Re: Registering a user profile

[Kevin Anthony]

Did you include the module in your settings.py?

Kevin
Please excuse brevity, sent from phone
On Feb 14, 2012 1:27 PM, "Christos Jonathan Hayward" <
christos.jonathan.hayw...@gmail.com> wrote:

> Thank you, little master and creecode. I tried 'pim.UserProfile' and
> 'pim.models.UserProfile' and they both errored out. With 'pim.UserProfile',
> which it looks like the documentation calls for, I get:
>
> SiteProfileNotAvailable at /
>
>
> Unable to load the profile model, check AUTH_PROFILE_MODULE in your project 
> settings
>
>  Request Method: GET Request URL: http://localhost:8000/ Django Version:
> 1.3.1 Exception Type: SiteProfileNotAvailable Exception Value:
>
>
> Unable to load the profile model, check AUTH_PROFILE_MODULE in your project 
> settings
>
> Exception Location: 
> /usr/local/Cellar/python/2.7/lib/python2.7/site-packages/django/contrib/auth/models.py
> in get_profile, line 380 Python Executable:/usr/local/bin/python Python
> Version:2.7.0 Python Path:
>
>
> ['/Users/jonathan/pim',
>  
> '/usr/local/Cellar/python/2.7/lib/python2.7/site-packages/distribute-0.6.14-py2.7.egg',
>  
> '/usr/local/Cellar/python/2.7/lib/python2.7/site-packages/pip-0.8.1-py2.7.egg',
>  '/usr/local/Cellar/python/2.7/lib/python27.zip',
>  '/usr/local/Cellar/python/2.7/lib/python2.7',
>  '/usr/local/Cellar/python/2.7/lib/python2.7/plat-darwin',
>  '/usr/local/Cellar/python/2.7/lib/python2.7/plat-mac',
>  '/usr/local/Cellar/python/2.7/lib/python2.7/plat-mac/lib-scriptpackages',
>  '/usr/local/Cellar/python/2.7/lib/python2.7/lib-tk',
>  '/usr/local/Cellar/python/2.7/lib/python2.7/lib-old',
>  '/usr/local/Cellar/python/2.7/lib/python2.7/lib-dynload',
>  '/usr/local/Cellar/python/2.7/lib/python2.7/site-packages',
>  '/usr/local/Cellar/python/2.7/lib/python2.7/site-packages/PIL',
>  '/usr/local/lib/python2.7/site-packages',
>  
> '/usr/local/Cellar/python/2.7/lib/python2.7/site-packages/setuptools-0.6c11-py2.7.egg-info']
>
> Server time: Tue, 14 Feb 2012 12:17:42 -0600
>
>
> With 'pim.models.UserProfile' I get a slightly different:
>
> SiteProfileNotAvailable at /
>
>
> app_label and model_name should be separated by a dot in the 
> AUTH_PROFILE_MODULE setting
>
>  Request Method: GET Request URL: http://localhost:8000/ Django Version:
> 1.3.1 Exception Type: SiteProfileNotAvailable Exception Value:
>
>
> app_label and model_name should be separated by a dot in the 
> AUTH_PROFILE_MODULE setting
>
> Exception Location: 
> /usr/local/Cellar/python/2.7/lib/python2.7/site-packages/django/contrib/auth/models.py
> in get_profile, line 373 Python Executable:/usr/local/bin/python Python
> Version:2.7.0 Python Path:
>
>
> ['/Users/jonathan/pim',
>  
> '/usr/local/Cellar/python/2.7/lib/python2.7/site-packages/distribute-0.6.14-py2.7.egg',
>  
> '/usr/local/Cellar/python/2.7/lib/python2.7/site-packages/pip-0.8.1-py2.7.egg',
>  '/usr/local/Cellar/python/2.7/lib/python27.zip',
>  '/usr/local/Cellar/python/2.7/lib/python2.7',
>  '/usr/local/Cellar/python/2.7/lib/python2.7/plat-darwin',
>  '/usr/local/Cellar/python/2.7/lib/python2.7/plat-mac',
>  '/usr/local/Cellar/python/2.7/lib/python2.7/plat-mac/lib-scriptpackages',
>  '/usr/local/Cellar/python/2.7/lib/python2.7/lib-tk',
>  '/usr/local/Cellar/python/2.7/lib/python2.7/lib-old',
>  '/usr/local/Cellar/python/2.7/lib/python2.7/lib-dynload',
>  '/usr/local/Cellar/python/2.7/lib/python2.7/site-packages',
>  '/usr/local/Cellar/python/2.7/lib/python2.7/site-packages/PIL',
>  '/usr/local/lib/python2.7/site-packages',
>  
> '/usr/local/Cellar/python/2.7/lib/python2.7/site-packages/setuptools-0.6c11-py2.7.egg-info']
>
> Server time: Tue, 14 Feb 2012 12:25:41 -0600
>
>
> "pim" is the name of the project. Do I need to create a distinct
> application within that project?
>
> On Tue, Feb 14, 2012 at 12:20 PM, creecode  wrote:
>
>> Hello Jonathan,
>>
>> See the "Storing additional information about 
>> users"
>> section in the docs.  There it mentions the expected format of
>> AUTH_PROFILE_MODULE.
>>
>> I suspect what you need to do is wrap your UserProfile model up in it's
>> own app if it isn't in one already.  Alternately you need to change the
>> "models" in AUTH_PROFILE_MODULE to the name of your app.
>>
>> Let us know if that works for you.
>>
>> Toodle-lo..
>> creecode
>>
>>
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>
>
>
> --
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> Christos Jonathan Hayward, an Orthodox Christian autho

Easy Blog

[Kevin Anthony]

Hello,
I am a student and i have an existing django website that i'd like to
add a blog to, what is the simplest way to do this?
Also, it would be nice if i could use a standared CSS file to skin the blog
to look like the rest of my website.

Thanks in advance
Kevin

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Re: Django/Python Circular model reference

[Kevin Anthony]

Define it in one and back reference it in the other

Kevin
Please excuse brevity, sent from phone
On Jun 1, 2012 12:38 PM, "Jak"  wrote:

> The problem that I'm having is that the model "Question" is not
> defined since I am referencing it after I use it in the Answer
> model.
>
>
> Thanks
>
> Jak
>
> On Jun 1, 12:08 pm, Javier Guerra Giraldez  wrote:
> > On Fri, Jun 1, 2012 at 10:42 AM, Jak  wrote:
> > > Each answer has
> > > a question, and each question has an answer
> >
> > use OneToOneField relationships
> > (https://docs.djangoproject.com/en/1.4/ref/models/fields/#onetoonefield)
> >
> > --
> > Javier
>
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Re: Update database with model changes

[Kevin Anthony]

Use south

Kevin
Please excuse brevity, sent from phone
On Jun 7, 2012 2:05 PM, "Robert Steckroth" 
wrote:

> Hey Gang, is there a way to update the database with a syncdb or
> other command after a model has been changed? I added a field
> the the model after the syncdb.
>
>
> --
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Re: cookie based sessions or no?

[Kevin Anthony]

If you want to see an example, I have a Django app that sends json to both
an andriod app and a desktop app written in C

Django App: http://github.com/KevinAnthony/rchip_website

Desktop App: http://github.com/KevinAnthony/rchip

Android App: http://github.com/KevinAnthony/rchip_android


On Jun 13, 2012 1:30 PM, "Kurtis Mullins"  wrote:

> I wouldn't authenticate on every request. That seems like a lot
> of unnecessary work. Just authenticate once and use Cookies/Authentication
> Tokens to sustain the session. It's already built in so it's pretty easy to
> do. They even have a code snippet that shows how to use a special HTTP
> Header to keep this authenticated session going without relying on dumping
> the {% csrf_token %} on every response. It's written in Javascript but I'm
> sure you could take the same approach and include it in your Desktop
> application.
>
> On Wed, Jun 13, 2012 at 1:24 PM, Mike  wrote:
>
>> I'm working on a desktop app that will communicate with a server.  I have
>> some experience with Django and with the user authentication system but I
>> haven't deployed a Django app with authentication yet.  I'm planning to use
>> django for the server side component of this desktop app and the two will
>> communicate over SSL with JSON.  Using Django, I can authenticate users and
>> hold onto the cookie on the client side for authenticating the views that
>> need it before they return their JSON.  I could also send the userid and
>> password in every GET or POST.  Which method is better?  Is either more
>> secure?  Using cookies I can take advantage of stuff built into Django such
>> as the @login_required() decorator.
>>
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Cacheing and JSON

[Kevin Anthony]

I have a JSON api exposed writen in django, in which remote devices ask if
there are any commands for the device.
 And 99% of the time, the answer is no.
I've played around with database cacheing, and the problem i've run into
is, it can take several minutes until the new command gets sent to the
device.

Does anyone have an idea of the best way of doing something like this.

The commands come in via JSON also, if that helps.

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Re: Plotting a line graph

[Kevin Anthony]

I would look into the Google graph API
https://developers.google.com/chart/

On Mon, Jul 30, 2012 at 10:47 AM, Sithembewena Lloyd Dube  wrote:

> Hi all,
>
> I need to draw a simple line graph do to the following:
> - draw a simple line from y, x = 0 going towards x++. In other words, the
> line should begin at bottom left and run diagonally towards upper right.
>
> I have tried looking at ReportLab but I do not have enough time to dig
> through the docs. What plotting solution would anyone suggest?
>
> PS: An image of what I need to do is attached. X axis is miles (or points)
> won and Y axis is items receivable for those points, so if a user has 1
> miles a green dot should appear on the line demarcating 1 miles.
>
> --
> Regards,
> Sithembewena Lloyd Dube
>
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HttpResponseNotModified returning 200 code

[Kevin Anthony]

Here is my code:

id = get_id(request)
 if id is not None:
 host = request.GET['host']
 if host!=None:
 command =
command_queue.objects.all().filter(destination_hostname=host,user__id=id)
 if not command.count():
 HttpResponseNotModified()
 retval =
JSONResponse(command.values('command','command_text'),Extra={"success":True})
 command.delete()
 return retval
return HttpResponseForbidden()

I know it's getting to the HttpResponseNotModified, but I'm still getting a
HTTP status code of 200.

Can someone point me in the correct direction?
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Re: HttpResponseNotModified returning 200 code

[Kevin Anthony]

wow, that's embarrassing.  thanks.

On Wed, Aug 22, 2012 at 4:16 PM, Alexis Roda <
alexis.roda.villalo...@gmail.com> wrote:

> Al 22/08/12 21:36, En/na Kevin Anthony ha escrit:
>
>> Here is my code:
>>
>> id = get_id(request)
>>   if id is not None:
>>   host = request.GET['host']
>>   if host!=None:
>>   command =
>> command_queue.objects.all().**filter(destination_hostname=**
>> host,user__id=id)
>>   if not command.count():
>>   HttpResponseNotModified()
>>   retval =
>> JSONResponse(command.values('**command','command_text'),**
>> Extra={"success":True})
>>   command.delete()
>>   return retval
>>  return HttpResponseForbidden()
>>
>> I know it's getting to the HttpResponseNotModified, but I'm still
>> getting a HTTP status code of 200.
>>
>> Can someone point me in the correct direction?
>>
>
> return HttpResponseNotModified()
>
>
>
> HTH
>
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Re: bar charts

[Kevin Anthony]

Google charts api

Kevin
Please excuse brevity, sent from phone
On Nov 6, 2011 11:57 PM, "kenneth gonsalves"  wrote:

> hi,
>
> what do people use to display bar charts in their sites?
> --
> regards
> Kenneth Gonsalves
>
> --
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>
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Authentication over JSON

[Kevin Anthony]

I have a small exposed json API, currently it doesn't require
authentication, but i'd like to integrate it with django's authentication.
 A quick google search came up empty, and i was wondering if anyone had
any recommendations on how to do this?

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Re: Authentication over JSON

[Kevin Anthony]

https://docs.djangoproject.com/en/1.3/topics/auth/#authentication-in-web-requests

On Sun, Jan 8, 2012 at 12:20 PM, Stodge  wrote:

> This link is giving me a Page Not Found.
>
> On Jan 7, 1:10 pm, Michael Elkins  wrote:
> > On Sat, Jan 07, 2012 at 11:52:26AM -0500, Kevin Anthony wrote:
> > >I have a small exposed json API, currently it doesn't require
> > >authentication, but i'd like to integrate it with django's
> authentication.
> > > A quick google search came up empty, and i was wondering if anyone had
> > >any recommendations on how to do this?
> >
> > I've done this before using forms and POST, but you could easily
> > put the user credentials in your json object and use
> > django.contrib.auth as described here:
> >
> > https://docs.djangoproject.com/en/1.3/topics/Aauth/#authentication-in...
>
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Re: Authentication over JSON

[Kevin Anthony]

I'm having a problem with authentication from libcurl in C.  This works
fine from my android/iPhone apps, and from the browser, but libcurl can't
authenticate.
here's how i'm doing it
in django:
authentication function:
user = authenticate(username=username, password=password)
request.session['member_id'] = user.id
typical user function:
id = request.session['member_id']
if id is not None:
Do something useful
else:
Return Error Message

in libcurl: auth function
CURL *session = curl_easy_init(); if (session) { curl_easy_setopt(session,
CURLOPT_URL, url); curl_easy_perform(session); } g_free(url);
curl_easy_cleanup(session);
generic function:
*session = curl_easy_init(); if (session) { char* url =
g_strconcat(URL,"/getremotedevice/",NULL); printf("url:%s\n",url);
curl_easy_setopt(session, CURLOPT_URL, url); curl_easy_setopt(session,
CURLOPT_WRITEFUNCTION, get_active_decives_callback);
curl_easy_perform(session); g_free(url); } curl_easy_cleanup(session);


Am i doing something wrong?

Thanks
Kevin


On Sun, Jan 8, 2012 at 12:22 PM, Kevin Anthony wrote:

>
> https://docs.djangoproject.com/en/1.3/topics/auth/#authentication-in-web-requests
>
> On Sun, Jan 8, 2012 at 12:20 PM, Stodge  wrote:
>
>> This link is giving me a Page Not Found.
>>
>> On Jan 7, 1:10 pm, Michael Elkins  wrote:
>> > On Sat, Jan 07, 2012 at 11:52:26AM -0500, Kevin Anthony wrote:
>> > >I have a small exposed json API, currently it doesn't require
>> > >authentication, but i'd like to integrate it with django's
>> authentication.
>> > > A quick google search came up empty, and i was wondering if anyone had
>> > >any recommendations on how to do this?
>> >
>> > I've done this before using forms and POST, but you could easily
>> > put the user credentials in your json object and use
>> > django.contrib.auth as described here:
>> >
>> > https://docs.djangoproject.com/en/1.3/topics/Aauth/#authentication-in.
>> ..
>>
>> --
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>>
>>
>
>
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> Kevin Anthony
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>
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Django Static Files

[Kevin Anthony]

I'm having a problem setting up my django static files,
my static files root is at:
/var/www/mysite/static/
here's my alias info
AliasMatch ^/([^/]*\.css) /var/www/mysite/static/$1

Order deny,allow
Allow from all


This is from my settings.py
STATIC_ROOT = '/var/www/mysite/static/'
STATIC_URL = '/static/'

and here is from base.html

which resolves to this on the website


except it 404's from access log
***.***.***.*** - - [24/Jun/2011:23:53:45 -0400] "GET /static/
style.css HTTP/1.1" 404 1322 "http://***.***.***.***/"; "Mozilla/5.0
(X11; Linux i686) AppleWebKit/534.30 (KHTML, like Gecko) Ubuntu/11.04
Chromium/12.0.742.91 Chrome/12.0.742.91 Safari/534.30"

I'm sure i'm missing something stupid, but i can't figure out why it
won't serve with apache
When I serve it using python manage 0.0.0.0:80 the css doesn't 404

Can someone please help me?

Thanks
Kevin Anthony

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Re: rss feed question

[Kevin Anthony]

http://www.feedparser.org/

On Sat, Jun 25, 2011 at 12:21 AM, raj  wrote:
> I was trying to follow the following guide:
> https://docs.djangoproject.com/en/dev/ref/contrib/syndication/?from=olddocs
> and I had some questions.
>
> I'm not quite sure, but it seems like this guide is showing how to
> create your own feed. How would I go about retrieving the feed instead
> of creating it?
> I want to implement a feed reader on my site that obtains rss feeds
> from other websites.
> Thank you
>
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Re: Django Static Files

[Kevin Anthony]

I sort of knew that
Can someone post their scrubed conf file?
On Jun 25, 2011 12:54 AM, "Andrew Brookins"  wrote:
> Sorry: posting from phones... Not always awesome.
>
> If the development server serves your static files, but Apache does not,
then the problem is likely somewhere in your Apache conf or server config.
>
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Json and django.contrib.auth.views.login

[Kevin Anthony]

i'm trying to use JSON on a website that also has a HTML frontend, but
when i enable this line in urls.py
url(r'^json/sendcommand/','rchip.views.json_send_command'),

i get this message
Caught ViewDoesNotExist while rendering: Tried json_command in module
rchip.views. Error was: 'module' object has no attribute
'json_command'

this is my login URL:
url(r'^accounts/login/$','django.contrib.auth.views.login',
{'template_name': 'main/login.html', }),

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Re: Json and django.contrib.auth.views.login

[Kevin Anthony]

No, it's there

def 
json_send_command(request,command_in=None,command_text_in=None,source_in=None,method_in=None):
and it works, if i navigate to
mysite.com/json/sendcommand/
i get the correct message telling me i didn't supply a command

On Tue, Jul 19, 2011 at 6:29 PM, Andre Terra  wrote:
> Kevin,
>
> Please open your views.py module located inside the rchip module and
> you will see there is no view named json_send_command.
>
> Please refer to that app's documentation to find more about the
> correct setup for your urls.
>
> Cheers,
> AT
>
> On 7/19/11, Kevin Anthony  wrote:
>> i'm trying to use JSON on a website that also has a HTML frontend, but
>> when i enable this line in urls.py
>> url(r'^json/sendcommand/','rchip.views.json_send_command'),
>>
>> i get this message
>> Caught ViewDoesNotExist while rendering: Tried json_command in module
>> rchip.views. Error was: 'module' object has no attribute
>> 'json_command'
>>
>> this is my login URL:
>> url(r'^accounts/login/$','django.contrib.auth.views.login',
>> {'template_name': 'main/login.html', }),
>>
>> --
>> Thanks
>> Kevin Anthony
>> www.NoSideRacing.com
>>
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>>
>
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Re: import django models without runing the server

[Kevin Anthony]

I found the best way to do this is
python manage.py < script.py
On Jul 21, 2011 8:00 PM, "Gelonida N"  wrote:
> On 07/18/2011 04:33 PM, bruno desthuilliers wrote:
>> On Jul 18, 3:33 pm, Alexander Crössmann
>>  wrote:
>>> Hi Malcom,
>>>
>>> I am not sure the management commands are what I want
>>
>> Strange enough, it seems that everyone starts by saying this and ends
>> up writing custom management commands ;)
>>
>
>
> I wrote quite some scripts meanwhile, which just set
> DJANGO_SETTINGS_MODULE and use then the models.
>
> I think if a django model is only a tiny part of a bigger script, then
> management commands are not really advantageous over management commands.
>
> Another issue, that I had is trying to use django under windows with
py2exe.
>
> Management commands are no more found, as django would require the
> python source code in order to find existing management commands.
>
> Perhaps there is an easy work around, but I am not aware of one.
>
>
>
>
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Django, Json and Android

[Kevin Anthony]

i'm trying to interface a django json page with an android application.
it seems most json applications written for android use
www.somepage.com/json.php?this=that&something=anotherthing

But that doesn't work with django,

Has anyone interfaced Django and Android? and if they did, is there
any reading material on it?

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Deleting a model object then returning it

[Kevin Anthony]

Accoding to the documentation all i need to do is

object = someobject.objects.all().filter(somefield=somevalue)
print object
object.delete()
print object


and theoretically, object should be unchanged, since according to the
documentation:
Issues a SQL DELETE for the object. This only deletes the object in the
database; the Python instance will still be around, and will still have data
in its fields.

but when i run this command
i get
[]
[]

so the python instance looses it's data. Is there another way to delete the
data from SQL while still being about to use it in Python?
because after i delete it, i need to serialize the data to JSON

Thanks
Kevin Anthony

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