Newbie : Help for using RequestContext

[Mickael . barbo]

Hello to all Django users :-)

I'm new to Django and this is my first post.

I'd like to implement breadcrumbs on all my pages.

My strategy is to create a middleware and to use RequestContext to
add a dict to the context of each request then use the context in my html

My problem is that I don't understand how to link RequestContext to 
my request. Hereafter my code :

my_middleware.py
from django.template import RequestContext


class SimpleBreadcrumbs(object):
def __init__(self, get_response):
self.get_response = get_response
# One-time configuration and initialization.


def __call__(self, request):
# Code to be executed for each request before
# the view (and later middleware) are called.

request_context = RequestContext(request)
request_context.push({"level0": "Adrian", "level1": "Thomas"})

response = self.get_response(request)


# Code to be executed for each request/response after
# the view is called.

return response


my_template.html

{% extends 'pricing/body.html' %}

{% block content %}

{{ level0 }}

{% endblock content %}


What I'm doing wrong ?

Thx for your help

Micka
Django newbie
;-)





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Re: Newbie : Help for using RequestContext

[mickael . barbo]

Oh, 
*Thank you Andréas for your kind attention and your reactivity.*
Nice, I didn't know about request.session... And thanks to you, *now I Know* 
:-)

Just for archive, I found a way with context_processors here (old django 
version, but I adapt to django 2) :
http://apprendre-python.com/page-django-context-processor-template

Very happy to join Django community :D

Micka

Le mercredi 10 janvier 2018 09:36:46 UTC+1, Andréas Kühne a écrit :
>
> Hi Micka,
>
> And welcome to django.
>
> Regarding how to add things in middleware - you can add the information to 
> the session like this:
>
> class SimpleBreadcrumbs(object):
> def __init__(self, get_response):
> self.get_response = get_response
> # One-time configuration and initialization.
>
>
> def __call__(self, request):
> # Code to be executed for each request before
> # the view (and later middleware) are called.
>
> request.session['breadcrumbs'] = {"level0": "Adrian", "level1": 
> "Thomas"}
>
> response = self.get_response(request)
>
>
> # Code to be executed for each request/response after
> # the view is called.
>
> return response
>
>
> Then in your templates you can do this:
>
> {% extends 'pricing/body.html' %}
>
> {% block content %}
>
> {{ breadcrumbs.level0 }} / {{ breadcrumbs.level1 }}
>
> {% endblock content %}
>
> Regards,
>
> Andréas
>
> 2018-01-10 0:42 GMT+01:00 >:
>
>> Hello to all Django users :-)
>>
>> I'm new to Django and this is my first post.
>>
>> I'd like to implement breadcrumbs on all my pages.
>>
>> My strategy is to create a middleware and to use RequestContext to
>> add a dict to the context of each request then use the context in my html
>>
>> My problem is that I don't understand how to link RequestContext to 
>> my request. Hereafter my code :
>>
>> my_middleware.py
>> from django.template import RequestContext
>>
>>
>> class SimpleBreadcrumbs(object):
>> def __init__(self, get_response):
>> self.get_response = get_response
>> # One-time configuration and initialization.
>>
>>
>> def __call__(self, request):
>> # Code to be executed for each request before
>> # the view (and later middleware) are called.
>>
>> request_context = RequestContext(request)
>> request_context.push({"level0": "Adrian", "level1": "Thomas"})
>>
>> response = self.get_response(request)
>>
>>
>> # Code to be executed for each request/response after
>> # the view is called.
>>
>> return response
>>
>>
>> my_template.html
>>
>> {% extends 'pricing/body.html' %}
>>
>> {% block content %}
>>
>> {{ level0 }}
>>
>> {% endblock content %}
>>
>>
>> What I'm doing wrong ?
>>
>> Thx for your help
>>
>> Micka
>> Django newbie
>> ;-)
>>
>>
>>
>>
>>
>> -- 
>> You received this message because you are subscribed to the Google Groups 
>> "Django users" group.
>> To unsubscribe from this group and stop receiving emails from it, send an 
>> email to django-users...@googlegroups.com .
>> To post to this group, send email to django...@googlegroups.com 
>> .
>> Visit this group at https://groups.google.com/group/django-users.
>> To view this discussion on the web visit 
>> https://groups.google.com/d/msgid/django-users/6cf0e65a-2b48-4bbb-a8a7-0351252e49f9%40googlegroups.com
>>  
>> 
>> .
>> For more options, visit https://groups.google.com/d/optout.
>>
>
>

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Newbie : Best data archive strategy

[mickael . barbo]

Hi,

I'd like to archive some data.

I came with this idea :


class DataModel(models.Model):
xxx

class DataModelArchive(DataModel):
pass


The DataModelArchive database created has only "a pointer" to DataModel.

I saw a post indicating that I'll have to first create an AbstractDataModel 
and inherit for it for both DataModelArchive and DataModel.

Well, what is the "best way" to archive data using Django ?

Thx for your attention

Micka

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Re: Newbie : Best data archive strategy

[mickael . barbo]

Thanks Matthew for your response.

I looked at Reversion. If I understand correctly what it did, it duplicate 
each transaction on internal database ?

Le mardi 12 juin 2018 20:01:02 UTC+2, Matthew Pava a écrit :
>
> I think what you’re really looking for is an audit log.  There are some 
> Django packages available that do that automatically.
>
>  
>
> You might find this one quite helpful, called Django Reversion:
>
> https://github.com/etianen/django-reversion
>
>  
>
>  
>
> *From:* django...@googlegroups.com  [mailto:
> django...@googlegroups.com ] *On Behalf Of *
> mickae...@gmail.com 
> *Sent:* Tuesday, June 12, 2018 12:22 PM
> *To:* Django users
> *Subject:* Newbie : Best data archive strategy
>
>  
>
> Hi,
>
> I'd like to archive some data.
>
> I came with this idea :
>
>
> class DataModel(models.Model):
>
> xxx
>
>
> class DataModelArchive(DataModel):
>
> pass
>
>  
>
>
> The DataModelArchive database created has only "a pointer" to DataModel.
>
> I saw a post indicating that I'll have to first create an 
> AbstractDataModel and inherit for it for both DataModelArchive and 
> DataModel.
>
> Well, what is the "best way" to archive data using Django ?
>
> Thx for your attention
>
> Micka
>
> -- 
> You received this message because you are subscribed to the Google Groups 
> "Django users" group.
> To unsubscribe from this group and stop receiving emails from it, send an 
> email to django-users...@googlegroups.com .
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> .
> Visit this group at https://groups.google.com/group/django-users.
> To view this discussion on the web visit 
> https://groups.google.com/d/msgid/django-users/ef59e00a-3354-44f5-9c99-5ca85885026e%40googlegroups.com
>  
> 
> .
> For more options, visit https://groups.google.com/d/optout.
>

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Re: Newbie : Best data archive strategy

[Mickael Barbo]

Ok, so "audit log" is like a "snapshot". I think it's too much for what I
need.

To clarify my needs, I have a data that once "used/read", it's no more
needed.
I just want to keep it "archived", in an other place to get access to it if
I want to add some function (statistics, etc...).

So, Gerardo, it seems to be like " I want to "move" data to an archive
system (data is still relevant and useful)."

Hope this clarify my needs...

Thx Matthew and Gerardo for your help.


2018-06-12 20:38 GMT+02:00 Gerardo Palazuelos Guerrero <
gerardo.palazue...@gmail.com>:

> Hi Mickael,
> When I read Archive, in my mind is a different thing, not the same as
> audit. So, for one moment, think about situation/scenario you are working
> on.
>
> Archive is to manage data purge from my transactional tables; this means I
> want to "delete" data (that has not more value) or I want to "move" data to
> an archive system (data is still relevant and useful).
>
> Audit is to create a perfect tracking of transitions on value overtime.
> This is required due to special regulations you have.
>
> So, it might be useful if you clarify what is the scenario you are trying
> to solve.
>
> Regards,
> Gerardo.
>
>
>
> --
> Gerardo Palazuelos Guerrero
>
>
> On Tue, Jun 12, 2018 at 12:14 PM, Matthew Pava 
> wrote:
>
>> Hi Mickael,
>>
>> It saves a copy of each record every time a record is changed.  But it is
>> saved in a separate table, so it doesn’t change your model’s table.
>>
>>
>>
>> *From:* django-users@googlegroups.com [mailto:django-users@googlegro
>> ups.com] *On Behalf Of *mickael.ba...@gmail.com
>> *Sent:* Tuesday, June 12, 2018 1:17 PM
>> *To:* Django users
>> *Subject:* Re: Newbie : Best data archive strategy
>>
>>
>>
>> Thanks Matthew for your response.
>>
>> I looked at Reversion. If I understand correctly what it did, it
>> duplicate each transaction on internal database ?
>>
>> Le mardi 12 juin 2018 20:01:02 UTC+2, Matthew Pava a écrit :
>>
>> I think what you’re really looking for is an audit log.  There are some
>> Django packages available that do that automatically.
>>
>>
>>
>> You might find this one quite helpful, called Django Reversion:
>>
>> https://github.com/etianen/django-reversion
>>
>>
>>
>>
>>
>> *From:* django...@googlegroups.com [mailto:django...@googlegroups.com] *On
>> Behalf Of *mickae...@gmail.com
>> *Sent:* Tuesday, June 12, 2018 12:22 PM
>> *To:* Django users
>> *Subject:* Newbie : Best data archive strategy
>>
>>
>>
>> Hi,
>>
>> I'd like to archive some data.
>>
>> I came with this idea :
>>
>>
>> class DataModel(models.Model):
>>
>> xxx
>>
>>
>> class DataModelArchive(DataModel):
>>
>> pass
>>
>>
>>
>>
>> The DataModelArchive database created has only "a pointer" to DataModel.
>>
>> I saw a post indicating that I'll have to first create an
>> AbstractDataModel and inherit for it for both DataModelArchive and
>> DataModel.
>>
>> Well, what is the "best way" to archive data using Django ?
>>
>> Thx for your attention
>>
>> Micka
>>
>> --
>> You received this message because you are subscribed to the Google Groups
>> "Django users" group.
>> To unsubscribe from this group and stop receiving emails from it, send an
>> email to django-users...@googlegroups.com.
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>> Visit this group at https://groups.google.com/group/django-users.
>> To view this discussion on the web visit https://groups.google.com/d/ms
>> gid/django-users/ef59e00a-3354-44f5-9c99-5ca85885026e%40googlegroups.com
>> 
>> .
>> For more options, visit https://groups.google.com/d/optout.
>>
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>> .
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>> 

Newbie : Implementation possible ?

[mickael . barbo]

Hi community :)

I'd like to implement something like "joined image".

In Database, I'd like CoreObject to have the key of "Object1" OR "Object2" 
OR "Object3" (like foreignKey).

How can I do that ?

The context is that CoreObject is a central DataBaseFile and will receive 
information from one of ObjectX + ObjectX.pk to access ObjectX.

Thanks for your help

Micka

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Newbie : Object copy - weird error :-)

[mickael . barbo]

Hi all :-)

I'd like to archive some data.

I did that :

class AbstractDataModel(models.Model):
xxx

class Meta:
abstract = True


def __iter__(self):

return iter([self.xxx, self.yyy, self.zzz, self.aaa,
self.qqq, self.mode_bbb])


class DataModel(DataModel):

pass


class DataModelArchive(DataModel):
# 
https://stackoverflow.com/questions/21699707/python-how-to-copy-all-attibutes-from-base-class-to-derived-one
def __init__(self, source=None):
if source is not None:
self.__dict__.update(source.__dict__)


But when I want to access data in DataModelArchive, like 
DataModelArchive.objects.all() for example,
I get 

Traceback (most recent call last):
  File "/home/.../tests.py", line 1090, in test_archive
print(DataModelArchive.objects.all())
  File 
"/home/.../venv/lib/python3.6/site-packages/django/db/models/query.py", 
line 248, in __repr__
data = list(self[:REPR_OUTPUT_SIZE + 1])
  File 
"/home/.../venv/lib/python3.6/site-packages/django/db/models/query.py", 
line 272, in __iter__
self._fetch_all()
  File 
"/home/.../venv/lib/python3.6/site-packages/django/db/models/query.py", 
line 1179, in _fetch_all
self._result_cache = list(self._iterable_class(self))
  File 
"/home/.../venv/lib/python3.6/site-packages/django/db/models/query.py", 
line 63, in __iter__
obj = model_cls.from_db(db, init_list, row[model_fields_start:
model_fields_end])
  File "/home/.../lib/python3.6/site-packages/django/db/models/base.py", 
line 507, in from_db
new = cls(*values)
TypeError: __init__() takes from 1 to 2 positional arguments but 11 were 
given

What am I doing wrong ?

Thx

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Newbie : Object copy - weird error :-)

[mickael . barbo]

Hi all :-)

I'd like to archive some data.

I did that :

class AbstractDataModel(models.Model):

xxx


class Meta:
abstract = True


def __iter__(self):

return iter([self.xxx, self.yyy, self.zzz, self.aaa,
self.qqq, self.mode_bbb])


class DataModel(AbstractDataModel):


pass


class DataModelArchive(AbstractDataModel):
# 
https://stackoverflow.com/questions/21699707/python-how-to-copy-all-attibutes-from-base-class-to-derived-one
def __init__(self, source=None):
if source is not None:
self.__dict__.update(source.__dict__)



But when I want to access data in DataModelArchive, like 
DataModelArchive.objects.all() for example,
I get 


Traceback (most recent call last):
  File "/home/.../tests.py", line 1090, in test_archive
print(DataModelArchive.objects.all())
  File 
"/home/.../venv/lib/python3.6/site-packages/django/db/models/query.py", 
line 248, in __repr__
data = list(self[:REPR_OUTPUT_SIZE + 1])
  File 
"/home/.../venv/lib/python3.6/site-packages/django/db/models/query.py", 
line 272, in __iter__
self._fetch_all()
  File 
"/home/.../venv/lib/python3.6/site-packages/django/db/models/query.py", 
line 1179, in _fetch_all
self._result_cache = list(self._iterable_class(self))
  File 
"/home/.../venv/lib/python3.6/site-packages/django/db/models/query.py", 
line 63, in __iter__
obj = model_cls.from_db(db, init_list, row[model_fields_start:
model_fields_end])
  File "/home/.../lib/python3.6/site-packages/django/db/models/base.py", 
line 507, in from_db
new = cls(*values)
TypeError: __init__() takes from 1 to 2 positional arguments but 11 were 
given



What am I doing wrong ?

Thx
;-)

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Re: Newbie : Object copy - weird error :-)

[mickael . barbo]

Error typo, I creates a new thread with the good description ;-)

Le mardi 26 juin 2018 16:35:27 UTC+2, Nelson Varela a écrit :
>
> The following class is kinda weird:
> class DataModel(DataModel):
>
> A class which inherits itself???
>
>
>
> On Tuesday, June 26, 2018 at 11:31:24 AM UTC+2, mickae...@gmail.com wrote:
>>
>> Hi all :-)
>>
>> I'd like to archive some data.
>>
>> I did that :
>>
>> class AbstractDataModel(models.Model):
>> xxx
>>
>> class Meta:
>> abstract = True
>>
>>
>> def __iter__(self):
>>
>> return iter([self.xxx, self.yyy, self.zzz, self.aaa,
>> self.qqq, self.mode_bbb])
>>
>>
>> class DataModel(DataModel):
>>
>> pass
>>
>>
>> class DataModelArchive(DataModel):
>> # 
>> https://stackoverflow.com/questions/21699707/python-how-to-copy-all-attibutes-from-base-class-to-derived-one
>> def __init__(self, source=None):
>> if source is not None:
>> self.__dict__.update(source.__dict__)
>>
>>
>> But when I want to access data in DataModelArchive, like 
>> DataModelArchive.objects.all() for example,
>> I get 
>>
>> Traceback (most recent call last):
>>   File "/home/.../tests.py", line 1090, in test_archive
>> print(DataModelArchive.objects.all())
>>   File 
>> "/home/.../venv/lib/python3.6/site-packages/django/db/models/query.py", 
>> line 248, in __repr__
>> data = list(self[:REPR_OUTPUT_SIZE + 1])
>>   File 
>> "/home/.../venv/lib/python3.6/site-packages/django/db/models/query.py", 
>> line 272, in __iter__
>> self._fetch_all()
>>   File 
>> "/home/.../venv/lib/python3.6/site-packages/django/db/models/query.py", 
>> line 1179, in _fetch_all
>> self._result_cache = list(self._iterable_class(self))
>>   File 
>> "/home/.../venv/lib/python3.6/site-packages/django/db/models/query.py", 
>> line 63, in __iter__
>> obj = model_cls.from_db(db, init_list, row[model_fields_start:
>> model_fields_end])
>>   File "/home/.../lib/python3.6/site-packages/django/db/models/base.py", 
>> line 507, in from_db
>> new = cls(*values)
>> TypeError: __init__() takes from 1 to 2 positional arguments but 11 were 
>> given
>>
>> What am I doing wrong ?
>>
>> Thx
>>
>>

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Re: Newbie : Object copy - weird error :-)

[Mickael Barbo]

Hi 赖信桃,

Sorry for formating problem. Here it is

class AbstractDataModel(models.Model):

xxx


class Meta:
abstract = True


def __iter__(self):

 return iter([self.xxx, self.yyy, self.zzz, self.aaa,
  self.qqq, self.mode_bbb])


class DataModel(AbstractDataModel):

pass


class DataModelArchive(AbstractDataModel):
# https://stackoverflow.com/questions/21699707/python-how-
to-copy-all-attibutes-from-base-class-to-derived-one
def __init__(self, source=None):
if source is not None:
self.__dict__.update(source.__dict__)



2018-06-27 4:34 GMT+02:00 赖信桃 :

> Can you format your code or post it on a gist?
> On Wed, Jun 27, 2018 at 00:17  wrote:
>
>> Hi all :-)
>>
>> I'd like to archive some data.
>>
>> I did that :
>>
>> class AbstractDataModel(models.Model):
>>
>> xxx
>>
>>
>> class Meta:
>> abstract = True
>>
>>
>> def __iter__(self):
>>
>> return iter([self.xxx, self.yyy, self.zzz, self.aaa,
>> self.qqq, self.mode_bbb])
>>
>>
>> class DataModel(AbstractDataModel):
>>
>>
>> pass
>>
>>
>> class DataModelArchive(AbstractDataModel):
>> # https://stackoverflow.com/questions/21699707/python-how-
>> to-copy-all-attibutes-from-base-class-to-derived-one
>> def __init__(self, source=None):
>> if source is not None:
>> self.__dict__.update(source.__dict__)
>>
>>
>>
>> But when I want to access data in DataModelArchive, like
>> DataModelArchive.objects.all() for example,
>> I get
>>
>>
>> Traceback (most recent call last):
>>   File "/home/.../tests.py", line 1090, in test_archive
>> print(DataModelArchive.objects.all())
>>   File "/home/.../venv/lib/python3.6/site-packages/django/db/
>> models/query.py", line 248, in __repr__
>> data = list(self[:REPR_OUTPUT_SIZE + 1])
>>   File "/home/.../venv/lib/python3.6/site-packages/django/db/
>> models/query.py", line 272, in __iter__
>> self._fetch_all()
>>   File "/home/.../venv/lib/python3.6/site-packages/django/db/
>> models/query.py", line 1179, in _fetch_all
>> self._result_cache = list(self._iterable_class(self))
>>   File "/home/.../venv/lib/python3.6/site-packages/django/db/
>> models/query.py", line 63, in __iter__
>> obj = model_cls.from_db(db, init_list, row[model_fields_start:model_
>> fields_end])
>>   File "/home/.../lib/python3.6/site-packages/django/db/models/base.py",
>> line 507, in from_db
>> new = cls(*values)
>> TypeError: __init__() takes from 1 to 2 positional arguments but 11 were
>> given
>>
>>
>>
>> What am I doing wrong ?
>>
>> Thx
>> ;-)
>>
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Re: Newbie : Object copy - weird error :-)

[Mickael Barbo]

Hello  Julio,

Ok, I see.

I try to create a way to archive (copy) the same object instance on an
other DataBase.

I followed this advice : # https://stackoverflow.com/
questions/21699707/python-how-to-copy-all-attibutes-from-
base-class-to-derived-one


2018-06-27 14:56 GMT+02:00 Julio Biason :

> Hi Mikael,
>
> The problem is happening because of this: __init__() takes from 1 to 2
> positional arguments but 11 were given
>
> On your new __init__(), you added just 2 parameters: `self` and `source`.
> But you overwrote the default `models.Model` init, which receives way more
> parameters (the original signature for this function is `__init__(self,
> *args, **kwargs)`).
>
> What are you actually trying to achieve with this?
>
> On Tue, Jun 26, 2018 at 1:17 PM,  wrote:
>
>> Hi all :-)
>>
>> I'd like to archive some data.
>>
>> I did that :
>>
>> class AbstractDataModel(models.Model):
>>
>> xxx
>>
>>
>> class Meta:
>> abstract = True
>>
>>
>> def __iter__(self):
>>
>> return iter([self.xxx, self.yyy, self.zzz, self.aaa,
>> self.qqq, self.mode_bbb])
>>
>>
>> class DataModel(AbstractDataModel):
>>
>>
>> pass
>>
>>
>> class DataModelArchive(AbstractDataModel):
>> # https://stackoverflow.com/questions/21699707/python-how-to-
>> copy-all-attibutes-from-base-class-to-derived-one
>> def __init__(self, source=None):
>> if source is not None:
>> self.__dict__.update(source.__dict__)
>>
>>
>>
>> But when I want to access data in DataModelArchive, like
>> DataModelArchive.objects.all() for example,
>> I get
>>
>>
>> Traceback (most recent call last):
>>   File "/home/.../tests.py", line 1090, in test_archive
>> print(DataModelArchive.objects.all())
>>   File "/home/.../venv/lib/python3.6/site-packages/django/db/models
>> /query.py", line 248, in __repr__
>> data = list(self[:REPR_OUTPUT_SIZE + 1])
>>   File "/home/.../venv/lib/python3.6/site-packages/django/db/models
>> /query.py", line 272, in __iter__
>> self._fetch_all()
>>   File "/home/.../venv/lib/python3.6/site-packages/django/db/models
>> /query.py", line 1179, in _fetch_all
>> self._result_cache = list(self._iterable_class(self))
>>   File "/home/.../venv/lib/python3.6/site-packages/django/db/models
>> /query.py", line 63, in __iter__
>> obj = model_cls.from_db(db, init_list, row[model_fields_start:model_f
>> ields_end])
>>   File "/home/.../lib/python3.6/site-packages/django/db/models/base.py",
>> line 507, in from_db
>> new = cls(*values)
>> TypeError: __init__() takes from 1 to 2 positional arguments but 11 were
>> given
>>
>>
>>
>> What am I doing wrong ?
>>
>> Thx
>> ;-)
>>
>> --
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>
>
>
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Re: Newbie : Object copy - weird error :-)

[mickael . barbo]

Thanks you Melvyn, this is it :-)

Have a nice day.

Regards

Le mardi 3 juillet 2018 00:34:14 UTC+2, Melvyn Sopacua a écrit :
>
> On vrijdag 29 juni 2018 09:44:40 CEST Mickael Barbo wrote:
>
>  
>
> > I try to create a way to archive (copy) the same object instance on an
>
> > other DataBase.
>
> > 
>
> > I followed this advice : # https://stackoverflow.com/
>
> > questions/21699707/python-how-to-copy-all-attibutes-from-
>
> > base-class-to-derived-one
>
>  
>
> That advice is for normal python classes. Django models have some 
> restrictions, one being that fields are special attributes. Messing with a 
> model's __init__() is not something you normally do as a model's class 
> creation is highly customized.
>
>  
>
> If you're really using 2 different databases, a model's save() operation 
> supports a `using` keyword that allows you to select the database 
> connection 
> <https://docs.djangoproject.com/en/2.0/topics/db/multi-db/#selecting-a-database-for-save>.
>  
> Archiving becomes really easy that way.
>
>  
>
>  
>
> -- 
>
> Melvyn Sopacua
>

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App structure : "One file - One object" - Is there a better way ?

[Mickael Barbo]

Hi !

*I like working with " 1 file - 1 object " (Object could be class,
function...).*
It simplify visibility, debug etc... and it's easy for me to *don't pollute
my brain* :-)


For exemple, I do :


In *class_.py file* :

class ():
a
b
c

from ._method1 import method1
from ._method2 import method2



and in *_method1.py file* :

def method1(self):
"my code"




*It works great, but is there a better way to do that ? is there a solution
to do that "automatically" ?*



I read lots of thinks about mixin, heritage, etc... but is there a better
way to split code to get a better granularity ?


Thanks for sharing your point ;-)

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Re: App structure : "One file - One object" - Is there a better way ?

[Mickael Barbo]

Hi Anthony 😊

Thanks for sharing your experience.

"1 file one object doesn't mean what you think it means."

I hope you get the meaning I described 😉

"it normally means (for instance) defining one class (and ALL of it's
methods' in one file) - not importing methods into class definitions - I
have never seen anyone suggest that."

A method is a function ? a function an object ? right ?

My purpose is that *I prefer working on several "small" files containing 1
small function/object* and *NOT* *dealing with a "big" file* containing all
methods of class (for example). It's straightforward to find what I look
for.

Mixins and inheritance don't really help here - unless you are reusing the
same method in multiple classes - in which case you might have a mixin, or
an inheritance situation.
Agree 😊

If you have one or more methods that provide a useful extra behavior to one
or many classes (say that you have a set of methods that provide extra
formatting on some fields, then that would be a mixin
Ok

If you can identify one of your classes being an extension to another in
some way - so for instance you have a model for Customers, and you have a
model for your Gold Customers then you might well have an inheritance
situation - anywhere you can say Model A is a type of Model B that is
inheritance: Gold Customers are a type of Customer.
Ok

So, for you, *if you would reduce the size of files you are working on, how
would you do that ?*

For example, let's say you have a Customer class with 15 methods and the
file is about 1000 lines of code.
How to split this file in smaller files with 1 method per file ?


Thanks for your help Anthony, hoping to be as clear as possible.
Regards


2018-07-14 10:56 GMT+02:00 Anthony Flury :

> On 13/07/18 12:44, Mickael Barbo wrote:
>
>> Hi !
>> *
>> I like working with " 1 file - 1 object " (Object could be class,
>> function...).*
>> It simplify visibility, debug etc... and it's easy for me to *don't
>> pollute my brain* :-)
>>
>>
> 1 file one object doesn't mean what you think it means.
>
> it normally means (for instance) defining one class (and ALL of it's
> methods' in one file) - not importing methods into class definitions - I
> have never seen anyone suggest that.
>
> Mixins and inheritance don't really help here - unless you are reusing the
> same method in multiple classes - in which case you might have a mixin, or
> an inheritance situation.
>
> If you have one or more methods that provide a useful extra behavior to
> one or many classes (say that you have a set of methods that provide extra
> formatting on some fields, then that would be a mixin
>
> If you can identify one of your classes being an extension to another in
> some way - so for instance you have a model for Customers, and you have a
> model for your Gold Customers then you might well have an inheritance
> situation - anywhere you can say Model A is a type of Model B that is
> inheritance: Gold Customers are a type of Customer.
>
>
>> For exemple, I do :
>>
>>
>> In *class_.py file* :
>>
>> |
>> class():
>> a
>> b
>> c
>>
>> from.|_method1|importmethod1
>> from.|_method2| importmethod2
>> |
>>
>>
>>
>> and in |*_method1.py file* :
>> |
>> |
>> |
>> |
>> |
>> def|method1(self):
>> |
>> "my code"
>> |
>> |
>> |
>> |
>> |
>> |
>> |
>> |
>> |
>> |
>> *|It works great, but is there a better way to do that ? is there a
>> solution to do that "automatically" ?|*
>> *|
>> |*
>> *|
>> |*
>>
>> *||*
>> |I read lots of thinks about mixin, heritage, etc... but is there a
>> better way to split code to get a better granularity ?|
>> |
>> |
>>
>> ||
>> |Thanks for sharing your point ;-)|
>> ||*||*
>>
>>
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