Re: Apache Segmentation Fault on succesful authentication
On Wed, Nov 12, 2008 at 03:22:02AM -0800, huw_at1 wrote: > > An update on this. > > 'which python' returns: > > libpython2.5.so.1.0 => not found > libpthread.so.0 => /lib64/libpthread.so.0 (0x0039a4a0) > libdl.so.2 => /lib64/libdl.so.2 (0x0039a460) > libutil.so.1 => /lib64/libutil.so.1 (0x0039b340) > libm.so.6 => /lib64/libm.so.6 (0x0039a420) > libc.so.6 => /lib64/libc.so.6 (0x0039a3e0) > /lib64/ld-linux-x86-64.so.2 (0x0039a2c0) > > This explains why I cannot compile mod_python without first setting > the LD_LIBRARY_PATH to '/usr/local/lib'. I don't know if this is the > reason why the mod_python compilation continuously compiles with the > python library as static. I upgraded my apache to the latest version > however I still am getting segmentation faults on user authentication. > Which potentially suggests that the problem is not apache and is > something else like this issue. echo '/usr/local/lib' >> /etc/ld.so.conf --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~--~~~~--~~--~--~---
nested template problem
hello.
Does django template engine supports nested dictionary?
i'm trying to display a nested array with no luck.
that's my tries:
--- python manage.py shell ---
from django.template import Template, Context
list_parts = {
'root': {'value': [{'tag': 'a'},{'tag':'b'}]},
'wheel': {'value': [{'tag': 'c'}, ]}
}
t = Template("""
{% for part in list_parts %}
{{part}}
{% for subpart in part %}
{{ subpart }}
{% endfor %}
{% endfor %}
""")
c=Context({'list_parts':list_parts})
print t.render(c)
--
i tried every possible combination of
{% for subpart in part %}
{% for subpart in part.part %}
{% for subpart in list_parts.part %}
but i'm not able to show the information.
where i am wrong?
/me hopeless.
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Re: nested template problem
On Thu, Dec 18, 2008 at 11:42:19AM -0800, bruno desthuilliers wrote:
> > i'm trying to display a nested array with no luck.
> >
> > that's my tries:
> >
> > --- python manage.py shell ---
> > from django.template import Template, Context
> > list_parts = {
> > 'root': {'value': [{'tag': 'a'},{'tag':'b'}]},
> > 'wheel': {'value': [{'tag': 'c'}, ]}
> >
> > }
>
> Why do you name it "list_" when it's a dict ?
code obfuscation. :-)
> > t = Template("""
> > {% for part in list_parts %}
>
> This will iterate over the keys. If you want key:values pairs, you
> have to spell it:
>
> {% for partname, partvalue in list_parts.items %}
argh!
i realize that i was reading the documentation from this page:
http://www.djangoproject.com/documentation/0.96/templates/
and not from this page:
http://docs.djangoproject.com/en/dev/ref/templates/builtins/?from=olddocs
too bad. :-(
thank you very much.
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extend TimeFormat
hello, i've a problem extending the TimeFormat class (used by "time" template filter). basically, i need a new method: def F(self): if self.date.minute == 0: return self.G() return u'%s:%s' % (self.G(), self.i()) very similar to the original one except for a G() instead of a g(). the (too) easy path is to modify the dateformat.py, but i don't want to modify the django installation for many obvious reasons. i want to extend the dateformat class, and i tryed to put this - from django.utils.dateformat import TimeFormat class TimeFormat(TimeFormat): "extends with one method" def F(self): if self.date.minute == 0: return self.G() return u'%s:%s' % (self.G(), self.i()) --- in many places inside my project tree (settings.py, views.py, __init__.py ) but in vain. where should i put it? regards, marco. -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
extend TimeFormat
hello, i've a problem extending the TimeFormat class (used by "time" template filter). basically, i need a new method: def F(self): if self.date.minute == 0: return self.G() return u'%s:%s' % (self.G(), self.i()) very similar to the original one except for a G() instead of a g(). the (too) easy path is to modify the dateformat.py, but i don't want to modify the django installation for many obvious reasons. i want to extend the dateformat class, and i tryed to put this - from django.utils.dateformat import TimeFormat class TimeFormat(TimeFormat): "extends with one method" def F(self): if self.date.minute == 0: return self.G() return u'%s:%s' % (self.G(), self.i()) --- in many places inside my project tree (settings.py, views.py, __init__.py ) but in vain. where should i put it? regards, marco. -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en. -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
