identifiers.html
LANGUAGE_CODE = 'en-us'
SITE_ID = 1
# If you set this to False, Django will make some optimizations so as not
# to load the internationalization machinery.
USE_I18N = True
# If you set this to False, Django will not format dates, numbers and
# calendars according to the current locale
USE_L10N = True
# Absolute path to the directory that holds media.
# Example: "/home/media/media.lawrence.com/media/"
MEDIA_ROOT = ''
# URL that handles the media served from MEDIA_ROOT. Make sure to use a
# trailing slash if there is a path component (optional in other cases).
# Examples: "http://media.lawrence.com";, "http://example.com/media/";
MEDIA_URL = ''
# Absolute path to the directory that holds media.
# Example: "/home/media/media.lawrence.com/static/"
STATICFILES_ROOT = ''
# URL that handles the static files served from STATICFILES_ROOT.
# Example: "http://static.lawrence.com/";, "http://example.com/static/";
STATICFILES_URL = '/static/'
# URL prefix for admin media -- CSS, JavaScript and images.
# Make sure to use a trailing slash.
# Examples: "http://foo.com/static/admin/";, "/static/admin/".
ADMIN_MEDIA_PREFIX = '/static/admin/'
# A list of locations of additional static files
STATICFILES_DIRS = ()
# List of finder classes that know how to find static files in
# various locations.
STATICFILES_FINDERS = (
'django.contrib.staticfiles.finders.FileSystemFinder',
'django.contrib.staticfiles.finders.AppDirectoriesFinder',
#'django.contrib.staticfiles.finders.DefaultStorageFinder',
)
# Make this unique, and don't share it with anybody.
SECRET_KEY = 'ky7bf$^vv$$-#vjx4ha%j&e!d#$g=7w2...@i-^9g#ai9fa8*^'
# List of callables that know how to import templates from various sources.
TEMPLATE_LOADERS = (
'django.template.loaders.filesystem.Loader',
'django.template.loaders.app_directories.Loader',
# 'django.template.loaders.eggs.Loader',
)
MIDDLEWARE_CLASSES = (
'django.middleware.common.CommonMiddleware',
'django.contrib.sessions.middleware.SessionMiddleware',
'django.middleware.csrf.CsrfViewMiddleware',
'django.contrib.auth.middleware.AuthenticationMiddleware',
'django.contrib.messages.middleware.MessageMiddleware',
)
ROOT_URLCONF = 'flyp.urls'
TEMPLATE_DIRS = (
# Put strings here, like "/home/html/django_templates" or
"C:/www/django/templates".
# Always use forward slashes, even on Windows.
# Don't forget to use absolute paths, not relative paths.
)
INSTALLED_APPS = (
'django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.sessions',
'django.contrib.sites',
'django.contrib.messages',
'django.contrib.staticfiles',
'django.contrib.admin'
# Uncomment the next line to enable the admin:
# 'django.contrib.admin',
# Uncomment the next line to enable admin documentation:
# 'django.contrib.admindocs',
)
# A sample logging configuration. The only tangible logging
# performed by this configuration is to send an email to
# the site admins on every HTTP 500 error.
# See http://docs.djangoproject.com/en/dev/topics/logging for
# more details on how to customize your logging configuration.
LOGGING = {
'version': 1,
'disable_existing_loggers': False,
'handlers': {
'mail_admins': {
'level': 'ERROR',
'class': 'django.utils.log.AdminEmailHandler'
}
},
'loggers': {
'django.request':{
'handlers': ['mail_admins'],
'level': 'ERROR',
'propagate': True,
},
}
}
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To post
ImportError: Could not import settings 'flyp.settings' (Is it on sys.path? Does it have syntax errors?): No module named flyp.settings
MY system path is
D:\Python25\Lib\site-packages\django\bin\admin.py;D:\Python25;D:\Program
Files\Subversion\bin:D:\Python25\Lib\site-packages\django;D:\Python25\Lib\site-packages\django\bin\flyp;D:\Python25\Tools;D:\Python25\Lib\site-packages\django\bin\flyp\settings;
my LOCATION looks like this
SetHandler python-program
PythonHandler django.core.handlers.modpython
SetEnv DJANGO_SETTINGS_MODULE flyp.settings
PythonOption django.root /flyp
PythonDebug On
PythonPath
"['D:/Python25','D:/Python25/Lib/site-packages/django/bin/flyp','D:/Python25/Lib/site-packages/django/bin/flyp/settings',]
+ sys.path"
i AM GETTING FOLLOWING ERROR
MOD_PYTHON ERROR
ProcessId: 3908
Interpreter:'192.168.1.116'
ServerName: '192.168.1.116'
DocumentRoot: 'C:/Program Files/Apache Software Foundation/Apache2.2/htdocs'
URI:'/flyp/'
Location: '/flyp/'
Directory: None
Filename: 'C:/Program Files/Apache Software
Foundation/Apache2.2/htdocs/flyp/'
PathInfo: ''
Phase: 'PythonHandler'
Handler:'django.core.handlers.modpython'
Traceback (most recent call last):
File "D:\Python25\Lib\site-packages\mod_python\importer.py", line
1537, in HandlerDispatch
default=default_handler, arg=req, silent=hlist.silent)
File "D:\Python25\Lib\site-packages\mod_python\importer.py", line
1229, in _process_target
result = _execute_target(config, req, object, arg)
File "D:\Python25\Lib\site-packages\mod_python\importer.py", line
1128, in _execute_target
result = object(arg)
File "D:\Python25\lib\site-packages\django\core\handlers\modpython.py",
line 213, in handler
return ModPythonHandler()(req)
File "D:\Python25\lib\site-packages\django\core\handlers\modpython.py",
line 174, in __call__
self.load_middleware()
File "D:\Python25\lib\site-packages\django\core\handlers\base.py",
line 37, in load_middleware
for middleware_path in settings.MIDDLEWARE_CLASSES:
File "D:\Python25\lib\site-packages\django\utils\functional.py",
line 276, in __getattr__
self._setup()
File "D:\Python25\lib\site-packages\django\conf\__init__.py", line
41, in _setup
self._wrapped = Settings(settings_module)
File "D:\Python25\lib\site-packages\django\conf\__init__.py", line
76, in __init__
raise ImportError("Could not import settings '%s' (Is it on
sys.path? Does it have syntax errors?): %s" % (self.SETTINGS_MODULE,
e))
ImportError: Could not import settings 'flyp.settings' (Is it on
sys.path? Does it have syntax errors?): No module named flyp.settings
AND ALSO GETTING THIS ERROR WHILE CREATING DATABASE
Exception exceptions.AttributeError: '_shutdown' in ignored
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Fwd: ImportError: Could not import settings 'flyp.settings' (Is it on sys.path? Does it have syntax errors?): No module named flyp.settings
-- Forwarded message --
From: sami nathan
Date: Mon, Nov 1, 2010 at 6:42 PM
Subject: ImportError: Could not import settings 'flyp.settings' (Is it
on sys.path? Does it have syntax errors?): No module named
flyp.settings
To: django-users@googlegroups.com
MY system path is
D:\Python25\Lib\site-packages\django\bin\admin.py;D:\Python25;D:\Program
Files\Subversion\bin:D:\Python25\Lib\site-packages\django;D:\Python25\Lib\site-packages\django\bin\flyp;D:\Python25\Tools;D:\Python25\Lib\site-packages\django\bin\flyp\settings;
my LOCATION looks like this
SetHandler python-program
PythonHandler django.core.handlers.modpython
SetEnv DJANGO_SETTINGS_MODULE flyp.settings
PythonOption django.root /flyp
PythonDebug On
PythonPath
"['D:/Python25','D:/Python25/Lib/site-packages/django/bin/flyp','D:/Python25/Lib/site-packages/django/bin/flyp/settings',]
+ sys.path"
i AM GETTING FOLLOWING ERROR
MOD_PYTHON ERROR
ProcessId: 3908
Interpreter: '192.168.1.116'
ServerName: '192.168.1.116'
DocumentRoot: 'C:/Program Files/Apache Software Foundation/Apache2.2/htdocs'
URI: '/flyp/'
Location: '/flyp/'
Directory: None
Filename: 'C:/Program Files/Apache Software
Foundation/Apache2.2/htdocs/flyp/'
PathInfo: ''
Phase: 'PythonHandler'
Handler: 'django.core.handlers.modpython'
Traceback (most recent call last):
File "D:\Python25\Lib\site-packages\mod_python\importer.py", line
1537, in HandlerDispatch
default=default_handler, arg=req, silent=hlist.silent)
File "D:\Python25\Lib\site-packages\mod_python\importer.py", line
1229, in _process_target
result = _execute_target(config, req, object, arg)
File "D:\Python25\Lib\site-packages\mod_python\importer.py", line
1128, in _execute_target
result = object(arg)
File "D:\Python25\lib\site-packages\django\core\handlers\modpython.py",
line 213, in handler
return ModPythonHandler()(req)
File "D:\Python25\lib\site-packages\django\core\handlers\modpython.py",
line 174, in __call__
self.load_middleware()
File "D:\Python25\lib\site-packages\django\core\handlers\base.py",
line 37, in load_middleware
for middleware_path in settings.MIDDLEWARE_CLASSES:
File "D:\Python25\lib\site-packages\django\utils\functional.py",
line 276, in __getattr__
self._setup()
File "D:\Python25\lib\site-packages\django\conf\__init__.py", line
41, in _setup
self._wrapped = Settings(settings_module)
File "D:\Python25\lib\site-packages\django\conf\__init__.py", line
76, in __init__
raise ImportError("Could not import settings '%s' (Is it on
sys.path? Does it have syntax errors?): %s" % (self.SETTINGS_MODULE,
e))
ImportError: Could not import settings 'flyp.settings' (Is it on
sys.path? Does it have syntax errors?): No module named flyp.settings
AND ALSO GETTING THIS ERROR WHILE CREATING DATABASE
Exception exceptions.AttributeError: '_shutdown' in ignored
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ImportError: Could not import settings 'flyp.settings' (Is it on sys.path? Does it have syntax errors?): No module named flyp.settings
MY system path is
D:\Python25\Lib\site-packages\django\bin\admin.py;D:\Python25;D:\Program
Files\Subversion\bin:D:\Python25\Lib\site-packages\django;D:\Python25\Lib\site-packages\django\bin\flyp;D:\Python25\Tools;D:\Python25\Lib\site-packages\django\bin\flyp\settings;
my LOCATION looks like this
SetHandler python-program
PythonHandler django.core.handlers.modpython
SetEnv DJANGO_SETTINGS_MODULE flyp.settings
PythonOption django.root /flyp
PythonDebug On
PythonPath
"['D:/Python25','D:/Python25/Lib/site-packages/django/bin/flyp','D:/Python25/Lib/site-packages/django/bin/flyp/settings',]
+ sys.path"
i AM GETTING FOLLOWING ERROR
MOD_PYTHON ERROR
ProcessId: 3908
Interpreter:'192.168.1.116'
ServerName: '192.168.1.116'
DocumentRoot: 'C:/Program Files/Apache Software Foundation/Apache2.2/htdocs'
URI:'/flyp/'
Location: '/flyp/'
Directory: None
Filename: 'C:/Program Files/Apache Software
Foundation/Apache2.2/htdocs/flyp/'
PathInfo: ''
Phase: 'PythonHandler'
Handler:'django.core.handlers.modpython'
Traceback (most recent call last):
File "D:\Python25\Lib\site-packages\mod_python\importer.py", line
1537, in HandlerDispatch
default=default_handler, arg=req, silent=hlist.silent)
File "D:\Python25\Lib\site-packages\mod_python\importer.py", line
1229, in _process_target
result = _execute_target(config, req, object, arg)
File "D:\Python25\Lib\site-packages\mod_python\importer.py", line
1128, in _execute_target
result = object(arg)
File "D:\Python25\lib\site-packages\django\core\handlers\modpython.py",
line 213, in handler
return ModPythonHandler()(req)
File "D:\Python25\lib\site-packages\django\core\handlers\modpython.py",
line 174, in __call__
self.load_middleware()
File "D:\Python25\lib\site-packages\django\core\handlers\base.py",
line 37, in load_middleware
for middleware_path in settings.MIDDLEWARE_CLASSES:
File "D:\Python25\lib\site-packages\django\utils\functional.py",
line 276, in __getattr__
self._setup()
File "D:\Python25\lib\site-packages\django\conf\__init__.py", line
41, in _setup
self._wrapped = Settings(settings_module)
File "D:\Python25\lib\site-packages\django\conf\__init__.py", line
76, in __init__
raise ImportError("Could not import settings '%s' (Is it on
sys.path? Does it have syntax errors?): %s" % (self.SETTINGS_MODULE,
e))
ImportError: Could not import settings 'flyp.settings' (Is it on
sys.path? Does it have syntax errors?): No module named flyp.settings
AND ALSO GETTING THIS ERROR WHILE CREATING DATABASE
Exception exceptions.AttributeError: '_shutdown' in ignored
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ATTRIBUTE ERROR
If i am doing anything wrong forgive me i am newbe
MY error is
Exception Type: AttributeError
Exception Value:
'str' object has no attribute 'resolve'
Exception Location:
D:\Python25\lib\site-packages\django\core\urlresolvers.py in resolve,
line 25
My url.py look like this
from django.conf.urls.defaults import *
from it.view import current_datetime
# Uncomment the next two lines to enable the admin:
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
# Example:
(r'^wap/di/sub/$",current_datetime')
# Uncomment the admin/doc line below to enable admin documentation:
# (r'^admin/doc/', include('django.contrib.admindocs.urls')),
# Uncomment the next line to enable the admin:
# (r'^admin/', include(admin.site.urls)),
)
~~~
My view.py looks like this
from django.http import *
import urllib
def current_datetime(request):
word = request.GET['word']
message =
urllib.urlopen('http://m.broov.com/wap/di/sub?word='+word+'&type=00submit=Submit',)
return HttpResponse (message)
~~
Thank u for notification
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Attributr error
THIS IS HOW MY URL.PY LOOKS LIKE
from django.conf.urls.defaults import *
from it.view import current_datetime
# Uncomment the next two lines to enable the admin:
#from django.contrib import admin
#admin.autodiscover()
urlpatterns = patterns('',
# Example:
(r"^wap/di/sub/$",current_datetime),
# Uncomment the admin/doc line below to enable admin documentation:
# (r'^admin/doc/', include('django.contrib.admindocs.urls')),
# Uncomment the next line to enable the admin:
# (r'^admin/', include(admin.site.urls)),
)
`~~~
My view .py looks like this
from django.http import *
import urllib
from django_restapi.responder import XMLResponder
def current_datetime(request):
word = request.GET['word']
message =
urllib.urlopen('http://m.broov.com/wap/di/sub?word='+word+'&type=00submit=Submit',)
return XMLResponder(message)
But my error is
Exception Value:
'XMLResponder' object has no attribute 'status_code'
Exception Location:
D:\Python25\lib\site-packages\django\middleware\common.py in
process_response, line 94
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Re: Attributr error
I want my final result in xml format and how can i do that? thanks for notification -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: Attributr error
Where should i use this please tell!! should i use in urls.py -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: Attributr error
HOW TO GET XML RESPONSE in following
THIS IS HOW MY URL.PY LOOKS LIKE
from django.conf.urls.defaults import *
from it.view import current_datetime
# Uncomment the next two lines to enable the admin:
#from django.contrib import admin
#admin.autodiscover()
urlpatterns = patterns('',
# Example:
(r"^wap/di/sub/$",current_datetime),
# Uncomment the admin/doc line below to enable admin documentation:
# (r'^admin/doc/', include('django.contrib.admindocs.urls')),
# Uncomment the next line to enable the admin:
# (r'^admin/', include(admin.site.urls)),
)
`~~~
My view .py looks like this
from django.http import *
import urllib
from django_restapi.responder import XMLResponder
def current_datetime(request):
word = request.GET['word']
message =
urllib.urlopen('http://m.broov.com/wap/di/sub?word='+word+'&type=00submit=Submit',)
return HttpResponse(message)
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Re: Attributr error
i Think serialisation would be helpful for this some one help me how to use it -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
SERIALIZING
HOW TO GET XML RESPONSE in following
THIS IS HOW MY URL.PY LOOKS LIKE
from django.conf.urls.defaults import *
from it.view import current_datetime
# Uncomment the next two lines to enable the admin:
#from django.contrib import admin
#admin.autodiscover()
urlpatterns = patterns('',
# Example:
(r"^wap/di/sub/$",current_datetime),
# Uncomment the admin/doc line below to enable admin documentation:
# (r'^admin/doc/', include('django.contrib.admindocs.urls')),
# Uncomment the next line to enable the admin:
# (r'^admin/', include(admin.site.urls)),
)
`~~~
My view .py looks like this
from django.http import *
import urllib
from django_restapi.responder import XMLResponder
def current_datetime(request):
word = request.GET['word']
message =
urllib.urlopen('http://m.broov.com/wap/di/sub?word='+word+'&type=00submit=Submit',)
return HttpResponse(message)
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WEB SERVICE IN DJANGO USING SOAP
Thanks for notification I am trying to develop web service using
django with soap interface i checked my code in python to open wsdl
file but its showing error i am sure that wsdl file dosent have any
errors this is my code>>> from SOAPpy import WSDL
>> server=WSDL.Proxy('D/soap/FlyppSms.wsdl')
Traceback (most recent call last):
File "", line 1, in
File "D:\Python25\Lib\site-packages\SOAPpy\WSDL.py", line 67, in __init__
self.wsdl = reader.loadFromString(str(wsdlsource))
File "D:\Python25\Lib\site-packages\SOAPpy\wstools\WSDLTools.py", line 47, in
loadFromString
return self.loadFromStream(StringIO(data))
File "D:\Python25\Lib\site-packages\SOAPpy\wstools\WSDLTools.py", line 28, in
loadFromStream
document = DOM.loadDocument(stream)
File "D:\Python25\Lib\site-packages\SOAPpy\wstools\Utility.py", line 602, in l
oadDocument
return xml.dom.minidom.parse(data)
File "D:\Python25\Lib\site-packages\_xmlplus\dom\minidom.py", line 1915, in pa
rse
return expatbuilder.parse(file)
File "D:\Python25\Lib\site-packages\_xmlplus\dom\expatbuilder.py", line 930, i
n parse
result = builder.parseFile(file)
File "D:\Python25\Lib\site-packages\_xmlplus\dom\expatbuilder.py", line 207, i
n parseFile
parser.Parse(buffer, 0)
xml.parsers.expat.ExpatError: not well-formed (invalid token): line 1, column 1
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Re: WEB SERVICE IN DJANGO USING SOAP
encoding="UTF-8"?> should i remove this from wsdl file...? and more over i am trying to use my system as server i am refering dive into python chapter 12 introspecting wsdl and searching google i cant find weather its an client side code or server side code but i am in need of server side code do u find any refrence for me to study server side code using SOAP or REST sorry if i had asked anything wrong i am newbee -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: WEB SERVICE IN DJANGO USING SOAP
After opening and closing also showing me the same result i cant say not to output the BOM to generator b coz its an another person who generated and gave to me and asking me to create web service using just wsdl file and given me open choice of use rather SOAP or REST i also decided to use REST now will u refer me the tutorial to rest and also to solve above problem -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: WEB SERVICE IN DJANGO USING ZSI
for creating server.py from wsdl file i am using this following code i dont na weather its right but its not creating any file but its throwing error >>> wsdl2py --extended --file=D;\soap\FlyppSms.wsdl File "", line 1 wsdl2py --extended --file=D;\soap\FlyppSms.wsdl ^ SyntaxError: unexpected character after line continuation character -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: WEB SERVICE IN DJANGO USING ZSI
But i am not havin python intreptor i use my command prompt this way Microsoft Windows [Version 6.1.7600] Copyright (c) 2009 Microsoft Corporation. All rights reserved. C:\Users\ezhil>python Python 2.5 (r25:51908, Sep 19 2006, 09:52:17) [MSC v.1310 32 bit (Intel)] on wi 32 Type "help", "copyright", "credits" or "license" for more information. >>> wsdl2py --extende --file=D:\soap\FlyppSms.wsdl File "", line 1 wsdl2py --extende --file=D:\soap\FlyppSms.wsdl ^ SyntaxError: invalid syntax >>> shouldn't i use this way -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
WEB SERVICE IN DJANGO USING ZSI
To genrate sevice file from my wsdl i used following command but it shows the same D:\Python25\Scripts>wsdl2py --complexType --file=ZonedLocation.wsdl 'wsdl2py' is not recognized as an internal or external command, operable program or batch file. but my wsdl2py is in the scripts oly -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: WEB SERVICE IN DJANGO USING ZSI
To create server file i used this command but showing following error D:\Python25\Scripts>python wsdl2py --complexType localhost 8080 d:/soap/zz/FlypS ms.wsdl Expecting a file/url as argument (WSDL). Traceback (most recent call last): File "wsdl2py", line 9, in wsdl2py() File "D:\Python25\Lib\site-packages\ZSI\generate\commands.py", line 122, in ws dl2py sys.exit(os.EX_USAGE) AttributeError: 'module' object has no attribute 'EX_USAGE' -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: WEB SERVICE IN DJANGO USING ZSI
ANY one knows how to generate server.py flie from wsdl2py in ZSI -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
WEB service using Restify
THANKS FOR NOTIFICATION
I am trying to do webservice with RESTfull web service but i dint create models
my view file looks like this
from django.http import *
import urllib
def current_datetime(request):
word = request.GET['word']
message=urllib.urlopen('http://m.broov.com/wap/di/sub?word='+word+'&type=00submit=Submit',)
return HttpResponse(message)
My url looks like this (r'^wap/di/sub/',current_datetime ),
i want to restify my view but all examples are showing oly models .py
now i need help to do that
THANKS
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urllib .urlopen problem
my django site was running successfully but now it s giving me the
following error
IO ERROR [Errno socket error] (11004, 'getaddrinfo failed'
my view looks like this and i am running in proxy settings but i
included that in my code
proxie = {'http': 'http://192.168.1.100:8080'}
word = request.GET['word']
message=urllib.urlopen('http://m.broov.com/wap/di/sub?word='+word+'&type=00submit=Submit',)
socket.setdefaulttimeout(1120)
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
return HttpResponse(message)
ANd it would be gracefull if someone help me to build web service
using RESTfull to run server
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get request from an java API to DJango
THANKS FOR NOTIFICATION Hi i am newbie to django i am having task that want to get request from an java API and give Response to the same API (To act as an server ) So i am having WSDL file for the JAVA API I decided to do that in ZSI WEB SERVICE and i generated server file using wsdl2py cmmd and according to tutorial i am seeing i want to overrriden the class in the server file but i am getting error Type error unbound method __init__() must be called with TypeCode instance as first argument (got String instance instead)" i am getting word from that API and i am returning the same word what this error says clearly? So i am finding little bit difficult in the ZSI is there Any other method to do the above task please suggest me At last clearly now i need to get request from that API and parse it -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
ZSI WEB SERVICE
__init__() must be called with TypeCode instance as first argument (got String instance instead) what this error says when i overriden the ZSI server file i got this error is there any one to say what this error says -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: get request from an java API to DJango
thanks for notification.Please guide me through a source to get a grasp of suds and continue working.Suggest me a point to startwith.To be honest i am completely new to this. Regards, Sami -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: get request from an java API to DJango
But i should act as an server will suds allow that? -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: ZSI WEB SERVICE
"""__init__() must be called with TypeCode instance as first argument (got String instance instead) """what this error says when i overriden the ZSI server file (generated using wsdl2py in ZSI) i got this error is there any one to say what this error says I am trying to act as server -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: ZSI WEB SERVICE
Ya me too in the same problem if any one find the solution please post here -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
WEB SERVICE
Hi i want to do web service in using django My client is sending SOAP request and should send response as SOAP response i am now sucessful in this process using ZSI but i want to run the process in django server So i refered http://djangosnippets.org/snippets/979/ now it would be helpfull for me if i get help of running echo server using the same example -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: WEB SERVICE
HI
Now i am getting some way but i still cant parse the incoming request my
view looks like this at present i am trying to send the request i am getting
from xml.dom import minidom
import urllib
import socket
from django.http import HttpResponse
from django.core import serializers
import urllib
import socket
def recive_ShortMessage(request):
if request.method == 'GET':
ref= "Process in progress"
return HttpResponse(ref)
elif request.method == 'POST':
print request
socket.setdefaulttimeout(20)
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
request.message=['brave']
print request.message
XMLSerializer = serializers.get_serializer("xml")
xml_serializer = XMLSerializer()
xml_serializer.serialize(request)
data = xml_serializer.getvalue()
print data
return HttpResponse(request)
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parsing SOAP request
Hi i am working web service i am getting SOAP(POST) request from client now i am trying to parse the request xml and sending the response my soap request is http://schemas.xmlsoap.org/soap/envelope/ ">http://flypp.infy.com/sms/v2010r1_0 ">12345343661t1p1p2DICT test']}> response now i want send response as change is denoted in colors **'http://schemas.xmlsoap.org/soap/envelope/ ">http://flypp.infy.com/sms/v2010r1_0 ">12345343661t1p1p2TEXT HERE ']}> -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: parsing SOAP request
Hi
Now i tried to parse the incoming request and send my response i tried
in the following way by just sending what request came as it as response
(ECHO server).and i am very newbie i dont know how to parse the request. I
used ZSI sucessfully but in that requset was handled by itself but ZSI
application is not accepting in django
My view looks like this :
def recive_ShortMessage(request):
if request.method == 'GET':
ref= "Process in progress"
return HttpResponse(ref)
elif request.method == 'POST':
print request.POST.QueryDict
return HttpResponse (request.POST)
But the error is
org.apache.axis2.AxisFault: in xml declaration
at [row,col {unknown-source}]: [1,13]
(I am using java client)
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QUERYDICT immutable
HI I am NEWBIE i am trying to run an server and my POST request is from java api(client) and i cant able to see exact error in java api its just showing HTML request is not accepting in java b coz django giving me error iin html format but by some how i manage to print request.POST from my request - -- http://schemas.xmlsoap.org/soap/envelope/ ">http://flypp.infy.com/sms/v2010r1_0 ">12345343661t1p1p2< messa ge>DICT test ']}> -- -- now i want to change just message in my request.POST (denoted by red color in above request) and i am helpless i tried the following code def recive_ShortMessage(request): if request.method == 'POST': request=request.POST.QueryDict.copy() qt=request.QueryDict.copy() print qt qt['message'] = 'I am changing it!' return HttpResponse(qt) _ _ As java api is not showing what error i am having i can know error in this program -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
XML parsing
HI
I am trying to parse my response by the following method
elif request.method == 'POST':
reqp=request.raw_post_data
response = HttpResponse(mimetype='text/xml')
response.write(reqp)
print response
xmldoc = minidom.parse('binary.xml')
reflist = xmldoc.getElementsByTagName('message')
print reflist
return response
But its giving me error of "TO MANY VALUE TO UNPACK"
--
my request looks like this
http://sc
hemas.xmlsoap.org/soap/envelope/
">http://flypp.infy.com/sms/v2010r1_0
">1234534366<
applicationID>1t1p
1p2DICT
test
Now my ultimate aim is to send error response to client sending me the
above request without DICT in message
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