Re: Ajax Form Submission Trouble

2007-08-14 Thread dor

Try this: onclick="this.disabled=true;"
Notice the "disabled" instead of "disable"!


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Testing an app without a models.py file

2012-04-21 Thread dor
As of the latest version (1.4), this is impossible. What's the rationale behind 
it? Why isn't it fixed by now? If I make a fix, will it be accepted by the 
official team?

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