Having ERROR running Django project !!!

2018-03-26 Thread Jamaldin Pro
Hello
I was creating a Djnago project and when I finish it, it was working 
perfectly but when I start adding ("name"/"text"/"information") to models 
from admin page, It stops working I mean after adding I can't open my home 
page. *If I will try to open it, it auto downloads unknown file*.

*I NEED HELP AS SOON AS POSSIBLE* !!!

Thank u.

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Re: Having ERROR running Django project !!!

2018-03-28 Thread Jamaldin Pro
I see no logs error and When I run it from chrome this error happens but 
when I try to use it from Internet e.version~9 it works normally, I can 
deal with it but also when I deploy to pythonanywhere there is error too. 
Yes I run it "python manage.py runserver"

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Re: Having ERROR running Django project !!!

2018-03-28 Thread Jamaldin Pro

>
> It is unknown and When I try to open it, it shows programs to open with 
> I'm choosing chrome and my site opens without css/static/js I think that is 
> html file 
>

DEBUG = True

Can you tell me what files you need because I have a lot of 
files.setting.py? / wsgi.py? / urls.py? / template HTMLs?

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Re: Having ERROR running Django project !!!

2018-03-28 Thread Jamaldin Pro
https://github.com/XJoma/mk-center1

django version 1.11.5
now you have my project. So fix my problem plz !!!
It is my first time uploading so I don't know how to not show my password

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Re: Having ERROR running Django project !!!

2018-03-29 Thread Jamaldin Pro
Can you help?

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Re: Having ERROR running Django project !!!

2018-03-29 Thread Jamaldin Pro
Thank you!

On Thursday, March 29, 2018 at 8:07:07 PM UTC+6, Jani Tiainen wrote:
>
> Yes. I managed to "fix" your code.,
>
> https://github.com/XJoma/mk-center1/blob/master/home/views.py#L47
>
> Firstm never, ever pass locals() anywhere it's best way to introduce a lot 
> of bugs. Also you have quite a good record of from foo import * which is as 
> bad as well.
>
> But your problem is that fourth parameter to render() is actually 
> content_type. Now you're passing total garbage for content_type which 
> causes browser to think that incoming data is something it can't handle and 
> downloads it.
>
> There is no parameter that would fit anything what could take another dict 
> besides context which you're already passing in.
>
>
> On Thu, Mar 29, 2018 at 3:03 PM, Jamaldin Pro  > wrote:
>
>> Can you help? 
>>
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>
>
>
> -- 
> Jani Tiainen
>
> - Well planned is half done, and a half done has been sufficient before...
>

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Re: Filtering Queryset by Foreign Key Properties

2018-03-30 Thread Jamaldin Pro

>
> class ProductType(models.Model):
> class Meta:
> verbose_name_plural = 'тип'
> verbose_name = 'типы'
>
> image = models.ImageField(upload_to='products_type_images/')
> name = models.CharField(max_length=20, blank=True, null=True, 
> default=None)
> is_active = models.BooleanField(default=True)
>
> def __str__(self):
> return "%s" % self.name
>
>
> class Product(models.Model):
> class Meta:
> verbose_name_plural = 'запчасть'
> verbose_name = 'запчасти'
>
> name = models.CharField(max_length=20)
> price = models.DecimalField(max_digits=10, decimal_places=2, default=0)
> short_description = models.TextField(blank=True, null=True, default=None, 
> max_length=100)
> description = models.TextField(blank=True, null=True, default=None)
> is_active = models.BooleanField(default=True)
> type = models.ForeignKey(ProductType, blank=True, null=True, default=None)
>
> def __str__(self):
> return "(%s, %s)" % (self.id, self.name)
>
>
> class ProductImage(models.Model):
> class Meta:
> verbose_name_plural = 'фотография_запчасти'
> verbose_name = 'фотографии_запчасти'
>
> product = models.ForeignKey(Product, blank=True, null=True, default=None)
> image = models.ImageField(upload_to='products_images/')
> is_main = models.BooleanField(default=False)
> is_active = models.BooleanField(default=True)
> created = models.DateTimeField(default=timezone.now)
>
> def category(request, category_name):
# products_images_list = get_object_or_404(Product, id=category_name)
query = request.GET.get("q")
if query:

products_images_list = ProductImage.objects.filter(
product__type__name__contains=query) 


But in my template this is not working I want to filter my product's types. 
Can you help my? Django 1.11

Thank you.
 

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Filtering Queryset by Foreign Key Properties

2018-03-31 Thread Jamaldin Pro

>
> class ProductType(models.Model):
>
> image = models.ImageField(upload_to='products_type_images/')
> name = models.CharField(max_length=20, blank=True, null=True, 
> default=None)
> is_active = models.BooleanField(default=True)
>
> def __str__(self):
> return "%s" % self.name
>
>
> class Product(models.Model):
>
> name = models.CharField(max_length=20)
> price = models.DecimalField(max_digits=10, decimal_places=2, default=0)
> short_description = models.TextField(blank=True, null=True, default=None, 
> max_length=100)
> description = models.TextField(blank=True, null=True, default=None)
> is_active = models.BooleanField(default=True)
> type = models.ForeignKey(ProductType, blank=True, null=True, default=None)
>
> def __str__(self):
> return "(%s, %s)" % (self.id, self.name)
>
>
> class ProductImage(models.Model):
>
> product = models.ForeignKey(Product, blank=True, null=True, default=None)
> image = models.ImageField(upload_to='products_images/')
> is_main = models.BooleanField(default=False)
> is_active = models.BooleanField(default=True)
> created = models.DateTimeField(default=timezone.now)
>
>
 

def category(request):
query = request.GET.get("q")
if query:

  products_images_list = ProductImage.objects.filter(
product__type__name__contains=query) 




But in my template this is not working I want to filter my product's types. 
Can you help my? Django 1.11

Thank you.
 

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Re: Filtering Queryset by Foreign Key Properties

2018-03-31 Thread Jamaldin Pro
Can anyone help me?

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Infinite scrolling, Ajax, Phone or PC?

2018-04-02 Thread Jamaldin Pro
 Hello.

   How can I make Infinite scrolling html? example: 
https://www.megacom.kg/hype/ru.html#instruction
   How can I go from first url to another without reloading the website?
   How can I know if the user is entering my website from phone or pc? If 
user is entering from phone it should show the Whatsapp button and If user 
is entering from PC it should hide it.

" I can't find any place to ask this thing, and this place might be the 
wrong place. SORRY if it is like that. If you can answer even one of this 
answer it plz "

Thank you ♪

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