Re: Arrayfield constraint issue in 4.1

[Manjusha]

I think default should be assigned like this

 default=[ ] or
default= list()


But I'm junior so may I don't know well

On Mon, 12 Dec 2022, 03:13 James Gillard,  wrote:

> The callable list is indeed assigned as the default for the ArrayField, as
> documented here:
> https://docs.djangoproject.com/en/4.1/ref/contrib/postgres/fields/#django.contrib.postgres.fields.ArrayField
>
> The original issue has already had a patch merged, which will be released
> in 4.1.5, see the fix here:
> https://docs.djangoproject.com/en/dev/releases/4.1.5/
>
> On Sunday, 11 December 2022 at 18:02:24 UTC manjushak...@gmail.com wrote:
>
>> Hello Sir, I need to understand the form.py  file because , what  is the
>> only list you have assigned as default in arrayfield, is it the method
>> list() ?
>>
>>
>> On Sat, Dec 10, 2022 at 10:00 PM James Gillard 
>> wrote:
>>
>>> Thanks for the feedback. I opened a ticket and it was indeed confirmed
>>> as a bug: https://code.djangoproject.com/ticket/34205
>>>
>>> On Thursday, 8 December 2022 at 15:04:40 UTC Ryan Nowakowski wrote:
>>>
 Might be a bug. Check the release notes for the post 4.0.8 versions to
 see if anything related changed. File a bug with the simplest example code
 that demonstrates the issue.


 On December 8, 2022 6:37:52 AM CST, James Gillard <
 ja...@journeetrips.com> wrote:
>
> I can't yet work out whether this is a Django bug or how I'm using
> model constraints... Upgraded from 4.0.8 to 4.1.4 and have hit this issue
> when saving this model in the admin. I'd read in the release notes that
> these constraints would be validated on model save, and that's the code
> that's leading to this exception. If it's not something I've done, it 
> seems
> ArrayField isn't working with this new validation of my condition. The 
> same
> happens for Q(phone_numbers__len__gte=0), and the error disappears if I
> comment out this condition. It seems the generated code might be wrong, as
> I see 12 "%s" and only 11 elements in params. All it's trying to do is
> ensure that an empty list isn't considered unique.
>
> Here's the failing model:
>
> phone_numbers = ArrayField(models.CharField(max_length=200),
> default=list, blank=True)
>
> class Meta:
> constraints = [
> models.UniqueConstraint(
>fields=['phone_numbers'],
>condition=~Q(phone_numbers__len=0),
>name='unique_email_phones',
> ),
> ]
> )
>
> [image: Screenshot 2022-12-08 at 12.30.35.png]
>
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>>> .
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Re: Arrayfield constraint issue in 4.1

[James Gillard]

I agree it looks odd, but the docs I linked say that list is fine, and
here's example from a test inside Django itself:
https://github.com/django/django/blob/cb791a2540c289390b68a3ea9c6a79476890bab2/tests/postgres_tests/models.py#L51

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On Mon, 12 Dec 2022 at 14:45, Manjusha  wrote:

> I think default should be assigned like this
>
>  default=[ ] or
> default= list()
>
>
> But I'm junior so may I don't know well
>
> On Mon, 12 Dec 2022, 03:13 James Gillard,  wrote:
>
>> The callable list is indeed assigned as the default for the ArrayField,
>> as documented here:
>> https://docs.djangoproject.com/en/4.1/ref/contrib/postgres/fields/#django.contrib.postgres.fields.ArrayField
>>
>> The original issue has already had a patch merged, which will be released
>> in 4.1.5, see the fix here:
>> https://docs.djangoproject.com/en/dev/releases/4.1.5/
>>
>> On Sunday, 11 December 2022 at 18:02:24 UTC manjushak...@gmail.com wrote:
>>
>>> Hello Sir, I need to understand the form.py  file because , what  is the
>>> only list you have assigned as default in arrayfield, is it the method
>>> list() ?
>>>
>>>
>>> On Sat, Dec 10, 2022 at 10:00 PM James Gillard 
>>> wrote:
>>>
 Thanks for the feedback. I opened a ticket and it was indeed confirmed
 as a bug: https://code.djangoproject.com/ticket/34205

 On Thursday, 8 December 2022 at 15:04:40 UTC Ryan Nowakowski wrote:

> Might be a bug. Check the release notes for the post 4.0.8 versions to
> see if anything related changed. File a bug with the simplest example code
> that demonstrates the issue.
>
>
> On December 8, 2022 6:37:52 AM CST, James Gillard <
> ja...@journeetrips.com> wrote:
>>
>> I can't yet work out whether this is a Django bug or how I'm using
>> model constraints... Upgraded from 4.0.8 to 4.1.4 and have hit this issue
>> when saving this model in the admin. I'd read in the release notes that
>> these constraints would be validated on model save, and that's the code
>> that's leading to this exception. If it's not something I've done, it 
>> seems
>> ArrayField isn't working with this new validation of my condition. The 
>> same
>> happens for Q(phone_numbers__len__gte=0), and the error disappears if I
>> comment out this condition. It seems the generated code might be wrong, 
>> as
>> I see 12 "%s" and only 11 elements in params. All it's trying to do is
>> ensure that an empty list isn't considered unique.
>>
>> Here's the failing model:
>>
>> phone_numbers = ArrayField(models.CharField(max_length=200),
>> default=list, blank=True)
>>
>> class Meta:
>> constraints = [
>> models.UniqueConstraint(
>>fields=['phone_numbers'],
>>condition=~Q(phone_numbers__len=0),
>>name='unique_email_phones',
>> ),
>> ]
>> )
>>
>> [image: Screenshot 2022-12-08 at 12.30.35.png]
>>
>> --
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 To view this discussion on the web visit
 https://groups.google.com/d/msgid/django-users/4a8a0941-dd65-4c22-bf16-4e11181794a0n%40googlegroups.com
 
 .

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>> .
>>
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Re: Permission for admin to add patient

[Manjusha]

Hi, need to register the model.py file in admin.py file and then make 
migrations as like mention in following documentation.
https://docs.djangoproject.com/en/4.1/intro/tutorial02/

On Monday, December 12, 2022 at 4:49:26 AM UTC+5:30 curtis...@gmail.com 
wrote:

> Hello to all. Please, I would like to know in Django, how to allow an 
> administrator to add a patient, but not a simple connected user? the 
> following pics are my models.py, view.py and my template.py.
>

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Re: Permission for admin to add patient

[Manjusha]

I'm junior may it will work!!

On Tuesday, December 13, 2022 at 12:31:17 PM UTC+5:30 Manjusha wrote:

> Hi, need to register the model.py file in admin.py file and then make 
> migrations as like mention in following documentation.
> https://docs.djangoproject.com/en/4.1/intro/tutorial02/
>
> On Monday, December 12, 2022 at 4:49:26 AM UTC+5:30 curtis...@gmail.com 
> wrote:
>
>> Hello to all. Please, I would like to know in Django, how to allow an 
>> administrator to add a patient, but not a simple connected user? the 
>> following pics are my models.py, view.py and my template.py.
>>
>

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Re: Permission for admin to add patient

[rahul sharma]

connect with me in zoom

On Tue, Dec 13, 2022 at 12:34 PM Manjusha 
wrote:

> I'm junior may it will work!!
>
> On Tuesday, December 13, 2022 at 12:31:17 PM UTC+5:30 Manjusha wrote:
>
>> Hi, need to register the model.py file in admin.py file and then make
>> migrations as like mention in following documentation.
>> https://docs.djangoproject.com/en/4.1/intro/tutorial02/
>>
>> On Monday, December 12, 2022 at 4:49:26 AM UTC+5:30 curtis...@gmail.com
>> wrote:
>>
>>> Hello to all. Please, I would like to know in Django, how to allow an
>>> administrator to add a patient, but not a simple connected user? the
>>> following pics are my models.py, view.py and my template.py.
>>>
>> --
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> 
> .
>

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Re: Permission for admin to add patient

[André Hangalo]

from .models import ModelName

admin.site.register(ModelName)

On Tue, 13/12/2022 at 08:04 Manjusha  wrote:

> I'm junior may it will work!!
>
> On Tuesday, December 13, 2022 at 12:31:17 PM UTC+5:30 Manjusha wrote:
>
>> Hi, need to register the model.py file in admin.py file and then make
>> migrations as like mention in following documentation.
>> https://docs.djangoproject.com/en/4.1/intro/tutorial02/
>>
>> On Monday, December 12, 2022 at 4:49:26 AM UTC+5:30 curtis...@gmail.com
>> wrote:
>>
>>> Hello to all. Please, I would like to know in Django, how to allow an
>>> administrator to add a patient, but not a simple connected user? the
>>> following pics are my models.py, view.py and my template.py.
>>>
>> --
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> 
> .
>
-- 
RICK DEU

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